Campbell Biology in Focus, Books a la Carte Edition; Modified Mastering Biology with Pearson eText - ValuePack Access Card - for Campbell Biology in Focus (2nd Edition)
2nd Edition
ISBN: 9780134433769
Author: Lisa A. Urry, Michael L. Cain, Steven A. Wasserman
Publisher: PEARSON
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Chapter 11.4, Problem 2CC
MAKE CONNECTIONS In Table 11.1, note the
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EXAMPLE PROBLEM A plant with orange, spotted flowers was grown in the greenhouse from a seed collected in the wild. The plant was self-pollinated and gave rise to the following progeny: 88 orange with spots, 34 yellow with spots, 32 orange with no spots, and 8 yellow with no spots. What can you conclude about the dominance relationships of the alleles responsible for the spotted and unspotted phenotypes? What can you conclude about the genotype of the original plant that had orange, spotted flowers?
Topic: Trihybrid Cross,
Height in merigonias is determined by three unlinked genes that act additively. Each has two alleles, one compltely dominant allele(A,B or C) that makes plants taller and one recessive allele that makes plants shorter. Do the corss AaBbCc X AaBbCc. The fraction of The F1 progenty will be ? Pls explain it with more details. thanks
Consider these two crosses and assume that independent segregation is exhibited by all gene pairs:
RrmmTT x RRMmTtFfGg x FfGg
Derive the gametic ratio of the second parent in each cross using the branching method.
What proportion of the offspring in each cross will be heterozygous for all gene pairs?
Derive the genotypic ratio for the offspring from each cross using the branching method.
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Chapter 11 Solutions
Campbell Biology in Focus, Books a la Carte Edition; Modified Mastering Biology with Pearson eText - ValuePack Access Card - for Campbell Biology in Focus (2nd Edition)
Ch. 11.1 - DRAW IT Pea plants heterozygous for flower...Ch. 11.1 - List all gametes that could be made by a pea plant...Ch. 11.1 - Prob. 3CCCh. 11.2 - For any gene with a dominant allele A and...Ch. 11.2 - Two organisms, with genotypes BbDD and BBDd, are...Ch. 11.2 - Prob. 3CCCh. 11.3 - Incomplete dominance and epistasis are both terms...Ch. 11.3 - Prob. 2CCCh. 11.3 - WHAT IF? A rooster with gray feathers and a hen of...Ch. 11.4 - Beth and Tom each have a sibling with cystic...
Ch. 11.4 - MAKE CONNECTIONS In Table 11.1, note the...Ch. 11 - DRAW IT Two pea plants heterozygous for the...Ch. 11 - A man with type A blood marries a woman with type...Ch. 11 - A man has six fingers on each hand and six toes on...Ch. 11 - Prob. 4TYUCh. 11 - Flower position, stem length, and seed shape are...Ch. 11 - Prob. 6TYUCh. 11 - Prob. 7TYUCh. 11 - Prob. 8TYUCh. 11 - Prob. 9TYUCh. 11 - Prob. 10TYUCh. 11 - In tigers, a recessive allele that is pleiotropic...Ch. 11 - Prob. 12TYUCh. 11 - Imagine that you are a genetic counselor, and a...Ch. 11 - Prob. 15TYUCh. 11 - Prob. 16TYUCh. 11 - Prob. 17TYU
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- INTERPRET DATA Using the graph in Figure 11-20, determine how many offspring were involved in the hypothetical cross studying skin color. What percentage had the lightest skin possible? the darkest skin possible? Figure 11-20 Polygenic inheritance in human s pigmentation This simplified example assumes that skin pigmentation in humans is governed by alleles of three unlinked loci. The alleles producing dark skin (A, B, and C) are represented by capital letters, but they are not dominant. Instead, their effects are additive. The number of dark dots, each signifying an allele producing dark skin, is counted to determine the phenotype. A wide range of phenotypes is possible when individuals of intermediate phenotype mate and have offspring (AaBbCc AaBbCc). The expected distribution of phenotypes is consistent with the superimposed normal distribution curve.arrow_forwardGive typed explanation In pea plants, the tall allele (T) is dominant to the dwarf allele (t) and the yellow pea color allele (Y) is dominant to the green pea color allele (y). Cross TtYy with Ttyy. What would be the genotype and phenotype ratios in their offspring? (Please include the gametes produced by each parent.)arrow_forwardFinish these crosses below:(assume all parents are homozygous for alleles) Cross 1:These are the parents: Sepia Male, Wild Type FemaleWhat are the alleles of the parents? (like Aa and AA / or like XY and XWXW+) Use a Punnett square below to determine the F1 generation phenotypic ratios. What is the phenotypic ratio of the F1? If two F1 individuals mated, what would the F2 phenotypic ratios be?arrow_forward
