Chemistry for Today: General, Organic, and Biochemistry
Chemistry for Today: General, Organic, and Biochemistry
9th Edition
ISBN: 9781305960060
Author: Spencer L. Seager, Michael R. Slabaugh, Maren S. Hansen
Publisher: Cengage Learning
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Chapter 12, Problem 12.1E
Interpretation Introduction

Interpretation:

The definition of an unsaturated hydrocarbon is to be stated.

Concept introduction:

Hydrocarbons are the organic compounds that contain carbon and hydrogen atoms. Hydrocarbons are classified into two groups, saturated hydrocarbon and unsaturated hydrocarbon.

Expert Solution & Answer
Check Mark

Answer to Problem 12.1E

Unsaturated hydrocarbons contain either double bond or triple bond between the adjacent carbon atoms. They contain high percentage of carbon.

Explanation of Solution

In unsaturated hydrocarbons, there is either double bond or triple bond present between the adjacent carbon atoms. They contain high percentage of carbon. Unsaturated hydrocarbons are further classified into alkene and alkyne.

The adjacent carbon atoms in alkene are connected through a double bond while the adjacent carbon atoms in alkyne are connected through a triple bond. The general molecular formula for alkene and alkyne is CnH2n and CnH2n2 respectively, where n represents the natural number.

Conclusion

Unsaturated hydrocarbons contain either double bond or triple bond between the adjacent carbon atoms. They contain high percentage of carbon.

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Chapter 12 Solutions

Chemistry for Today: General, Organic, and Biochemistry

Ch. 12 - Prob. 12.11ECh. 12 - Prob. 12.12ECh. 12 - What type of hybridized orbital is present on...Ch. 12 - What type of orbital overlaps to form a pi bond in...Ch. 12 - Prob. 12.15ECh. 12 - Explain the difference between geometric and...Ch. 12 - Draw structural formulas and give IUPAC names for...Ch. 12 - Prob. 12.18ECh. 12 - Which of the following alkenes can exist as...Ch. 12 - Draw structural formulas for the following:...Ch. 12 - Prob. 12.21ECh. 12 - In what ways are the physical properties of...Ch. 12 - Prob. 12.23ECh. 12 - Prob. 12.24ECh. 12 - Complete the following reactions. Where more than...Ch. 12 - Prob. 12.26ECh. 12 - Prob. 12.27ECh. 12 - What reagents would you use to prepare each of the...Ch. 12 - What is an important commercial application of...Ch. 12 - Prob. 12.30ECh. 12 - Terpin hydrate is used medicinally as an...Ch. 12 - Prob. 12.32ECh. 12 - Prob. 12.33ECh. 12 - Prob. 12.34ECh. 12 - Prob. 12.35ECh. 12 - Much of todays plumbing in newly built homes is...Ch. 12 - Prob. 12.37ECh. 12 - What type of hybridized orbital is present on...Ch. 12 - How many sigma bonds and how many pi bonds make up...Ch. 12 - Prob. 12.40ECh. 12 - Explain why geometric isomerism is not possible in...Ch. 12 - Give the common name and major uses of the...Ch. 12 - Describe the physical and chemical properties of...Ch. 12 - Prob. 12.44ECh. 12 - Prob. 12.45ECh. 12 - Prob. 12.46ECh. 12 - Prob. 12.47ECh. 12 - Prob. 12.48ECh. 12 - Limonene, which is present in citrus peelings, has...Ch. 12 - A disubstituted cycloalkane such as a exhibits...Ch. 12 - Prob. 12.51ECh. 12 - Prob. 12.52ECh. 12 - Give an IUPAC name for the following as...Ch. 12 - Give an IUPAC name for the following as...Ch. 12 - Name the following compounds, using the prefixed...Ch. 12 - Name the following compounds, using the prefixed...Ch. 12 - Name the following by numbering the benzene ring....Ch. 12 - Name the following by numbering the benzene ring....Ch. 12 - Prob. 12.59ECh. 12 - Write structural formulas for the following:...Ch. 12 - Prob. 12.61ECh. 12 - Prob. 12.62ECh. 12 - Prob. 12.63ECh. 12 - Prob. 12.64ECh. 12 - Prob. 12.65ECh. 12 - Prob. 12.66ECh. 12 - Prob. 12.67ECh. 12 - Prob. 12.68ECh. 12 - Prob. 12.69ECh. 12 - Prob. 12.70ECh. 12 - Prob. 12.71ECh. 12 - Prob. 12.72ECh. 12 - Prob. 12.73ECh. 12 - Prob. 12.74ECh. 12 - Prob. 12.75ECh. 12 - Prob. 12.76ECh. 12 - Prob. 12.77ECh. 12 - Prob. 12.78ECh. 12 - Prob. 12.79ECh. 12 - Prob. 12.80ECh. 12 - Prob. 12.81ECh. 12 - Prob. 12.82ECh. 12 - Prob. 12.83ECh. 12 - The compound CH2=CHCH2CH2CH3 is an example of: a....Ch. 12 - The correct structural for ethyne is: a. HC=CH b....Ch. 12 - Prob. 12.86E
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