Chapter 10.1, Problem 17SSC

To determine

Work done on the car and force-displacement graph.

Answer to Problem 17SSC

Work done on the car is $W=\text{1}\text{.275}\text{kJ}$

Explanation of Solution

Given:

Displacement is $d=15\text{m}$

Force is decreased at constant rate from 210 N to 40 N.

Formula Used:

Work done is given by area under the force-displacement graph.

Area of triangle is: $\frac{1}{2}\text{base×height}$

Calculation:

From the given condition the force-displacement graph will be,

  

As, work done is given by area under the force-displacement graph.

So, from the above graph, work done is

  $\begin{array}{l}W=\frac{1}{2}d\left(F_1-F_2\right)\\ =\frac{1}{2}\times 15\times \left(210-40\right)\\ =1275\text{J}\\ \text{=1}\text{.275}\text{kJ}\end{array}$