Concept explainers
a .
the force that stretches the spring 0.1 meter
a .
Answer to Problem 66E
Explanation of Solution
Given:
A force of 265 newtons stretches a spring 0.15 meter.
Concept Used:
Hooke’s Law states that the distance y a spring stretches (or compresses) from its natural, or equilibrium, length varies directly as the applied force x on the spring. That is
Where k is a non-zero constant called the constant of proportionality.
Now, it is given that when
Substitute these values in equation (1),
Thus, equation (1) becomes,
Substitute
Conclusion:
The force that stretches the spring 0.1 meter is 176.78 newtons.
b.
To find: the distance to which a force of 90 newtons stretches the spring.
b.
Answer to Problem 66E
Explanation of Solution
Given:
From part (a), the spring follows the model:
Substitute
Conclusion:
A force of 90 newtons stretches the spring to a distance of 0.0509 meters.
Chapter 1 Solutions
EBK PRECALCULUS W/LIMITS
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