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Recall the skater described at the beginning of this section. Let her mass be m. (i) What would be her
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Chapter 11 Solutions
Bundle: Physics for Scientists and Engineers, Volume 2, Loose-leaf Version, 10th + WebAssign Printed Access Card for Serway/Jewett's Physics for Scientists and Engineers, 10th, Multi-Term
- The centrifuge at NASA Ames Research Center has a radius of 8.8 m and can produce farces on its payload of 20 gs or 20 times the force of gravity on Earth. (a) What is the angular momentum of a 20-kg payload that experiences 10 gs in the centrifuge? (b) If the driver motor was turned off in (a) and the payload lost 10 kg, what would be its new spin rate, taking into account there are no frictional forces present?arrow_forwardConsider the figure below. A baton consists of two uniform spheres, each of mass 0.50 kg and radius 5.0 cm are mounted at the ends of a 0.30 m uniform rod. A student spins the baton about an axis perpendicular to the rod and passing through its center as shown in the figure. If we simplify the problem by treating each sphere as a point particle (located at the center of the sphere) and the baton as massless, what is the moment of inertia of the entire system at this axis of rotation?arrow_forwardPlease answer C, D, E The angular position of a rod varies as 20.7t2 radians from time t = 0. The rod has two beads on it as shown in the following figure, one at r1 = 13 cm from the rotation axis and the other at r2 = 32 cm from the rotation axis. (Note: figure may not be drawn to scale.) (a) What is the instantaneous angular velocity (in rad/s) of the rod at t = 3 s? (Indicate the direction with the sign of your answer. Round your answer to at least one decimal place.) 1.24.2 rad/s, ANSWERED (b) What is the angular acceleration (in rad/s2) of the rod at t = 3 s? (Indicate the direction with the sign of your answer.) 41.4 rad/s2, ANSWERED (c) What are the tangential speeds of the beads (in m/s) at t = 3 s? vt, 1 =16.146 m/s, ANSWERED vt, 2 =____m/s (d)What are the tangential accelerations of the beads at t = 3 s? (Enter the magnitudes in m/s2.) at, 1 = ______ m/s2 at, 2 = ______ m/s2 (e) What are the centripetal accelerations of the beads at t = 3 s? (Enter the magnitudes…arrow_forward
- (Please explain)In a collision of disks, where the system is not isolated because of the existence of friction. How is it possible that conservation of angular momentum is still valid to a relatively good accuracy?arrow_forwardConsider a cylindrical turntable whose mass is M and radius is R, turning with an initial angular speed ω1. (a) A parakeet of mass m, after hovering in flight above the outer edge of the turntable, gently lands on it and stays in one place on it, as shown below. What is the angular speed of the turntable after the parakeet lands? (Use any variable or symbol stated above as necessary.) (b) Becoming dizzy, the parakeet jumps off (not flies off) with a velocity relative to the turntable. The direction of is tangent to the edge of the turntable and in the direction of its rotation. What will be the angular speed of the turntable afterwards? Express your answer in terms of the two masses m and M, the radius R, the parakeet speed and the initial angular speed ω1. (Use any variable or symbol stated above along with the following as necessary: v for ||.)arrow_forwardA uniform 2-kg solid disk of radius R=0.4m is free to rotate on a frictionless horizontal axle through its center. The disk is initially at rest, and then a 10-g bullet traveling at 530 m/s is fired into it as shown in the figure below. If the bullet embeds itself in the disk at a vertical distance of 0.2 m above the axle, what will be the angular velocity of the disk?arrow_forward
- A 0.005 00-kg bullet traveling horizontally with a speed of 1.00 × 103 m/s strikes an 18.0-kg door, embedding itself 10.0 cm from the side opposite the hinges as shown in Figure. The 1.00-m wide door is free to swing on its frictionless hinges. (a) Before it hits the door, doesthe bullet have angular momentum relative to the door’s axis of rotation? (b) If so, evaluate this angular momentum. If not, explain why there is no angular momentum. (c) Is the mechanical energy of the bullet–door system constant during this collision? Answer without doing a calculation. (d) At what angular speed does the door swing open immediately after thecollision? (e) Calculate the total energy of the bullet–door system and determine whether it is less than or equal to the kinetic energy’ of the bullet before the collision. (f) What If? Imagine now that the door is hanging vertically downward, hinged at the top, so that Figure is aside view of the door and bullet during the collision. What is the maximum…arrow_forwardSolve on-page and correctly. Calculate the angular momentum about the Earth’s center, of 84.3kg person on the equator of rotating earth?arrow_forwardSuppose a 0.250-kg ball is thrown at 14.0 m/s to a motionless person standing on ice who catches it with an outstretched arm as shown in the figure below. (a) Calculate the final linear velocity of the person, given his mass is 67.5 kg.(b) What is his angular velocity if each arm is 5.00 kg in mass? You may treat his arms as uniform rods of length 0.9 m (measured from the center axis of his body) and the rest of his body as a uniform cylinder of radius 0.170 m. Neglect the effect of the ball on his rotational inertia and on his center of mass, so that it remains in his geometrical center. (Answer is NOT 0.415)(c) Compare the initial and final total kinetic energy. (Answer is NOT 32.92) KEi KEf =arrow_forward
- Consider the figure above consisting of three particles of mass m attached to a massless rod. Given an axis of rotation through point P, the rod rotates as shown in the figure. If the rod is released from rest in the horizontal position at t = 0. What is the angular acceleration of the system (rod and three particles) immediately after being released? Let d = 2.00 m.arrow_forwardA wheel is rolling without slipping on a horizontal surface. In an inertial frame of reference in which the surface is at rest, is there any point on the wheel that has a velocity that is purely vertical? Is there any point that has a horizontal velocity component opposite to the velocity of the center of mass? Explain. Do your answers change if the wheel is slipping as it rolls? Why or why not?arrow_forwardConsider the Atwood machine, where two masses m1 = 12.6 kg and m2 = 4.2 kg are connected by an ideal wire that passes through a pulley of mass M = E of radius R = 0.15 m. The pulley is attached, but can rotate freely around its axis of symmetry. As shown in the Figure below, at the initial instant the mass m1 is at a height h= 3.29 m in relation to m2. Knowing that the system starts from rest, and that the magnitude of the linear velocity of m1 when the masses pass through the same vertical position is v=3.31 m/s, what is the mass M of the pulley? Here, assume the acceleration due to gravity as g=10 m/s², the pulley moment of inertia as I=MR2 and, finally, that the wire does not slide on the pulley. Choose one: a. 4,2 kg b. 14,7 kg c. 10,5 kg d. 6,3 kg e. 12,6 kg f. 16,8 kg g. 8,4 kg h. None of the other alternatives.arrow_forward
- Glencoe Physics: Principles and Problems, Student...PhysicsISBN:9780078807213Author:Paul W. ZitzewitzPublisher:Glencoe/McGraw-HillUniversity Physics Volume 1PhysicsISBN:9781938168277Author:William Moebs, Samuel J. Ling, Jeff SannyPublisher:OpenStax - Rice University