EBK PRECALCULUS W/LIMITS
EBK PRECALCULUS W/LIMITS
4th Edition
ISBN: 9781337516853
Author: Larson
Publisher: CENGAGE CO
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Concept explainers

Maximization
Have you ever seen a bridge in the shape of a parabola? Where is its maximum on the bridge? The maximum of that bridge is the highest point on that bridge. The process of finding the maximum of the bridge here is called the maximization.
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Chapter 10.2, Problem 84E

  (a)

To determine

To graph: The equation of parabola x2=py for p=1,p=2,p=3 and p=4 .

  (a)

Expert Solution
Check Mark

Explanation of Solution

Given information:

The standard form of equation of parabola x2=py .

Graph:

Consider the standard form of equation of parabola x2=py .

For p=1 , the equation is x2=y .

For p=2 , the equation is x2=2y .

For p=3 , the equation is x2=3y .

For p=4 , the equation is x2=4y .

On the Cartesian plane plot the parabolas.

The result obtained on screen is provided below,

  EBK PRECALCULUS W/LIMITS, Chapter 10.2, Problem 84E , additional homework tip 1

The red curve represents x2=y , the blue curve represents x2=2y , green curve represents x2=3y and purple curve represents x2=4y .

Interpretation:

As the value of p increase from 1 to 4 the graph becomes wider than the previous one.

  (b)

To determine

To calculate: The focus of the parabola x2=py for p=1,p=2,p=3 and p=4 .

  (b)

Expert Solution
Check Mark

Answer to Problem 84E

The focus of the parabola x2=py for p=1,p=2,p=3 and p=4 is (0,1),(0,2),(0,3) and (0,4) respectively.

Explanation of Solution

Given information:

The standard form of equation of parabola x2=py .

Formula used:

The focus of the parabola of the form x2=py is (0,p) .

Calculation:

Consider the standard form of equation of parabola x2=py .

For p=1 , the equation is x2=y .

For p=2 , the equation is x2=2y .

For p=3 , the equation is x2=3y .

For p=4 , the equation is x2=4y .

Recall thatfocus of the parabola of the form x2=py is (0,p) .

For p=1 , the equation is x2=y and focus is (0,1) .

For p=2 , the equation is x2=2y and focus is (0,2) .

For p=3 , the equation is x2=3y and focus is (0,3)

For p=4 , the equation is x2=4y and focus is (0,4) .

Thus, the focus of the parabola x2=py for p=1,p=2,p=3 and p=4 is (0,1),(0,2),(0,3) and (0,4) respectively.

  (c)

To determine

To calculate: The length of latus rectum of the parabola x2=py for p=1,p=2,p=3 and p=4 .

  (c)

Expert Solution
Check Mark

Answer to Problem 84E

The length of latus rectum of the parabola x2=py for p=1,p=2,p=3 and p=4 is 4,8,12 and 16 respectively.

Explanation of Solution

Given information:

The standard form of equation of parabola x2=py .

  EBK PRECALCULUS W/LIMITS, Chapter 10.2, Problem 84E , additional homework tip 2

Formula used:

The focus of the parabola of the form x2=py is (0,p) .

Calculation:

Consider the standard form of equation of parabola x2=py .

  EBK PRECALCULUS W/LIMITS, Chapter 10.2, Problem 84E , additional homework tip 3

Recall thatfocus of the parabola of the form x2=py is (0,p) .

For p=1 , the equation is x2=y and focus is (0,1) . Search for a point on the parabola that lie on the horizontal line y=1 .

  x2=4yx2=4(1)x2=4x=±2

Therefore, there are two points (2,1) and (−2,1) with a distance of 4 units between them.

For p=2 , the equation is x2=2y and focus is (0,2) . Search for a point on the parabola that lie on the horizontal line y=2 .

  x2=8yx2=8(2)x2=16x=±4

Therefore, there are two points (4,2) and (−4,2) with a distance of 8 units between them.

For p=3 , the equation is x2=3y and focus is (0,3) . Search for a point on the parabola that lie on the horizontal line y=3 .

  x2=12yx2=12(3)x2=36x=±6

Therefore, there are two points (6,3) and (−6,3) with a distance of 12 units between them.

For p=4 , the equation is x2=4y and focus is (0,4) . Search for a point on the parabola that lie on the horizontal line y=4 .

  x2=16yx2=16(4)x2=64x=±8

Therefore, there are two points (8,4) and (−8,4) with a distance of 16 units between them.

