Elementary Statistics - With CD and Access
12th Edition
ISBN: 9780321934895
Author: Triola
Publisher: PEARSON
expand_more
expand_more
format_list_bulleted
Concept explainers
Question
Chapter 11.3, Problem 15BSC
To determine
To test: The claim that getting a cold is independent of the treatment groups.
To explain: Whether Echinacea is effective in preventing cold.
Expert Solution & Answer
Want to see the full answer?
Check out a sample textbook solutionStudents have asked these similar questions
Does cable video-on-demand (VOD) increase ad effectiveness? A study compared general TV and VOD audiences after viewing a brand ad. Whether the viewer indicated that the ad made them want to visit the brand website was collected and organized in the accompanying table. Complete parts (a) through (b) below. Test at the 1% level of significance.
Set up null and alternative hypotheses to try to determine whether there is a difference in ad impact between general TV viewing and VOD viewing.
Let group 1 be the general TV audience, and let group 2 be the VOD audience. State the null and alternative hypotheses. Choose the correct answer below.
A.
H0: P1<P2
H1: P1≥P2
B.
H0: P1=P2
H1: P1≠P2
C.
H0: P1≠P2
H1: P1=P2
D.
H0:
P1≤P2
H1:
P1>P2
E.
H0: P1>P2
H1: P1≤P2
F.
H0: P1≥P2
H1: P1<P2
Calculate the test statistic.
Conduct the hypothesis test defined in (a), using the 0.01 level of significance.…
The General Social Survey polled 1280 men and 1531 women to determine their level of education. The results are presented in the following table. Test at the 0.01 level of significance if education level is independent of gender.
Education Level
No High School Diploma
High School Diploma
Associate’s Degree
Bachelor’s Degree
Graduate Degree
Men
178
608
96
248
150
Women
186
827
128
259
131
(a) State the hypotheses.
(b) Statetheteststatistic.
(c) CalculatetheP-value.
(d) Makeadecision.
(e) Statetheconclusionaddressingtheoriginalclaim.
Independent random samples of 32 people living on the west side of a city and 30 people living on the east side of a city were taken to determine if the income levels of west side residents are significantly different from the income levels of east side residents. Given the testing statistics below, determine if the data provides sufficient evidence to conclude that the income levels of west side residents are significantly different from the income levels of east side residents, at the 2% significance level.
H0:μw=μeHa:μw≠μe
t0=2.364
t0.01=±2.099
Select the correct answer below:
No; the test statistic is not between the critical values.
No; the test statistic is between the critical values.
Yes; the test statistic is not between the critical values.
Yes; the test statistic is between the critical values.
Chapter 11 Solutions
Elementary Statistics - With CD and Access
Ch. 11.2 - Prob. 1BSCCh. 11.2 - Prob. 2BSCCh. 11.2 - Prob. 3BSCCh. 11.2 - Prob. 4BSCCh. 11.2 - Prob. 5BSCCh. 11.2 - Prob. 6BSCCh. 11.2 - In Exercises 5-20, conduct the hypothesis test and...Ch. 11.2 - In Exercises 5-20, conduct the hypothesis test and...Ch. 11.2 - Prob. 9BSCCh. 11.2 - In Exercises 5-20, conduct the hypothesis test and...
Ch. 11.2 - Prob. 11BSCCh. 11.2 - In Exercises 5-20, conduct the hypothesis test and...Ch. 11.2 - Prob. 13BSCCh. 11.2 - Prob. 14BSCCh. 11.2 - In Exercises 5-20, conduct the hypothesis test and...Ch. 11.2 - In Exercises 5-20, conduct the hypothesis test and...Ch. 11.2 - Prob. 17BSCCh. 11.2 - American Idol Contestants on the TV show American...Ch. 11.2 - In Exercises 5-20, conduct the hypothesis test and...Ch. 11.2 - Prob. 20BSCCh. 11.2 - Prob. 21BSCCh. 11.2 - Prob. 22BSCCh. 11.2 - Benfords Law. According to Benfords law, a variety...Ch. 11.2 - Prob. 24BSCCh. 11.2 - Testing Goodness-of-Fit with a Normal Distribution...Ch. 11.3 - Smoking Cessation The accompanying table...Ch. 11.3 - Prob. 2BSCCh. 11.3 - Degrees of Freedom and Critical Value For the...Ch. 11.3 - Prob. 4BSCCh. 11.3 - Prob. 5BSCCh. 11.3 - Prob. 6BSCCh. 11.3 - Prob. 7BSCCh. 11.3 - Prob. 8BSCCh. 11.3 - In Exercises 5-18, test the given claim. 9. Is...Ch. 11.3 - Prob. 10BSCCh. 11.3 - In Exercises 5-18, test the given claim. 11....Ch. 11.3 - Prob. 12BSCCh. 11.3 - Soccer Strategy In soccer, serious fouls in the...Ch. 11.3 - Prob. 14BSCCh. 11.3 - Prob. 15BSCCh. 11.3 - In Exercises 5-18, test the given claim. 16....Ch. 11.3 - Prob. 17BSCCh. 11.3 - Prob. 18BSCCh. 11.3 - Prob. 19BSCCh. 11.3 - Prob. 20BSCCh. 11.3 - Prob. 21BBCh. 11.3 - Using Yatess Correction for Continuity The...Ch. 11 - Prob. 1CQQCh. 11 - Prob. 2CQQCh. 11 - Questions 1-5 refer to the sample data in the...Ch. 11 - Prob. 4CQQCh. 11 - Prob. 5CQQCh. 11 - Prob. 6CQQCh. 11 - Prob. 7CQQCh. 11 - Prob. 8CQQCh. 11 - Prob. 9CQQCh. 11 - Questions 6-10 refer to the sample data in the...Ch. 11 - Auto Fatalities The table below lists auto...Ch. 11 - Prob. 2RECh. 11 - Prob. 3RECh. 11 - Prob. 4RECh. 11 - Prob. 5RECh. 11 - Home Field Advantage Winning-team data were...Ch. 11 - Prob. 1CRECh. 11 - Prob. 2CRECh. 11 - ICU Patients Listed below are the ages of randomly...Ch. 11 - Prob. 4CRECh. 11 - Boats and Manatees The table below lists the...Ch. 11 - Forward Grip Reach and Ergonomics When designing...Ch. 11 - Honesty Is the Best Policy In a USA Today survey...Ch. 11 - Probability and Honesty Based on the sample...Ch. 11 - Use Statdisk, Minitab, Excel, StatCrunch, a...Ch. 11 - Prob. 1FDD
