a)
Interpretation:
The actual product has to be identified.
Concept introduction:
Elimination reaction:An elimination reaction is removal of two substituents in a molecule and forms
E1 elimination:
E2 elimination:Alkyl halide forms an alkene from the abstraction of the proton from the β-carbon atom followed by elimination of the bromine in a single step.
b)
Interpretation:
The actual product has to be identified.
Concept introduction:
Elimination reaction:An elimination reaction is removal of two substituents in a molecule and forms alkene. An elimination reaction is one or two-step process which based on the mechanism when two substituents removed from the molecule in single step is called E2 reaction. When two substituents are removed from the molecule in two steps is called E1 reaction.
E1 elimination: Alkyl halide forms carbocation by the removal of bromine followed by the abstraction of the proton from the β-carbon atom in two steps which leads to the product as an alkene
E2 elimination:Alkyl halide forms an alkene from the abstraction of the proton from the β-carbon atom followed by elimination of the bromine in a single step.
c)
Interpretation:
The actual product has to be identified.
Concept introduction:
Elimination reaction:An elimination reaction is removal of two substituents in a molecule and forms alkene. An elimination reaction is one or two-step process which based on the mechanism when two substituents removed from the molecule in single step is called E2 reaction. When two substituents are removed from the molecule in two steps is called E1 reaction.
E1 elimination: Alkyl halide forms carbocation by the removal of bromine followed by the abstraction of the proton from the β-carbon atom in two steps which leads to the product as an alkene
E2 elimination:Alkyl halide forms an alkene from the abstraction of the proton from the β-carbon atom followed by elimination of the bromine in a single step.
Trending nowThis is a popular solution!
Chapter 11 Solutions
Organic Chemistry
- can you name the types of reactions of these then predict the products. And can you make sure the recations are balanced?arrow_forwardIn parts 1 and 2 draw the two organic products of this reaction, showing any nonzero formal charges. Then, in part 3 answer the question regarding purification of the reaction mixture. 1. Draw the product with the higher molecular weight here: 2. Draw the product with the lower molecular weight here:arrow_forwardPropose a detailed mechanism for the reaction below (in the attached picture), showing the structure of thestable intermediate and using curved arrows to indicate electron flow in each steparrow_forward