Biology: Life on Earth with Physiology Plus Mastering Biology with Pearson eText -- Access Card Package (11th Edition)
11th Edition
ISBN: 9780133910605
Author: Gerald Audesirk, Teresa Audesirk, Bruce E. Byers
Publisher: PEARSON
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Chapter 11, Problem 2MC
Summary Introduction
Introduction:
An organism’s genotype is the number of different alleles for a particular trait present in it. If the organism carries the same type of allele for a particular type of gene, it is homozygous for that particular gene. If it carries two different type of allele, it is heterozygous for that gene.
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Students have asked these similar questions
Is it possible for a bald man and a nonbald woman to have a nonbald son and bald daughter?
A. Yes, if the father is homozygous and the mother is heterozygous.
B. Yes, if both parents are heterozygous.
C. No, it is not possible.
D. Yes, if the father is heterozygous and the mother is homozygous.
Color blindness in men is controlled by a recessive gene located on the X chromosome. Can a brother and sister with color blindness have another normal brother?
A. Yes, if the mother is a carrier.
B.Yes, if the mother is homozygous.
C.Yes, if the father is heterogametic.
D.Yes, if the father is a carrier.
Which of the following is true of recessive sex-linked genes?
A.
A female showing the trait will pass it on to all of her sons who will all show the trait.
B.
A female showing the trait will pass it on to all of her daughters who will all show the trait.
C.
A male showing the trait will pass it on to all of his sons who will all show the trait.
D.
A male showing the trait will pass it on to all of his daughters who will all show the trait.
Chapter 11 Solutions
Biology: Life on Earth with Physiology Plus Mastering Biology with Pearson eText -- Access Card Package (11th Edition)
Ch. 11.1 - describe the relationships among chromosomes, DNA,...Ch. 11.1 - Prob. 2CYLCh. 11.2 - distinguish between self-fertilization and...Ch. 11.2 - Prob. 2CYLCh. 11.3 - Sudden Death on the court Many traits, in humans...Ch. 11.3 - describe the pattern of inheritance of a trait...Ch. 11.3 - Prob. 1TCCh. 11.3 - Prob. 2CYLCh. 11.3 - Prob. 3CYLCh. 11.4 - Prob. 1CYL
Ch. 11.4 - Prob. 1TCCh. 11.4 - Prob. 2CYLCh. 11.4 - Prob. 2TCCh. 11.4 - Prob. 3CYLCh. 11.5 - Prob. 1CSCCh. 11.5 - Prob. 1CYLCh. 11.5 - Prob. 1HYEWCh. 11.5 - Prob. 1TCCh. 11.5 - explain how polygenic inheritance and...Ch. 11.6 - describe how the patterns of inheritance differ...Ch. 11.7 - Prob. 1CYLCh. 11.7 - explain why most sex-linked traits are controlled...Ch. 11.7 - describe the pattern of inheritance of sex-linked...Ch. 11.8 - Prob. 1CSRCh. 11.8 - use pedigrees to determine the pattern of...Ch. 11.8 - Prob. 1ETCh. 11.8 - Prob. 1TCCh. 11.8 - Prob. 2CYLCh. 11.8 - Prob. 2ETCh. 11 - Prob. 1ACCh. 11 - An organism is described as Rr, with red coloring....Ch. 11 - In certain cattle, hair color can be red...Ch. 11 - Prob. 1MCCh. 11 - Define the following terms: gene, allele,...Ch. 11 - Prob. 2ACCh. 11 - Prob. 2FIBCh. 11 - Prob. 2GPCh. 11 - Prob. 2MCCh. 11 - Prob. 2RQCh. 11 - Prob. 3FIBCh. 11 - Prob. 3GPCh. 11 - Prob. 3MCCh. 11 - Prob. 3RQCh. 11 - Genes that are present on one sex chromosome but...Ch. 11 - Prob. 4GPCh. 11 - Prob. 4MCCh. 11 - Prob. 4RQCh. 11 - Prob. 5FIBCh. 11 - Prob. 5GPCh. 11 - Prob. 5MCCh. 11 - Prob. 5RQCh. 11 - Prob. 6GPCh. 11 - Prob. 6RQCh. 11 - In the couple described in Problem 6, the woman...
