From the given intermediates, the intermediate formed when 1-butene undergoes radical bromination has to be identified. Concept introduction: Stability of Radicals: Radicals are highly unstable due to its unpaired valence electron of an atom. The increasing order of radical stability is given below Benzylic > allylic > tertiary > secondary > primary > methyl Bond strength is depends on the formation of the radical, if the radical is involving in resonance which weakest bond strength. Radical Bromination: 2-methyl propane undergoes radical bromination which yields the 2-bromo-2-methylpropane.because bromination will occur where the tertiary radical is present. (Bromination reactions are more selective reaction). Bromination will occur on tertiary radical than the secondary than primary radical, tertiary radical is more stable radical than the other radicals.

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Answer 1

Question

Chapter 10, Problem 57IP

Interpretation Introduction

Interpretation:

From the given intermediates, the intermediate formed when 1-butene undergoes radical bromination has to be identified.

Concept introduction:

Stability of Radicals: Radicals are highly unstable due to its unpaired valence electron of an atom.

The increasing order of radical stability is given below

Benzylic > allylic > tertiary > secondary > primary > methyl

Bond strength is depends on the formation of the radical, if the radical is involving in resonance which weakest bond strength.

Radical Bromination:

2-methyl propane undergoes radical bromination which yields the 2-bromo-2-methylpropane.because bromination will occur where the tertiary radical is present. (Bromination reactions are more selective reaction).

Bromination will occur on tertiary radical than the secondary than primary radical, tertiary radical is more stable radical than the other radicals.

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Answer 2

Question

Chapter 10, Problem 57IP

Interpretation Introduction

Interpretation:

From the given intermediates, the intermediate formed when 1-butene undergoes radical bromination has to be identified.

Concept introduction:

Stability of Radicals: Radicals are highly unstable due to its unpaired valence electron of an atom.

The increasing order of radical stability is given below

Benzylic > allylic > tertiary > secondary > primary > methyl

Bond strength is depends on the formation of the radical, if the radical is involving in resonance which weakest bond strength.

Radical Bromination:

2-methyl propane undergoes radical bromination which yields the 2-bromo-2-methylpropane.because bromination will occur where the tertiary radical is present. (Bromination reactions are more selective reaction).

Bromination will occur on tertiary radical than the secondary than primary radical, tertiary radical is more stable radical than the other radicals.

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Answer 3

Question

Chapter 10, Problem 57IP

Interpretation Introduction

Interpretation:

From the given intermediates, the intermediate formed when 1-butene undergoes radical bromination has to be identified.

Concept introduction:

Stability of Radicals: Radicals are highly unstable due to its unpaired valence electron of an atom.

The increasing order of radical stability is given below

Benzylic > allylic > tertiary > secondary > primary > methyl

Bond strength is depends on the formation of the radical, if the radical is involving in resonance which weakest bond strength.

Radical Bromination:

2-methyl propane undergoes radical bromination which yields the 2-bromo-2-methylpropane.because bromination will occur where the tertiary radical is present. (Bromination reactions are more selective reaction).

Bromination will occur on tertiary radical than the secondary than primary radical, tertiary radical is more stable radical than the other radicals.

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Answer 4

Question

Chapter 10, Problem 57IP

Interpretation Introduction

Interpretation:

From the given intermediates, the intermediate formed when 1-butene undergoes radical bromination has to be identified.

Concept introduction:

Stability of Radicals: Radicals are highly unstable due to its unpaired valence electron of an atom.

The increasing order of radical stability is given below

Benzylic > allylic > tertiary > secondary > primary > methyl

Bond strength is depends on the formation of the radical, if the radical is involving in resonance which weakest bond strength.

Radical Bromination:

2-methyl propane undergoes radical bromination which yields the 2-bromo-2-methylpropane.because bromination will occur where the tertiary radical is present. (Bromination reactions are more selective reaction).

Bromination will occur on tertiary radical than the secondary than primary radical, tertiary radical is more stable radical than the other radicals.

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Answer 5

Chapter 10, Problem 57IP

Interpretation Introduction

Interpretation:

From the given intermediates, the intermediate formed when 1-butene undergoes radical bromination has to be identified.

Concept introduction:

Stability of Radicals: Radicals are highly unstable due to its unpaired valence electron of an atom.

The increasing order of radical stability is given below

Benzylic > allylic > tertiary > secondary > primary > methyl

Bond strength is depends on the formation of the radical, if the radical is involving in resonance which weakest bond strength.

Radical Bromination:

2-methyl propane undergoes radical bromination which yields the 2-bromo-2-methylpropane.because bromination will occur where the tertiary radical is present. (Bromination reactions are more selective reaction).

Bromination will occur on tertiary radical than the secondary than primary radical, tertiary radical is more stable radical than the other radicals.

Answer 6

Chapter 10, Problem 57IP

Interpretation Introduction

Interpretation:

From the given intermediates, the intermediate formed when 1-butene undergoes radical bromination has to be identified.

Concept introduction:

Stability of Radicals: Radicals are highly unstable due to its unpaired valence electron of an atom.

The increasing order of radical stability is given below

Benzylic > allylic > tertiary > secondary > primary > methyl

Bond strength is depends on the formation of the radical, if the radical is involving in resonance which weakest bond strength.

Radical Bromination:

2-methyl propane undergoes radical bromination which yields the 2-bromo-2-methylpropane.because bromination will occur where the tertiary radical is present. (Bromination reactions are more selective reaction).

Bromination will occur on tertiary radical than the secondary than primary radical, tertiary radical is more stable radical than the other radicals.

Answer 7

Chapter 10, Problem 57IP

Interpretation Introduction

Interpretation:

From the given intermediates, the intermediate formed when 1-butene undergoes radical bromination has to be identified.

Concept introduction:

Stability of Radicals: Radicals are highly unstable due to its unpaired valence electron of an atom.

The increasing order of radical stability is given below

Benzylic > allylic > tertiary > secondary > primary > methyl

Bond strength is depends on the formation of the radical, if the radical is involving in resonance which weakest bond strength.

Radical Bromination:

2-methyl propane undergoes radical bromination which yields the 2-bromo-2-methylpropane.because bromination will occur where the tertiary radical is present. (Bromination reactions are more selective reaction).

Bromination will occur on tertiary radical than the secondary than primary radical, tertiary radical is more stable radical than the other radicals.

Answer 8

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Answer 9

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Answer 10

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Answer 11

Ch. 10.1 - Prob. 1CC Ch. 10.1 - Prob. 1LTS Ch. 10.1 - Prob. 2PTS Ch. 10.1 - Prob. 3PTS Ch. 10.1 - Prob. 4ATS Ch. 10.1 - Prob. 2LTS Ch. 10.1 - Prob. 5PTS Ch. 10.1 - Prob. 6PTS Ch. 10.1 - Prob. 7ATS Ch. 10.2 - Prob. 3LTS

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Chapter 10 Solutions