- Please answer fast 2. Devise a simple method to calculate the total number of offspring genotypes and the total number of phenotypes (assuming complete dominance of Q, R and T) produced in the following cross without completing a branch diagram? q q R r Tt X Q Q r r T tarrow_forwardPEDIGREE ANALYSIS ANSWER THE FOLLOWING QUESTIONS 1. The chart shows a family's pedigree for Hitchhikers Thumb. Is this trait dominant or recessive? 2. How do you know? 3. How are individuals III-1 and III-2 related? 4. How would you name the two individuals that have Hitchhiker"s thumb? 5. Name the 2 individuals that were carriers of Hitchhiker's Thumb. 6. Is it possible for individual IV-2 to be a carrier? Why?arrow_forwardWhat is the relative fitness of the F1 hybrids relative to both parental populations according to this model?arrow_forward
- Curly wings is a recessive character in the fruitfly Drosophila melanogaster. The wild type dominant phenotype is straight wings. Flies heterozygous for straight wings were mated and the resulting offspring were a mix of straight and curly winged flies. What is the probability that of the 5 offspring from a single pair mating will be curly winged and 5 were straight winged? Use the binomial expansion.arrow_forwardIn a test cross, an individual dominant for a certain trait ( whether homozygous or heterozygous is unknown) is crossed with a homozygous recessive individual. A plant with spherical seeds is crossed with another plant. If the genotypes and phenotypes of the offspring are 100% heterozygous and 100% dominant, what were the genotypes of the parents? (hint: try multiple crosses until you find what works) If the genotypes and phenotypes of the offspring are 50% heterozygous spherical seeds and 50% wrinkled seeds, what were the genotypes of the parents?arrow_forwarduppose that goats have one gene that codes for color, where A is brown and a is white. The goats also have another gene that codes for height, where B is tall and b is short. If these two genes are unlinked, what is the probability that a cross between Aa Bb × Aa bb parents will produce three out of five offspring that are white and tall? Enter your answer as a decimal, rather than as a percentage. probability: 0.006 Please advise how it comes out to 0.006. that is the correct answer per the professorarrow_forward
- You are mapping three loci in Brandywine apricot trees (Prunus brandybucki), an important agricultural species in the Shire. In Brandywine apricot trees, sour fruit (fr+) is dominant to fishy-tasting fruit (fr), blue flowers (b+) is dominant to yellow flowers (b), and short, bushy height (sh+) is dominant to tall, tree-like height (sh). You perform a testcross with a plant that is heterozygous for all three loci and get the following offspring: Fruit flavor Flower color Plant height Observed Counts fr+ b+ sh+ 61 fr b sh 53 fr+ b+ sh 11 fr b sh+ 7 fr+ b sh 277 fr b+ sh+ 285 fr+ b sh+ 156 fr b+ sh 150 Total 1000 What is the recombination frequency between b and sh?arrow_forwardfigure shows the results of a dihybrid cross involving seed shape and seed color. Q. What proportion of the round and yellow F2 progeny from this cross is homozygous at least at one locus?arrow_forwardIf homozygous recessive (aa,tetrapter) f1 produces homozygous (aa) f2, what is the dominant and recessive trait of f2? Let’s say the dominant trait of the parents of f1 is Wild type and the recessive trait is Tetrapter.arrow_forward
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