Biology
Biology
12th Edition
ISBN: 9780134813448
Author: Audesirk, Teresa, Gerald, Byers, Bruce E.
Publisher: Pearson,
bartleby

Concept explainers

bartleby

Videos

Question
Book Icon
Chapter 11, Problem 5GP

a.

Summary Introduction

To determine: The expected proportions of phenotypes in children of BBMM × BbMm.

Introduction: The hair color in humans is regulated by two interacting genes. The pigment melanin is present in both types of hair that is brown hair as well as blond hair; however it is present more in brown haired people. Blond hair (b) is recessive to brown hair (B). The synthesis of melanin is coded by another gene having two alleles. The (M) allele allows the synthesis of melanin whereas the (m) allele prevents it. The genotypes (mm) are albino. The pigment melanin is present in both types of hair that is brown hair as well as blond hair; however it is present more in brown haired people. Blond hair (b) is recessive to brown hair (B).

b.

Summary Introduction

To determine: The expected proportions of phenotypes in children of BbMm ×BbMm.

Introduction: The mating has taken place between two doubly heterozygous individuals. Both of them have a genotype of BbMm that is both will have brown hair gene as well as gene for melanin synthesis.

c.

Summary Introduction

To determine:  The expected proportions of phenotypes in children of BbMm and bbmm.

Introduction: One of the parents have a genotype of BbMm that is will have brown hair gene as well as gene for melanin synthesis and the other parent is albino.

Blurred answer
Students have asked these similar questions
In the fruit fly, recessive mutations in either of two independently assorting genes, brown and purple, prevent the synthesis of red pigment in the eyes. Thus, homozygotes for either of these mutations have brownish-purple eyes. However, heterozygotes for both of these mutations have dark red, that is, wild-type eyes. If such double heterozygotes are intercrossed, what kinds of progeny will be produced, and in what proportions?
Colorblindness and hemophilia are both X-linked traits in humans. Explain how a female who has a defective color vision gene on one X chromosome and a defective blood clotting gene causing hemophilia on the other X chromosome can be neither a hemophiliac nor colorblind? Please discuss the effect of Gene dosage compensation in your answer and in your answer describe the molecular process by which this occurs.
One of the X chromosomes in a particular Drosophila female had a normal order of genes but carried recessive alleles of the genes for yellow body color (y), vermilion eye color (v), and forked bristles (f), as well as the dominant X-linked Bar eye mutation (B). Her other X chromosome carried the wild-type alleles of all four genes, but the region including y+, v+, and f+ (but not B+) was inverted with respect to the normal order of genes. This female was crossed to a wild- type male in the cross diagrammed her. The cross produced the following male offspring:* table in figure a. Why are there no male offspring with the allele combinations y v f+, v+ v+ f, y v+ f+, or y+ v f (regardless of the allele of the Bar eye gene)?b. What kinds of crossovers produced the y v f b+ and v+ y+ f+ B offspring? Can you determine any genetic distances from these classed of progeny?c. What kinds of crossovers produced the y+ v f+ B+ and y v+ f B offspring?

Chapter 11 Solutions

Biology

Knowledge Booster
Background pattern image
Biology
Learn more about
Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, biology and related others by exploring similar questions and additional content below.
Similar questions
SEE MORE QUESTIONS
Recommended textbooks for you
Text book image
Human Heredity: Principles and Issues (MindTap Co...
Biology
ISBN:9781305251052
Author:Michael Cummings
Publisher:Cengage Learning
Mechanisms of Genetic Change or Evolution; Author: Scientist Cindy;https://www.youtube.com/watch?v=5FE8WvGzS4Q;License: Standard Youtube License