Chapter 10.2, Problem 4PSA

To determine

To prove: that the line $AB,BC\text{ and }CA$ are equidistant from the center.

Answer to Problem 4PSA

  $AB,BC\text{ and }CA$ are equidistant from the center.

Explanation of Solution

Given:

  

Concept used:

Equilateral triangle has all side all angle equal:

  $AB=AC=BC$ .

chord of a circle is congruent, then there are equidistant from the center of the circle.

Calculation:

According to the given:

Equilateral $\Delta ABC$ is inscribed in circle $Q$ .

By the definition of the equilateral.

  $AB=AC=BC$ .

If chord of a circle is congruent, then there are equidistant from the center of the circle.

Hence, $AB,BC\text{ and }CA$ are equidistant from the center.