   Chapter 10.1, Problem 56E

Chapter
Section
Textbook Problem

# Classifying the Graph of an Equation In Exercises 51–58, classify the graph of the equation as a circle, a parabola, an ellipse, or a hyperbola. 2 x ( x − y ) = y ( 3 − y − 2 x )

To determine

Whether the graph of the equation 2x(xy)=y(3y2x) is a circle, a parabola, an ellipse or a hyperbola.

Explanation

Given:

The provided equation is:

2x(xy)=y(3y2x).

Formula used:

The standard equation of an ellipse centered at (h,k) with major and minor axes a and b is:

(xh)2a2+(yk)2b2=1

Calculation:

Consider the provided equation:

2x(xy)=y(3y2x)

Expand the equation to get:

2x22xy=3yy22xy2x2+y23y=0

Now, rewrite the equation by completing the squares as:

2x2

### Still sussing out bartleby?

Check out a sample textbook solution.

See a sample solution

#### The Solution to Your Study Problems

Bartleby provides explanations to thousands of textbook problems written by our experts, many with advanced degrees!

Get Started

#### Prove the second law of exponents [see (15)].

Single Variable Calculus: Early Transcendentals

#### Evaluate the limit, if it exists. limx4x2+3xx2x12

Single Variable Calculus: Early Transcendentals, Volume I

#### If 13f(x)dx=10 and 13g(x)dx=6, then 13(2f(x)3g(x))dx= a) 2 b) 4 c) 18 d) 38

Study Guide for Stewart's Single Variable Calculus: Early Transcendentals, 8th 