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Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, biology and related others by exploring similar questions and additional content below.Similar questions
- Which of the following statements accurately represents the difference between a gene and a locus? a. A gene is dominant, and a locus is recessive. b. A locus and a gene are essentially the same - there is no difference. c. A locus occurs in diploid cells, and a gene occurs in a haploid cell. d. A locus is a phenotype and a gene is a genotype.arrow_forwardIf a male is homozygous dominant for a trait, that parent’s genotype might be DD. If the female is heterozygous for the same trait, her type would be Dd. a. How many genetically different sperm can the male produce? b. Using punnet square, determine the expected genotypic ratios of their offspring. c. What are the expected phenotypic ratios?arrow_forwardThe gene S determines the stripe color of a kind of snake. It has two alleles which are codominant with each other: one allele (S1) causes red stripes, and the other (S2) causes white stripes. What do you predict a heterozygous (S1S2) snake will look like? Select one: a. Assortment of pink, red, and white stripes b. All pink stripes c. No stripes d. Both red and white stripesarrow_forward
- Alleles that show incomplete dominance will represent: Choose oneAnswer: A . heterozygotes that have a phenotype intermediate between the dominant and recessive alleles. B. homozygotes that have a genotype like the recessive allele C. homozygotes that have a phenotype intermediate between the dominant and recessive alleles. D. heterozygotes that have a genotype like the dominant allelearrow_forwardPhenylketonuria (PKU) is a disease that results from a recessive gene.Suppose that two unaffected parents produce a child with PKU. a. What is the probability that a sperm from the father will contain the PKU allele?b. What is the probability that an egg from the mother will contain the PKU allele?c. What is the probability that their next child will have PKU?d. What is the probability that their next child will be heterozygous for the PKU gene?arrow_forwardPhenylketonuria (PKU) is a disease that results from a recessive gene. Suppose that two unaffected parents produce a child with PKU. a. What is the probability that a sperm from the father will contain the PKU allele? b. What is the probability that an egg from the mother will contain the PKU allele? c. What is the probability that their next child will have PKU? d. What is the probability that their next child will be heterozygous for the PKU gene?arrow_forward
- Hemophilia is a disease caused by a gene found on the X chromosome. Therefore, it is referred to as a sex-linked disease. The recessive allele causes the disease. A man with hemophilia (xhy) marries a woman who is homozygous dominant (XHXH. A. Illustrate using a Punnett square the probability that their children will have the disease. B. Will any of their children have the disease? C. Predict the probabilities of their children having the disease.arrow_forwardThe allele for red feather color in pigeons, R, is dominant to the allele for brown feathers, r. A red pigeon who had a red parent and a brown parent is mated with a brown pigeon.a. Give the genotypes of the two pigeons being mated.b. Identify the gametes produced by each of the pigeons being mated.c. What proportion of the F1 progeny would be expected to have brown feathers?d. If these pigeons produce five progeny, what is the probability that all five will be red?arrow_forwardChoose the statement that is incorrect.a. A son can inherit a recessive allele on anX chromosome from either parent.b. An individual may inherit three or more of eachtype of chromosome characteristic of the species, acondition called polyploidy.c. A female child inherits one X chromosome from hermother and one from her father.d. Pedigree analysis can be used to determine a futurechild’s chance of being born with achondroplasiaarrow_forward
- Edward was found to be heterozygous (Ss) for the sickle-cell trait. The alleles represented by the letters S and s are a. on the X and Y chromosomes. b. linked. c. on homologous chromosomes. d. both present in each of Edward’s sperm cells.arrow_forwardIn Manx cats, the alleles "TT" yield a cat with a normal long tail, the alleles "Tt" yield a cat with a short or absent tail, and the alleles "tt" are lethal to the embryo. Predict the genotypes and phenotypes of potential kittens resulting from the mating of two short-tailed cats. a. genotype of male b. genotype of female c. genotypes of offspring d. phenotypes of officinaarrow_forwardThe mating below shows the sex chromosome found in two parents and their resulting offspring. Use this family information to answer the following questions. Xfmr1 Y x Xfmr1 XFMR1 → XFMR1 XFMR1Y How many Barr bodies would the child have? a. 3 b. 2 c. 1 d. 0 e. Cannot be determinedarrow_forward
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