Knowledge Booster
Learn more about
Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, statistics and related others by exploring similar questions and additional content below.Similar questions
- What is meant by the sample space of an experiment?arrow_forwardThe data below are stress-test scores from 6 nurses from the Emergency Care (EC) unit and 6 nurses from the Long Term (LT) care unit who were randomly selected for the study. The investigator wants to test, at the 5% level, whether there is a difference in stress test scores in the EC group and the LT group. EC LT 5 2 9 3 8 5 10 6 7 4 6 2 State the hypotheses. What statistical test should be used to determine if there is a difference in stress scores between EC and LT nurses? Determine the appropriate critical value and set up the decision rule. Compute the test statistic. Interpret your results. Give your conclusion.arrow_forwardA professor at a large university believes that students take an average of 15 credit hours per term. A random sample of 22 students in her class of 250 students reported the following number of credit hours that they were taking: 12 12 12 13 13 14 14 14 14 15 15 15 16 16 16 16 16 17 17 18 19 21 Does this sample indicate that students are taking more credit hours than the professor believes? Test an appropriate hypothesis and state your conclusion at 5% significance level. Which method will you use to perform the test? Choose the correct one. a1-sample T test b2-sample T test c-sample Z test d-sample T teste- e1proportion Z test.arrow_forward
- Again, suppose you work for AMC Cinemas (a national chain of movie theaters). You try to forecast future revenue from movie ticket sales based on the number of competing theaters within 15 miles, the ticket price at the nearest competitor, advertising expenditures, the local unemployment rate, and average outdoor temperature. Answer the following questions. (a) Suppose your quantitative study uses a 5% significance level in all hypothesis tests. In words, explain what a 5% significance level means. (b) Suppose that, instead of movie ticket sales, you use the same independent variables to predict popcorn sales at theaters. Would you expect a regression model for popcorn sales to have a higher, lower, or similar R-square value in comparison to the regression model for movie ticket sales? Explain the reasoning behind your expectation.arrow_forwardIndependent random samples of 31 people living on the west side of a city and 25 people living on the east side of a city were taken to determine if the income levels of west side residents are greater than the income levels of east side residents. Given the testing statistics below, determine if the data provides sufficient evidence to conclude that the income levels of west side residents are greater than the income levels of east side residents, at the 2% significance level. H0:μw≤μeHa:μw>μe t0=0.511 t0.02=2.104 Select the correct answer below: Yes; the test statistic is greater than the critical value. No; the test statistic is greater than the critical value. No; the test statistic is less than the critical value. Yes; the test statistic is less than the critical value.arrow_forwardIndependent random samples of 27 people living on the west side of a city and 26 people living on the east side of a city were taken to determine if the income levels of west side residents are less than the income levels of east side residents. Given the testing statistics below, determine if the data provides sufficient evidence to conclude that the income levels of west side residents are less than the income levels of east side residents, at the 4% significance level. H0:μw≥μeHa:μw<μe t0=−2.344 t0.04=−2.107 Select the correct answer below: Yes; the test statistic is greater than the critical value. No; the test statistic is less than the critical value. No; the test statistic is greater than the critical value. Yes; the test statistic is less than the critical value.arrow_forward
