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Math
GeometryElementary Geometry for College Students6th Edition

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Chapter 10.5, Problem 23E
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Elementary Geometry for College St...

6th Edition
Daniel C. Alexander + 1 other
ISBN: 9781285195698

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Chapter
Section
Problem 1E
Problem 2E
Problem 3E
Problem 4E
Problem 5E
Problem 6E
Problem 7E
Problem 8E
Problem 9E
Problem 10E
Problem 11E
Problem 12E
Problem 13E
Problem 14E
Problem 15E
Problem 16E
Problem 17E
Problem 18E
Problem 19E
Problem 20E
Problem 21E
Problem 22E
Problem 23E
Problem 24E
Problem 25E
Problem 26E
Problem 27E
Problem 28E
Problem 29E
Problem 30E
Problem 31E
Problem 32E
Problem 33E
Problem 34E
Problem 35E
Problem 36E
Problem 37E
Problem 38E
Problem 39E
Problem 40E
Problem 41E
Problem 42E
Problem 43E
Problem 44E
Problem 45E
Problem 46E
Problem 47E
Problem 48E
Problem 49E
BuyFindarrow_forward

Elementary Geometry for College St...

6th Edition
Daniel C. Alexander + 1 other
ISBN: 9781285195698
Textbook Problem
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In Exercises 9 to 24, find an equation of the line described. Leave the solution in the form Ax+By = C .

The line is the perpendicular bisector of the line segment that joins (3, 5) and (5,-1).

To determine

To answer:

Find the equation of the line which is the perpendicular bisector of the line segment that joins (3, 5) and (5,-1).

Explanation

The midpoint of the line segment M that joins (3, 5) and (5,-1) is calculated as follows,

M=3+52, 5-12

M=82, 42

M=4, 2

Let m1 be the slope of the line segment that joins (3, 5) and (5,-1)

Let m2 be the slope of the line for which the equation to be found.

The slope m1 is calculated using the relationship m=y-y1x-x1

Now,

x1=3

y1=5

x=5

y=-1

Substitute x1, y1, x and y to find the slope.

So,

m1=-1-55-3

m1=-62

m1=-3

Since slope of the unknown line is perpendicular to the line segment

m2=-1m1

Then

m2=-1

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Chapter 10.5,
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