Chapter 10.2, Problem 1PSA

To determine

Which chord is closer to the centre ?

Answer to Problem 1PSA

Both chords are at same distance from centre.

Explanation of Solution

Given information : $\text{In a circle, chord }\overline{\text{AB}}\text{ is 325 cm long and chord}\overline{\text{CD}}\text{is 3}\frac{\text{1}}{\text{4}}\text{m long}\text{.}$

  $\begin{array}{l}\text{325 cm = 3}\text{.25 cm}\text{. Length of }\overline{\text{AB}}\text{ chord = 3}\text{.25 m}\text{.}\\ \text{And length of chord }\overline{\text{CD}}\text{is 3}\frac{\text{1}}{\text{4}}\text{m = 3}\text{.25 m}\\ \text{Length of chord }\overline{\text{AB}}\text{ = length of chord }\overline{\text{CD}}.\\ \text{Both chords are at same distance from the centre}\text{.}\end{array}$