Temperature of 525 ml CO 2 having mass of 0.226gram and pressure of 455mmHg Conceptual Introduction: The ideal gas law or general gas equation is an equation for ideal gas. Equation as follows- PV = nRT Where, P = pressure of gas V = volume of gas N= No. of moles of gas (amount of substance in gas) R = Universal gas constant The gas constant R has a value 8.314J/mole Kelvin T = Temperature in Kelvin T (Kelvin) = T (Celsius) + 273.15 (Conversion from kelvin to Celsius) Molar mass of substance are given in periodic table. Element molar mass is in gram/mole. We can determine chemical amount of known substance in moles by dividing the substance mass in grams by substance molar mass Given: Volume = 525 ml Pressure = 455 mmHg Mass = 0.226 grams

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Answer 1

Question

Chapter 11.7, Problem 11.60QAP

Interpretation Introduction

Interpretation: Temperature of 525 ml CO₂having mass of 0.226gram and pressure of 455mmHg

Conceptual Introduction: The ideal gas law or general gas equation is an equation for ideal gas.

Equation as follows-

PV = nRT

Where, P = pressure of gas

V = volume of gas

N= No. of moles of gas (amount of substance in gas)

R = Universal gas constant

The gas constant R has a value 8.314J/mole Kelvin

T = Temperature in Kelvin

T_(Kelvin) = T_(Celsius) + 273.15 (Conversion from kelvin to Celsius)

Molar mass of substance are given in periodic table. Element molar mass is in gram/mole. We can determine chemical amount of known substance in moles by dividing the substance mass in grams by substance molar mass

Given:

Volume = 525 ml

Pressure = 455 mmHg

Mass = 0.226 grams

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Answer 2

Question

Chapter 11.7, Problem 11.60QAP

Interpretation Introduction

Interpretation: Temperature of 525 ml CO₂having mass of 0.226gram and pressure of 455mmHg

Conceptual Introduction: The ideal gas law or general gas equation is an equation for ideal gas.

Equation as follows-

PV = nRT

Where, P = pressure of gas

V = volume of gas

N= No. of moles of gas (amount of substance in gas)

R = Universal gas constant

The gas constant R has a value 8.314J/mole Kelvin

T = Temperature in Kelvin

T_(Kelvin) = T_(Celsius) + 273.15 (Conversion from kelvin to Celsius)

Molar mass of substance are given in periodic table. Element molar mass is in gram/mole. We can determine chemical amount of known substance in moles by dividing the substance mass in grams by substance molar mass

Given:

Volume = 525 ml

Pressure = 455 mmHg

Mass = 0.226 grams

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Answer 3

Question

Chapter 11.7, Problem 11.60QAP

Interpretation Introduction

Interpretation: Temperature of 525 ml CO₂having mass of 0.226gram and pressure of 455mmHg

Conceptual Introduction: The ideal gas law or general gas equation is an equation for ideal gas.

Equation as follows-

PV = nRT

Where, P = pressure of gas

V = volume of gas

N= No. of moles of gas (amount of substance in gas)

R = Universal gas constant

The gas constant R has a value 8.314J/mole Kelvin

T = Temperature in Kelvin

T_(Kelvin) = T_(Celsius) + 273.15 (Conversion from kelvin to Celsius)

Molar mass of substance are given in periodic table. Element molar mass is in gram/mole. We can determine chemical amount of known substance in moles by dividing the substance mass in grams by substance molar mass

Given:

Volume = 525 ml

Pressure = 455 mmHg

Mass = 0.226 grams

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Answer 4

Question

Chapter 11.7, Problem 11.60QAP

Interpretation Introduction

Interpretation: Temperature of 525 ml CO₂having mass of 0.226gram and pressure of 455mmHg

Conceptual Introduction: The ideal gas law or general gas equation is an equation for ideal gas.

Equation as follows-

PV = nRT

Where, P = pressure of gas

V = volume of gas

N= No. of moles of gas (amount of substance in gas)

R = Universal gas constant

The gas constant R has a value 8.314J/mole Kelvin

T = Temperature in Kelvin

T_(Kelvin) = T_(Celsius) + 273.15 (Conversion from kelvin to Celsius)

Molar mass of substance are given in periodic table. Element molar mass is in gram/mole. We can determine chemical amount of known substance in moles by dividing the substance mass in grams by substance molar mass

Given:

Volume = 525 ml

Pressure = 455 mmHg

Mass = 0.226 grams

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Answer 5

Chapter 11.7, Problem 11.60QAP

Interpretation Introduction

Interpretation: Temperature of 525 ml CO₂having mass of 0.226gram and pressure of 455mmHg

Conceptual Introduction: The ideal gas law or general gas equation is an equation for ideal gas.

Equation as follows-

PV = nRT

Where, P = pressure of gas

V = volume of gas

N= No. of moles of gas (amount of substance in gas)

R = Universal gas constant

The gas constant R has a value 8.314J/mole Kelvin

T = Temperature in Kelvin

T_(Kelvin) = T_(Celsius) + 273.15 (Conversion from kelvin to Celsius)

Molar mass of substance are given in periodic table. Element molar mass is in gram/mole. We can determine chemical amount of known substance in moles by dividing the substance mass in grams by substance molar mass

Given:

Volume = 525 ml

Pressure = 455 mmHg

Mass = 0.226 grams

Answer 6

Chapter 11.7, Problem 11.60QAP

Interpretation Introduction

Interpretation: Temperature of 525 ml CO₂having mass of 0.226gram and pressure of 455mmHg

Conceptual Introduction: The ideal gas law or general gas equation is an equation for ideal gas.

Equation as follows-

PV = nRT

Where, P = pressure of gas

V = volume of gas

N= No. of moles of gas (amount of substance in gas)

R = Universal gas constant

The gas constant R has a value 8.314J/mole Kelvin

T = Temperature in Kelvin

T_(Kelvin) = T_(Celsius) + 273.15 (Conversion from kelvin to Celsius)

Molar mass of substance are given in periodic table. Element molar mass is in gram/mole. We can determine chemical amount of known substance in moles by dividing the substance mass in grams by substance molar mass

Given:

Volume = 525 ml

Pressure = 455 mmHg

Mass = 0.226 grams

Answer 7

Chapter 11.7, Problem 11.60QAP

Interpretation Introduction

Interpretation: Temperature of 525 ml CO₂having mass of 0.226gram and pressure of 455mmHg

Conceptual Introduction: The ideal gas law or general gas equation is an equation for ideal gas.

Equation as follows-

PV = nRT

Where, P = pressure of gas

V = volume of gas

N= No. of moles of gas (amount of substance in gas)

R = Universal gas constant

The gas constant R has a value 8.314J/mole Kelvin

T = Temperature in Kelvin

T_(Kelvin) = T_(Celsius) + 273.15 (Conversion from kelvin to Celsius)

Molar mass of substance are given in periodic table. Element molar mass is in gram/mole. We can determine chemical amount of known substance in moles by dividing the substance mass in grams by substance molar mass

Given:

Volume = 525 ml

Pressure = 455 mmHg

Mass = 0.226 grams

Answer 8

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Answer 9

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Answer 10

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Answer 11

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