- A survey was conducted to investigate the relationship between gender (male and females) and sector of employment (private, government and academia). Using the information provided, does a relationship exist between gender and employment sector at the 5% significance level? Define the null hypothesis and the alternative hypothesis. A. H0: Gender and employment sector are independent vs H1: A relationship exists between gender and employment sector B. H1: Gender and employment sector are independent vs H0: No relationship exists between gender and employment sector C. H1: Gender and employment sector are independent vs H0: Gender is dependent on employment sector D. H0: A relationship exists between gender and employment sector vs H1: No relationship exists between gender and employment sectorarrow_forwardBack in April and May 19 85 the Gallup organization conducted a pool to estimate the percentage of Americans who approved President Reagan was at the 5% significance level to the data suggest that the percentage of those who approved the Reagan increase in 1985? Population 1 April P=795/1528 = 0.5203 Population 2 May P=840/1528 = 0.5497.So all your steps setting up your Null and alternative hypothesisarrow_forwardIn a study of high school students at least 16 years of age, researches obtained data summarized in the table below. Test the claim that texting while driving is independent of drinking alchohol and driving. Assume a significance level of 0.05. Drove when Drinking Did not drive when Drinking Totals Texting while Driving 731 3054 3785 No Texting and Driving 156 4564 4720 Totals 887 7618 8505 c) What is the Alternative Hypothesis? d) Which type of test will be used? e) What critical values are there?arrow_forward
- Applying the Concepts and SkillsUse the technology of your choice to solve Problems.Smoking and Cotinine. Smoking during pregnancy is hazardousto both the mother and baby. Passive smoking, or inhalation of second-hand smoke, is also a concern. In the article “Detection of Cotinine in Neonate Meconium as a Marker for Nicotine Exposure in Utero” (Eastern Mediterranean Health Journal, Vol. 10, No. 1/2, pp. 96–105), N. Sherif et al. studied whether activesmoking or passive-smoking mothers were passing along harmful chemicals to their babies. The level of cotinine in a newborn’s first meconium, which is the infant’s stool, is reported on the WeissStats site for independent samples of active-, passive-, and nonsmoking mothers. Cotinine levels are measured in nanograms per milliliter (ng/mL). Decide whether presuming that the assumptions of normal populations and equal population standard deviations are met is reasonable.arrow_forwardRhino viruses typically cause common colds. In a test of the effectiveness of echinacea, 41 of the 47 subjects treated with echinacea developed rhinovirus infections. In a placebo group, 74 of the 90 subjects developed rhinovirus infections. Use a 0.01 significance level to test the claim that echinacea has an effect on rhinovirus infections. Complete parts (a) through (c) below. H0: p1=p2 H1: p1≠p2 a. Test the claim using a hypothesis test. Consider the first sample to be the sample of subjects treated with echinacea and the second sample to be the sample of subjects treated with a placebo. What are the null and alternative hypotheses for the hypothesis test? Identify the test statistic. z = _________ Identify the P-value p-value = _________arrow_forward“Passive and Active Smoke” in Appendix B includes cotinine levels measured in a group of nonsmokers exposed to tobacco smoke (n = 40, Mean = 60.58 ng>mL, s = 138.08 ng>mL) and a group of nonsmokers not exposed to tobacco smoke (n = 40, Mean = 16.35 ng>mL, s = 62.53 ng>mL). Cotinine is a metabolite of nicotine, meaning that when nicotine is absorbed by the body, cotinine is produced. Use a 0.05 significance level to test the claim that nonsmokers exposed to tobacco smoke have a higher mean cotinine level than nonsmokers not exposed to tobacco smoke. 1. Construct a confidence interval estimate of the difference betwen the mean continen levels fo the two groups of nonsmokers. What confidence level would be appropriate? 2. Find the margin of error E using the formula. 3. What is the confidence interval? Explain the meaning of the confidence interal and what the limit represents.arrow_forward
arrow_back_ios
SEE MORE QUESTIONS
arrow_forward_ios
Recommended textbooks for you
- College Algebra (MindTap Course List)AlgebraISBN:9781305652231Author:R. David Gustafson, Jeff HughesPublisher:Cengage Learning
College Algebra (MindTap Course List)
Algebra
ISBN:9781305652231
Author:R. David Gustafson, Jeff Hughes
Publisher:Cengage Learning
Which is the best chart: Selecting among 14 types of charts Part II; Author: 365 Data Science;https://www.youtube.com/watch?v=qGaIB-bRn-A;License: Standard YouTube License, CC-BY