a.
Change in momentum of the bullet if it is embedded in the block.
a.
Answer to Problem 101A
Explanation of Solution
Given:
Mass of bullet,
Velocity of bullet before collision,
Mass of solid block,
Formula used:
Momentum of any object is given by,
Here, P is momentum, m is mass and v is velocity
If no external force is applied on the object hen momentum is conserved.
Calculation:
Initially solid block is at rest before the collision.
Therefore, velocity of solid block before the collision,
According to conservation of momentum.
Here, v is common velocity of bullet and block after collision.
Now, substitute the value of
Therefore, velocity of bullet after collision is 0.0499 m/s
Now, change in momentum of bullet is
Here, m is mass,
Now, substitute the value of m,
Here, negative sign indicates that change in momentum of bullet will be in opposite direction of its initial velocity.
Conclusion:
Therefore,momentum of bullet when it embedded in the block is
b.
Change in momentum of the bullet if it is embedded in the block.
b.
Answer to Problem 101A
Explanation of Solution
Given:
Mass of bullet,
Velocity of bullet before collision,
Mass of solid block,
Velocity of bullet after collision is,
Formula used:
Momentum of any object is given by,
Here, P is momentum, m is mass and v is velocity
If no external force is applied on the object hen momentum is conserved.
Calculation:
Now, change in momentum of bullet is
Here, m is mass,
Now, substitute the value of m,
Here, the negative sign indicates that change momentum of bullet will be in opposite direction of its initial velocity.
Conclusion:
Therefore, momentum of bullet when it embedded in the block is
c.
The case in which block has greater speed.
c.
Answer to Problem 101A
Second case
Explanation of Solution
Given:
Mass of bullet,
Velocity of bullet before collision,
Mass of solid block,
Velocity of bullet after collision is,
Formula used:
Momentum of any object is given by
Here, P is momentum, m is mass and v is velocity
If no external force is applied on the object,then momentum is conserved.
Calculation:
From part (a), velocity of block after collision is 0.0499 m/s.
Initially solid block is at rest before the collision.
Therefore, velocity of solid block before the collision,
According to conservation of momentum.
Now, substitute the value of
Conclusion:
Therefore, velocity of block after collision will be greater in second case.
Chapter 11 Solutions
Glencoe Physics: Principles and Problems, Student Edition
Additional Science Textbook Solutions
Sears And Zemansky's University Physics With Modern Physics
College Physics: A Strategic Approach (3rd Edition)
College Physics: A Strategic Approach (4th Edition)
University Physics with Modern Physics (14th Edition)
University Physics Volume 2
College Physics (10th Edition)
- College PhysicsPhysicsISBN:9781305952300Author:Raymond A. Serway, Chris VuillePublisher:Cengage LearningUniversity Physics (14th Edition)PhysicsISBN:9780133969290Author:Hugh D. Young, Roger A. FreedmanPublisher:PEARSONIntroduction To Quantum MechanicsPhysicsISBN:9781107189638Author:Griffiths, David J., Schroeter, Darrell F.Publisher:Cambridge University Press
- Physics for Scientists and EngineersPhysicsISBN:9781337553278Author:Raymond A. Serway, John W. JewettPublisher:Cengage LearningLecture- Tutorials for Introductory AstronomyPhysicsISBN:9780321820464Author:Edward E. Prather, Tim P. Slater, Jeff P. Adams, Gina BrissendenPublisher:Addison-WesleyCollege Physics: A Strategic Approach (4th Editio...PhysicsISBN:9780134609034Author:Randall D. Knight (Professor Emeritus), Brian Jones, Stuart FieldPublisher:PEARSON