The length of latus rectum of parabola of the form x2=py is |4p| .

Thus, the length of latus rectum of the parabola x2=py for p=1,p=2,p=3 and p=4 is 4,8,12 and 16 respectively.

  (d)

To determine

To describe: The use of latus rectum to sketch the parabola.

  (d)

Expert Solution
Check Mark

Answer to Problem 84E

The length of latus rectum is used to identity that how narrow or shallow the parabola is.

Explanation of Solution

Given information:

The standard form of equation of parabola x2=py .

Consider the standard form of equation of parabola x2=py .

Recall thatfocus of the parabola of the form x2=py is (0,p) .

Recall that the length of latus rectum is |4p| .

The length of latus rectum is used to identity that how narrow or shallow the parabola is.

When a parabola is to be sketched, first plot the vertex and focus of the parabola. Then plot the two points on the parabola that connects the line segment of latus rectum.

At the end join the two points with the vertex to construct the parabola.

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Chapter 10.2, Problem 83E
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Chapter 10.2, Problem 85E

Chapter 10 Solutions

EBK PRECALCULUS W/LIMITS

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Prob. 15ECh. 10.7 - Prob. 16ECh. 10.7 - Prob. 17ECh. 10.7 - Prob. 18ECh. 10.7 - Prob. 19ECh. 10.7 - Prob. 20ECh. 10.7 - Prob. 21ECh. 10.7 - Prob. 22ECh. 10.7 - Prob. 23ECh. 10.7 - Prob. 24ECh. 10.7 - Prob. 25ECh. 10.7 - Prob. 26ECh. 10.7 - Prob. 27ECh. 10.7 - Prob. 28ECh. 10.7 - Prob. 29ECh. 10.7 - Prob. 30ECh. 10.7 - Prob. 31ECh. 10.7 - Prob. 32ECh. 10.7 - Prob. 33ECh. 10.7 - Prob. 34ECh. 10.7 - Prob. 35ECh. 10.7 - Prob. 36ECh. 10.7 - Prob. 37ECh. 10.7 - Prob. 38ECh. 10.7 - Prob. 39ECh. 10.7 - Prob. 40ECh. 10.7 - Prob. 41ECh. 10.7 - Prob. 42ECh. 10.7 - Prob. 43ECh. 10.7 - Prob. 44ECh. 10.7 - Prob. 45ECh. 10.7 - Prob. 46ECh. 10.7 - Prob. 47ECh. 10.7 - Prob. 48ECh. 10.7 - Prob. 49ECh. 10.7 - Prob. 50ECh. 10.7 - Prob. 51ECh. 10.7 - Prob. 52ECh. 10.7 - Prob. 53ECh. 10.7 - Prob. 54ECh. 10.7 - Prob. 55ECh. 10.7 - Prob. 56ECh. 10.7 - Prob. 57ECh. 10.7 - Prob. 58ECh. 10.7 - Prob. 59ECh. 10.7 - Prob. 60ECh. 10.7 - Prob. 61ECh. 10.7 - Prob. 62ECh. 10.7 - Prob. 63ECh. 10.7 - Prob. 64ECh. 10.7 - Prob. 65ECh. 10.7 - Prob. 66ECh. 10.7 - Prob. 67ECh. 10.7 - Prob. 68ECh. 10.7 - Prob. 69ECh. 