Chapter 10.1, Problem 30E

To determine

To compare the graph.

Answer to Problem 30E

  $f(x):q(x)=\sqrt{x}:\sqrt{x}+8$

Explanation of Solution

Given information: $f\left(x\right)=\sqrt{x}$ and $q\left(x\right)=\sqrt{x}+8$

Formula Used: Ratio Property

Calculation:

Graph of $f\left(x\right)=\sqrt{x}$ and $q\left(x\right)=\sqrt{x}+8$

  $\begin{array}{cccc}x& 0& 1& 2\\ f(x)& 0& 1& 1.41\\ q(x)& 0& 9& 9.41\end{array}$

  

Now compare the graph of $q(x)$ to the graph of $f(x)$

  $\frac{f(x)}{q(x)}=\frac{\sqrt{x}}{\sqrt{x}+8}$

So,

  $f(x):q(x)=\sqrt{x}:\sqrt{x}+8$