Essential Statistics for the Behavioral Sciences
2nd Edition
ISBN: 9781506386300
Author: Gregory J. Privitera
Publisher: SAGE Publications, Inc
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Chapter 10, Problem 19CAP
(a)
To determine
To test whether or not her tutoring is effective at a
(b)
To determine
To compute effect size using estimated Cohen’s d .
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According to the February 2008 Federal Trade Commission report on consumer fraud and identity theft, 23% of all complaints in 2007 were for identity theft. In that year, Alaska had 321 complaints of identity theft out of 1,432 consumer complaints ("Consumer fraud and," 2008). Does this data provide enough evidence to show that Alaska had a lower proportion of identity theft than 23%? Test at the 5% level.
viii) Comparing p-value and α value, which is the correct decision to make for this hypothesis test?
A. Reject H
B. Fail to reject Ho
C. Accept Ho
D. Accept HA
Enter letter corresponding to correct answer.
(ix) Select the statement that most correctly interprets the result of this test:
A. The result is statistically significant at .05 level of significance. Evidence supports the claim that the proportion of complaints due to identity theft in Alaska is less than 23%.
B. The result is statistically significant at .05 level of significance. There is not…
In the previous year, 40% of women over the age of fifty had regularly scheduled mammograms. Following last year's test, a campaign was initiated to encourage women to be tested regularly. This year, a cancer research group surveys a random sample of 450 women, and 195 respond affirmatively. With a 5% significance level, test to see if the campaign was effective.
What is the null hypothesis?
options:
H0: μ ≤ 0.4
H0: μ ≥ 0.4
H0: p ≠ 0.4
H0: p ≥ 0.4
H0: p ≤ 0.4
H0: μ ≠ 0.4
None of these.
Back in April and May of 1985, the Gallup organization conducted a poll to estimate the percentage of Americans who approved of how President Reagan was handling his job. At the 5% significance level, do the data suggest that the percentage of those who approved of Reagan increased from April to May in 1985? Population 1: April p = 795/1528 = 0.5203 Population 2: May p = 840/1528 = 0.5497
Show all your steps, setting up your null and alternative hypothesis.
Chapter 10 Solutions
Essential Statistics for the Behavioral Sciences
Ch. 10 - Prob. 1FPCh. 10 - Prob. 2FPCh. 10 - Prob. 3FPCh. 10 - Prob. 4FPCh. 10 - Prob. 5FPCh. 10 - Prob. 6FPCh. 10 - Prob. 7FPCh. 10 - Prob. 8FPCh. 10 - Prob. 9FPCh. 10 - Prob. 10FP
Ch. 10 - Prob. 11FPCh. 10 - Prob. 12FPCh. 10 - Prob. 13CAPCh. 10 - Prob. 14CAPCh. 10 - Prob. 15CAPCh. 10 - Prob. 16CAPCh. 10 - Prob. 17CAPCh. 10 - Prob. 18CAPCh. 10 - Prob. 19CAPCh. 10 - Prob. 20CAPCh. 10 - Prob. 21CAPCh. 10 - Prob. 22CAPCh. 10 - Prob. 23CAPCh. 10 - Prob. 24CAPCh. 10 - Prob. 25CAPCh. 10 - Prob. 26CAPCh. 10 - Prob. 27CAPCh. 10 - Prob. 28CAPCh. 10 - Prob. 29PRCh. 10 - Prob. 30PRCh. 10 - Prob. 31PRCh. 10 - Prob. 32PRCh. 10 - Prob. 33PRCh. 10 - Prob. 34PR
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