Introduction to Probability and Statistics
14th Edition
ISBN: 9781133103752
Author: Mendenhall, William
Publisher: Cengage Learning
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Chapter 11.5, Problem 11.2E
(a)
To determine
To complete:the ANOVA table .
(b)
To determine
To find: the number of degrees of freedom associated with the F statistic.
(c)
To determine
To give: the rejection region for the test in part b for
(d)
To determine
To find: whether the given data is an evidence to indicate differences among the population means.
(e)
To determine
To estimate: the p -value for the test and explain whether the value confirms part d conclusion.
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Chapter 11 Solutions
Introduction to Probability and Statistics
Ch. 11.5 - Prob. 11.1ECh. 11.5 - Prob. 11.2ECh. 11.5 - Prob. 11.3ECh. 11.5 - Prob. 11.4ECh. 11.5 - Prob. 11.5ECh. 11.5 - Prob. 11.6ECh. 11.5 - These data are observations collected using a...Ch. 11.5 - Prob. 11.8ECh. 11.5 - Prob. 11.9ECh. 11.5 - Reducing Hostility A clinical psychologist wished...
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- Let ?1 denote true average tread life for a premium brand of P205/65R15 radial tire, and let ?2 denote the true average tread life for an economy brand of the same size. Test H0: ?1 − ?2 = 5000 versus Ha: ?1 − ?2 > 5000 at level 0.01, using the following data: m = 45, x = 42,100, s1 = 2400, n = 45, y = 36,200, and s2 = 1800. Calculate the test statistic and determine the P-value. (Round your test statistic to two decimal places and your P-value to four decimal places.) z = P-value = State the conclusion in the problem context. Fail to reject H0. The data does not suggest that the difference in average tread life exceeds 5000.Reject H0. The data suggests that the difference in average tread life exceeds 5000. Fail to reject H0. The data suggests that the difference in average tread life exceeds 5000.Reject H0. The data does not suggest that the difference in average tread life exceeds 5000.arrow_forwardIn a test of H0: p = 0.4 against H1: p ≠ 0.4, a sample of size 100 produces Z = 1.28 for the value of the test statistic. Thus the p-value (or observed level of significance) of the test is approximately equal to:arrow_forwardIn a test of H0: µ=150 against HA: µ<150, a sample of size 250 produces Z = -0.65 for the value of the test statistic. Thus the p-value is approximately equal toarrow_forward
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