Algebra 2
Algebra 2
1st Edition
ISBN: 9780078884825
Author: McGraw-Hill/Glencoe
Publisher: Glencoe/McGraw-Hill School Pub Co
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Chapter 10.4, Problem 46HP
To determine

To find: the explanation of the domain and range for an ellipse with equation.

Expert Solution & Answer
Check Mark

Answer to Problem 46HP

The domain and range for an ellipse with equation are {x|axa} and {y|byb}

Explanation of Solution

Given information:

The given equation for an ellipse is x2a2+y2b2=1

Concept used:

Write the standard form of the equation of the ellipse whose orientation is along the horizontal axis is,

  (xh)2a2+(yk)2b2=1

The coordinate of the foci is (h±c,k)

The value of c is calculated as,

  c=a2b2

The vertices are at (h±a,k) and the co-vertices are at (h,k±b) .

Write the standard form of the equation of the ellipse whose orientation is along the vertical axis is,

  (yk)2a2+(xh)2b2=1

The coordinate of the foci is (h,k±c)

The vertices are at (h,k±a) and the co-vertices are at (h±b,k) .

The value of c is calculated as,

  c=a2b2

The given equation of an ellipse is,

  x2a2+y2b2=1......(1.)

The equation as a function of x is calculated as,

  1x2a2=y2b2y2=b2(a2x2a2)y=±ba(a2x2)

  y as a function of x is

  y=±ba(a2x2).....(2.)

The expression in the radical is non-negative,

  a2x20a2x2axa

The domain of an ellipse is {x|axa}

The zero is the minimum value of the radical,

To calculated the value of y to put the minimum value of radical (0) in the function (2.)

  y=±ba(a2x2)y=±ba×0y=0

To calculate the value of y by putting the maximum value of radical (a) in the equation.(2.)

  y=±ba(a2x2)y=±ba×ay=±b

The function y lies at between b and b

The range for an ellipse is {y|byb}

Thus, the domain and range for an ellipse with equation are {x|axa} and {y|byb}

Chapter 10 Solutions

Algebra 2

Ch. 10.1 - Prob. 7CYUCh. 10.1 - Prob. 8CYUCh. 10.1 - Prob. 9CYUCh. 10.1 - Prob. 10PPSCh. 10.1 - Prob. 11PPSCh. 10.1 - Prob. 12PPSCh. 10.1 - Prob. 13PPSCh. 10.1 - Prob. 14PPSCh. 10.1 - Prob. 15PPSCh. 10.1 - Prob. 16PPSCh. 10.1 - Prob. 17PPSCh. 10.1 - Prob. 18PPSCh. 10.1 - Prob. 19PPSCh. 10.1 - Prob. 20PPSCh. 10.1 - Prob. 21PPSCh. 10.1 - Prob. 22PPSCh. 10.1 - Prob. 23PPSCh. 10.1 - Prob. 24PPSCh. 10.1 - Prob. 25PPSCh. 10.1 - Prob. 26PPSCh. 10.1 - Prob. 27PPSCh. 10.1 - Prob. 28PPSCh. 10.1 - Prob. 29PPSCh. 10.1 - Prob. 30PPSCh. 10.1 - Prob. 31PPSCh. 10.1 - Prob. 32PPSCh. 10.1 - Prob. 33PPSCh. 10.1 - Prob. 34PPSCh. 10.1 - Prob. 35PPSCh. 10.1 - Prob. 36PPSCh. 10.1 - Prob. 37PPSCh. 10.1 - Prob. 38PPSCh. 10.1 - Prob. 39PPSCh. 10.1 - Prob. 40PPSCh. 10.1 - Prob. 41PPSCh. 10.1 - Prob. 42HPCh. 10.1 - Prob. 43HPCh. 10.1 - Prob. 44HPCh. 10.1 - Prob. 45HPCh. 10.1 - Prob. 46HPCh. 10.1 - Prob. 47STPCh. 10.1 - Prob. 48STPCh. 10.1 - Prob. 49STPCh. 10.1 - Prob. 50STPCh. 10.1 - Prob. 51SRCh. 10.1 - Prob. 52SRCh. 10.1 - 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