   Chapter 11, Problem 4RE

Chapter
Section
Textbook Problem

# Finding a Vector In Exercises 3 and 4, find the component form of v given its magnitude and the angle it makes with the positive x-axis. ‖ v ‖ = 1 2 , θ = 225 ∘

To determine

To calculate: For the given vector v where the magnitude of vector v is v=12 and the angle it makes with positive x-axis is θ=225, find Component form of v

Explanation

Given:

The magnitude of vector v is v=12 and the angle it makes with positive x-axis is θ=225

Formula used:

If any nonzero vector v makes an angle θ with the positive x-axis has the same direction asu, then:

v=vcosθ,sinθ=vcosθi+vsinθj

If u is a unit vector and θ is the angle from the positive x-axis to u, then the terminal point of u lies on the unit circle:

u=cosθ,sinθ=cosθi+sinθ

### Still sussing out bartleby?

Check out a sample textbook solution.

See a sample solution

#### The Solution to Your Study Problems

Bartleby provides explanations to thousands of textbook problems written by our experts, many with advanced degrees!

Get Started

#### In Exercises 1-6, simplify the expression. 2. 2a23ab9b22ab2+3b3

Applied Calculus for the Managerial, Life, and Social Sciences: A Brief Approach

#### Multiply: (3)(2)(4)(7)

Elementary Technical Mathematics

#### limx0+(1+x)1/x= a) e b) e c) 1e d) 1e

Study Guide for Stewart's Single Variable Calculus: Early Transcendentals, 8th

#### True or False:

Study Guide for Stewart's Multivariable Calculus, 8th 