10.7 - Prob. 70ECh. 10.7 - Prob. 71ECh. 10.7 - Prob. 72ECh. 10.7 - Prob. 73ECh. 10.7 - Prob. 74ECh. 10.7 - Prob. 75ECh. 10.7 - Prob. 76ECh. 10.7 - Prob. 77ECh. 10.7 - Prob. 78ECh. 10.7 - Prob. 79ECh. 10.7 - Prob. 80ECh. 10.7 - Prob. 81ECh. 10.7 - Prob. 82ECh. 10.7 - Prob. 83ECh. 10.7 - Prob. 84ECh. 10.7 - Prob. 85ECh. 10.7 - Prob. 86ECh. 10.7 - Prob. 87ECh. 10.7 - Prob. 88ECh. 10.7 - Prob. 89ECh. 10.7 - Prob. 90ECh. 10.7 - Prob. 91ECh. 10.7 - Prob. 92ECh. 10.7 - Prob. 93ECh. 10.7 - Prob. 94ECh. 10.7 - Prob. 95ECh. 10.7 - Prob. 96ECh. 10.7 - Prob. 97ECh. 10.7 - Prob. 98ECh. 10.7 - Prob. 99ECh. 10.7 - Prob. 100ECh. 10.7 - Prob. 101ECh. 10.7 - Prob. 102ECh. 10.7 - Prob. 103ECh. 10.7 - Prob. 104ECh. 10.7 - Prob. 105ECh. 10.7 - Prob. 106ECh. 10.7 - Prob. 107ECh. 10.7 - Prob. 108ECh. 10.7 - Prob. 109ECh. 10.7 - Prob. 110ECh. 10.7 - Prob. 111ECh. 10.7 - Prob. 112ECh. 10.7 - Prob. 113ECh. 10.7 - Prob. 114ECh. 10.7 - Prob. 115ECh. 10.8 - Prob. 1ECh. 10.8 - Prob. 2ECh. 10.8 - Prob. 3ECh. 10.8 - Prob. 4ECh. 10.8 - Prob. 5ECh. 10.8 - Prob. 6ECh. 10.8 - Prob. 7ECh. 10.8 - Prob. 8ECh. 10.8 - Prob. 9ECh. 10.8 - Prob. 10ECh. 10.8 - Prob. 11ECh. 10.8 - Prob. 12ECh. 10.8 - Prob. 13ECh. 10.8 - Prob. 14ECh. 10.8 - Prob. 15ECh. 10.8 - Prob. 16ECh. 10.8 - Prob. 17ECh. 10.8 - Prob. 18ECh. 10.8 - Prob. 19ECh. 10.8 - Prob. 20ECh. 10.8 - Prob. 21ECh. 10.8 - Prob. 22ECh. 10.8 - Prob. 23ECh. 10.8 - Prob. 24ECh. 10.8 - Prob. 25ECh. 10.8 - Prob. 26ECh. 10.8 - Prob. 27ECh. 10.8 - Prob. 28ECh. 10.8 - Prob. 29ECh. 10.8 - Prob. 30ECh. 10.8 - Prob. 31ECh. 10.8 - Prob. 32ECh. 10.8 - Prob. 33ECh. 10.8 - Prob. 34ECh. 10.8 - Prob. 35ECh. 10.8 - Prob. 36ECh. 10.8 - Prob. 37ECh. 10.8 - Prob. 38ECh. 10.8 - Prob. 39ECh. 10.8 - Prob. 40ECh. 10.8 - Prob. 41ECh. 10.8 - Prob. 42ECh. 10.8 - Prob. 43ECh. 10.8 - Prob. 44ECh. 10.8 - Prob. 45ECh. 10.8 - Prob. 46ECh. 10.8 - Prob. 47ECh. 10.8 - Prob. 48ECh. 10.8 - Prob. 49ECh. 10.8 - Prob. 50ECh. 10.8 - Prob. 51ECh. 10.8 - Prob. 52ECh. 10.8 - Prob. 53ECh. 10.8 - Prob. 54ECh. 10.8 - Prob. 55ECh. 10.8 - Prob. 56ECh. 10.8 - Prob. 57ECh. 10.8 - Prob. 58ECh. 10.8 - Prob. 59ECh. 10.8 - Prob. 60ECh. 10.8 - Prob. 61ECh. 10.8 - Prob. 62ECh. 10.8 - Prob. 63ECh. 10.8 - Prob. 64ECh. 10.8 - Prob. 65ECh. 10.8 - Prob. 66ECh. 10.8 - Prob. 67ECh. 10.8 - Prob. 68ECh. 10.8 - Prob. 69ECh. 10.8 - Prob. 70ECh. 10.8 - Prob. 71ECh. 10.8 - Prob. 72ECh. 10.8 - Prob. 73ECh. 10.8 - Prob. 74ECh. 10.8 - Prob. 75ECh. 10.8 - Prob. 76ECh. 10.8 - Prob. 77ECh. 10.8 - Prob. 78ECh. 10.8 - Prob. 79ECh. 10.8 - Prob. 80ECh. 10.9 - Prob. 1ECh. 10.9 - Prob. 2ECh. 10.9 - Prob. 3ECh. 10.9 - Prob. 4ECh. 10.9 - Prob. 5ECh. 10.9 - Prob. 6ECh. 10.9 - Prob. 7ECh. 10.9 - Prob. 8ECh. 10.9 - Prob. 9ECh. 10.9 - Prob. 10ECh. 10.9 - Prob. 11ECh. 10.9 - Prob. 12ECh. 10.9 - Prob. 13ECh. 10.9 - Prob. 14ECh. 10.9 - Prob. 15ECh. 10.9 - Prob. 16ECh. 10.9 - Prob. 17ECh. 10.9 - Prob. 18ECh. 10.9 - Prob. 19ECh. 10.9 - Prob. 20ECh. 10.9 - Prob. 21ECh. 10.9 - Prob. 22ECh. 10.9 - Prob. 23ECh. 10.9 - Prob. 24ECh. 10.9 - Prob. 25ECh. 10.9 - Prob. 26ECh. 10.9 - Prob. 27ECh. 10.9 - Prob. 28ECh. 10.9 - Prob. 29ECh. 10.9 - Prob. 30ECh. 10.9 - Prob. 31ECh. 10.9 - Prob. 32ECh. 10.9 - Prob. 33ECh. 10.9 - Prob. 34ECh. 10.9 - Prob. 35ECh. 10.9 - Prob. 36ECh. 10.9 - Prob. 37ECh. 10.9 - Prob. 38ECh. 10.9 - Prob. 39ECh. 10.9 - Prob. 40ECh. 10.9 - Prob. 41ECh. 10.9 - Prob. 42ECh. 10.9 - Prob. 43ECh. 10.9 - Prob. 44ECh. 10.9 - Prob. 45ECh. 10.9 - Prob. 46ECh. 10.9 - Prob. 47ECh. 10.9 - Prob. 48ECh. 10.9 - Prob. 49ECh. 10.9 - Prob. 50ECh. 10.9 - Prob. 51ECh. 10.9 - Prob. 52ECh. 10.9 - Prob. 53ECh. 10.9 - Prob. 54ECh. 10.9 - Prob. 55ECh. 10.9 - Prob. 56ECh. 10.9 - Prob. 57ECh. 10.9 - Prob. 58ECh. 10.9 - Prob. 59ECh. 10.9 - Prob. 60ECh. 10.9 - Prob. 61ECh. 10.9 - Prob. 62ECh. 10.9 - Prob. 63ECh. 10.9 - Prob. 64ECh. 10.9 - Prob. 65ECh. 10.9 - Prob. 66ECh. 10.9 - Prob. 67ECh. 10.9 - Prob. 68ECh. 10.9 - Prob. 69ECh. 10.9 - Prob. 70ECh. 10.9 - Prob. 71ECh. 10.9 - Prob. 72ECh. 10.9 - Prob. 73ECh. 10.9 - Prob. 74ECh. 10.9 - Prob. 75ECh. 10.9 - Prob. 76ECh. 10.9 - Prob. 77ECh. 10.9 - Prob. 78ECh. 10 - Prob. 1RECh. 10 - Prob. 2RECh. 10 - Prob. 3RECh. 10 - Prob. 4RECh. 10 - Prob. 5RECh. 10 - Prob. 6RECh. 10 - Prob. 7RECh. 10 - Prob. 8RECh. 10 - Prob. 9RECh. 10 - Prob. 10RECh. 10 - Prob. 11RECh. 10 - Prob. 12RECh. 10 - Prob. 13RECh. 10 - Prob. 14RECh. 10 - Prob. 15RECh. 10 - Prob. 16RECh. 10 - Prob. 17RECh. 10 - Prob. 18RECh. 10 - Prob. 19RECh. 10 - Prob. 20RECh. 10 - Prob. 21RECh. 10 - Prob. 22RECh. 10 - Prob. 23RECh. 10 - Prob. 24RECh. 10 - Prob. 25RECh. 10 - Prob. 26RECh. 10 - Prob. 27RECh. 10 - Prob. 28RECh. 10 - Prob. 29RECh. 10 - Prob. 30RECh. 10 - Prob. 31RECh. 10 - Prob. 32RECh. 10 - Prob. 33RECh. 10 - Prob. 34RECh. 10 - Prob. 35RECh. 10 - Prob. 