ND STONY BROOK UNIVERSITY LOOSELEAF GENETICS: FROM GENES TO GENOMES
6th Edition
ISBN: 9781260406092
Author: HARTWELL, Leland, HOOD, Leroy, Goldberg, Michael
Publisher: Mcgraw-hill Education/stony Brook University
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Textbook Question
Chapter 11, Problem 30P
Now consider a mating between consanguineous people involving a recessive genetic disease. The figures that follow show the genotypes of these two people at four SNP loci (1–4).
a. | For which of these loci is it possible to obtain information about the linkage of the SNP to the disease gene? Explain your answer for each locus and describe any special conditions that may apply. |
b. | For any of the loci for which the mating is potentially informative, how would you tell whether the child is the product of a recombinant or non recombinant gamete? (That is, how could you solve the phase problem?) Be as specific as possible. |
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In a cross in Drosophila, a female heterozygous for the autosomallylinked genes a, b, c, d, and e (abcde/ + + + + +) was testcrossedwith a male homozygous for all recessive alleles (abcde/abcde).Even though the distance between each of the loci was at least3 map units, only four phenotypes were recovered, yielding thefollowing data:
Phenotype No. of Flies+ + + + + 440a b c d e 460+ + + + e 48a b c d + 52 Total = 1000
Why are many expected crossover phenotypes missing? Can anyof these loci be mapped from the data given here? If so, determinemap distances.
The DNA of every individual in the pedigree shown
below has been sequenced at the causative locus.
All the non-shaded individuals are wild type apart
from III.1. III.1 has been proven to have the
causative mutation for this autosomal dominant
condition, but they exhibit no symptoms. Based on
this small pedigree, what is the level of penetrance
for the condition? Please give your answer as a
WHOLE percentage, give the number only, no
percentage symbol.
Answer: The level of penetrance for the
condition shown in the pedigree below is Blank 1
percent.
1:1
1:2
Il:1
I1:2
I1:3
Il:4
I1:5
I1:6
II:1 I:2 III:3
III:4
III:3 III:6 III:7
III:8
III:9
III:10 III:11 III12 II:13 III:14
IV:1 | IV:2 IV:3 IV:4 IV:5 IV:6 IV:7 IV:8 IV:9 IV:10 IV:11 IV:12 IV:13 IV:14 IV:15 IV:16 IV:17
IV:18 IV:19
V:1 V:2 V:3 V:4 V:5
V:6
V:7
V:8 V:9
V:10
V:11 V:12
You are studying four linked genes located on chromosome 2 in the fruit fly Drosophila
melanogaster: adp (which contributes to obesity), b (which contributes to body color), pr (which
contributes to metabolism), and vg (which contributes to wing formation). A series of crosses
between pair-wise combinations of these mutations yielded the following recombination frequencies
between the indicated loci:
pr and adp 9%
adp and b 6%
pr and b 3%
vg and b 10%
vg and pr 7%
What is the genetic distance in map units (cM) between the adp and vg loci?
16
9
6
4
Chapter 11 Solutions
ND STONY BROOK UNIVERSITY LOOSELEAF GENETICS: FROM GENES TO GENOMES
Ch. 11 - Choose the phrase from the right column that best...Ch. 11 - Would you characterize the pattern of inheritance...Ch. 11 - Would you be more likely to find single nucleotide...Ch. 11 - A recent estimate of the rate of base...Ch. 11 - If you examine Fig. 11.5 closely, you will note...Ch. 11 - Approximately 50 million SNPs have thus far been...Ch. 11 - Mutations at simple sequence repeat SSR loci occur...Ch. 11 - Humans and gorillas last shared a common ancestor...Ch. 11 - In 2015, an international team of scientists...Ch. 11 - Using PCR, you want to amplify an approximately 1...
Ch. 11 - Prob. 11PCh. 11 - The previous problem raises several interesting...Ch. 11 - You want to make a recombinant DNA in which a PCR...Ch. 11 - You sequence a PCR product amplified from a...Ch. 11 - Prob. 15PCh. 11 - The trinucleotide repeat region of the Huntington...Ch. 11 - Sperm samples were taken from two men just...Ch. 11 - Prob. 18PCh. 11 - a. It is possible to perform DNA fingerprinting...Ch. 11 - On July 17, 1918, Tsar Nicholas II; his wife the...Ch. 11 - The figure that follows shows DNA fingerprint...Ch. 11 - Microarrays were used to determine the genotypes...Ch. 11 - A partial sequence of the wild-type HbA allele is...Ch. 11 - a. In Fig. 11.17b, PCR is performed to amplify...Ch. 11 - The following figure shows a partial microarray...Ch. 11 - Scientists were surprised to discover recently...Ch. 11 - The microarray shown in Problem 25 analyzes...Ch. 11 - The figure that follows shows the pedigree of a...Ch. 11 - One of the difficulties faced by human geneticists...Ch. 11 - Now consider a mating between consanguineous...Ch. 11 - The pedigree shown in Fig. 11.22 was crucial to...Ch. 11 - You have identified a SNP marker that in one large...Ch. 11 - The pedigrees indicated here were obtained with...Ch. 11 - Approximately 3 of the population carries a mutant...Ch. 11 - The drug ivacaftor has recently been developed to...Ch. 11 - In the high-throughput DNA sequencing protocol...Ch. 11 - A researcher sequences the whole exome of a...Ch. 11 - As explained in the text, the cause of many...Ch. 11 - Figure 11.26 portrayed the analysis of Miller...Ch. 11 - A research paper published in the summer of 2012...Ch. 11 - Table 11.2 and Fig. 11.27 together portray the...Ch. 11 - The human RefSeq of the entire first exon of a...Ch. 11 - Mutations in the HPRT1 gene in humans result in at...Ch. 11 - Prob. 44P
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