Fundamentals of Biostatistics
Fundamentals of Biostatistics
8th Edition
ISBN: 9781305268920
Author: Bernard Rosner
Publisher: Cengage Learning
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Chapter 10, Problem 5P

Answer Problem 10.4 if compliance is as given in Example 10.37.

Consider the Physicians’ Health Study data presented in Example 10.37 (p. 411).

10.4 Suppose 11,000 men are actually enrolled in each treatment group. What would be the power of such a study if a two-sided test with α = .05 were used and compliance is perfect?

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Given two estimators X1 and X2 for a population mean, E[X1] = 6, V[X1] = 4, and V[X2] = 5. If the true value of the population mean is 5, which of the following is(are) TRUE? A. X1 is an unbiased estimator.B. X2 is less precise than X1.
Question 17: A well-known brokerage firm executive claimed that 90% of investors are currently confident of meeting their investment goals. An XYZ Investor Optimism Survey, conducted over a two week period, found that in a sample of 100 people, 81% of them said they are confident of meeting their goals.Test the claim that the proportion of people who are confident is smaller than 90% at the 0.05 significance level.The null and alternative hypothesis would be:   H0:p≤0.9H0:p≤0.9H1:p>0.9H1:p>0.9 H0:μ≤0.9H0:μ≤0.9H1:μ>0.9H1:μ>0.9 H0:μ≥0.9H0:μ≥0.9H1:μ<0.9H1:μ<0.9 H0:μ=0.9H0:μ=0.9H1:μ≠0.9H1:μ≠0.9 H0:p=0.9H0:p=0.9H1:p≠0.9H1:p≠0.9 H0:p≥0.9H0:p≥0.9H1:p<0.9H1:p<0.9 The test is:   two-tailed right-tailed left-tailed The test statistic is:  (to 3 decimals)The p-value is:  (to 4 decimals)Based on this we: Fail to reject the null hypothesis Reject the null hypothesis
Question 9 A well-known brokerage firm executive claimed that 60% of investors are currently confident of meeting their investment goals. An XYZ Investor Optimism Survey, conducted over a two week period, found that in a sample of 100 people, 61% of them said they are confident of meeting their goals.Test the claim that the proportion of people who are confident is larger than 60% at the 0.10 significance level.The null and alternative hypothesis would be:   H0:μ≤0.6H0:μ≤0.6H1:μ>0.6H1:μ>0.6 H0:p≥0.6H0:p≥0.6H1:p<0.6H1:p<0.6 H0:p≤0.6H0:p≤0.6H1:p>0.6H1:p>0.6 H0:μ≥0.6H0:μ≥0.6H1:μ<0.6H1:μ<0.6 H0:μ=0.6H0:μ=0.6H1:μ≠0.6H1:μ≠0.6 H0:p=0.6H0:p=0.6H1:p≠0.6H1:p≠0.6 The test is:   left-tailed right-tailed two-tailed The test statistic is:  (to 2 decimals)The p-value is:  (to 4 decimals)Based on this we: Fail to reject the null hypothesis Reject the null hypothesis
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