36RECh. 10 - Prob. 37RECh. 10 - Prob. 38RECh. 10 - Prob. 39RECh. 10 - Prob. 40RECh. 10 - Prob. 41RECh. 10 - Prob. 42RECh. 10 - Prob. 43RECh. 10 - Prob. 44RECh. 10 - Prob. 45RECh. 10 - Prob. 46RECh. 10 - Prob. 47RECh. 10 - Prob. 48RECh. 10 - Prob. 49RECh. 10 - Prob. 50RECh. 10 - Prob. 51RECh. 10 - Prob. 52RECh. 10 - Prob. 53RECh. 10 - Prob. 54RECh. 10 - Prob. 55RECh. 10 - Prob. 56RECh. 10 - Prob. 57RECh. 10 - Prob. 58RECh. 10 - Prob. 59RECh. 10 - Prob. 60RECh. 10 - Prob. 61RECh. 10 - Prob. 62RECh. 10 - Prob. 63RECh. 10 - Prob. 64RECh. 10 - Prob. 65RECh. 10 - Prob. 66RECh. 10 - Prob. 67RECh. 10 - Prob. 68RECh. 10 - Prob. 69RECh. 10 - Prob. 70RECh. 10 - Prob. 71RECh. 10 - Prob. 72RECh. 10 - Prob. 73RECh. 10 - Prob. 74RECh. 10 - Prob. 75RECh. 10 - Prob. 76RECh. 10 - Prob. 77RECh. 10 - Prob. 78RECh. 10 - Prob. 79RECh. 10 - Prob. 80RECh. 10 - Prob. 81RECh. 10 - Prob. 82RECh. 10 - Prob. 83RECh. 10 - Prob. 84RECh. 10 - Prob. 85RECh. 10 - Prob. 86RECh. 10 - Prob. 87RECh. 10 - Prob. 88RECh. 10 - Prob. 89RECh. 10 - Prob. 90RECh. 10 - Prob. 91RECh. 10 - Prob. 92RECh. 10 - Prob. 93RECh. 10 - Prob. 94RECh. 10 - Prob. 95RECh. 10 - Prob. 96RECh. 10 - Prob. 97RECh. 10 - Prob. 98RECh. 10 - Prob. 99RECh. 10 - Prob. 100RECh. 10 - Prob. 101RECh. 10 - Prob. 102RECh. 10 - Prob. 103RECh. 10 - Prob. 104RECh. 10 - Prob. 105RECh. 10 - Prob. 106RECh. 10 - Prob. 107RECh. 10 - Prob. 108RECh. 10 - Prob. 109RECh. 10 - Prob. 110RECh. 10 - Prob. 111RECh. 10 - Prob. 112RECh. 10 - Prob. 113RECh. 10 - Prob. 114RECh. 10 - Prob. 115RECh. 10 - Prob. 116RECh. 10 - Prob. 117RECh. 10 - Prob. 118RECh. 10 - Prob. 119RECh. 10 - Prob. 1CTCh. 10 - Prob. 2CTCh. 10 - Prob. 3CTCh. 10 - Prob. 4CTCh. 10 - Prob. 5CTCh. 10 - Prob. 6CTCh. 10 - Prob. 7CTCh. 10 - Prob. 8CTCh. 10 - Prob. 9CTCh. 10 - Prob. 10CTCh. 10 - Prob. 11CTCh. 10 - Prob. 12CTCh. 10 - Prob. 13CTCh. 10 - Prob. 14CTCh. 10 - Prob. 15CTCh. 10 - Prob. 16CTCh. 10 - Prob. 17CTCh. 10 - Prob. 18CTCh. 10 - Prob. 19CTCh. 10 - Prob. 20CTCh. 10 - Prob. 21CTCh. 10 - Prob. 22CTCh. 10 - Prob. 1PSCh. 10 - Prob. 2PSCh. 10 - Prob. 3PSCh. 10 - Prob. 4PSCh. 10 - Prob. 5PSCh. 10 - Prob. 6PSCh. 10 - Prob. 7PSCh. 10 - Prob. 8PSCh. 10 - Prob. 9PSCh. 10 - Prob. 10PSCh. 10 - Prob. 11PSCh. 10 - Prob. 12PSCh. 10 - Prob. 13PSCh. 10 - Prob. 14PSCh. 10 - Prob. 15PSCh. 10 - Prob. 16PSCh. 10 - Prob. 17PS
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