(a) Interpretation: To draw the organic products formed when 4-octyne is treated with given reagent. Concept introduction: Reduction of an alkyne by the addition of H 2 to one or both of the pi bonds. When an alkyne is treated with two or more equivalents of H 2 and using the Pd catalyst, reduction of both the pi bonds occurs. Syn addition of H 2 to forms a cis alkene product and then form an alkane . Four new C-H bonds are formed.

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Answer 1

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Definition Definition Organic compounds that have a carbonyl group, C=O, as their functional group. The carbonyl group in aldehydes is placed at the end of the molecular structure, which means the C=O is attached to one hydrogen atom and an alkyl group or a benzene ring. Just like all the other homologous series in organic chemistry, the naming of aldehydes uses the suffix “-al”. The general molecular formula is C n H 2n O.

Chapter 12, Problem 12.39P

Interpretation Introduction

(a)

Interpretation:

To draw the organic products formed when 4-octyne is treated with given reagent.

Concept introduction:

Reduction of an alkyne by the addition of H₂ to one or both of the pi bonds. When an alkyne is treated with two or more equivalents of H₂ and using the Pd catalyst, reduction of both the pi bonds occurs. Syn addition of H₂ to forms a cis alkene product and then form an alkane. Four new C-H bonds are formed.

Interpretation Introduction

(b)

Interpretation:

To draw the organic products formed when 4-octyne is treated with given reagent.

Concept introduction:

Reduction of an alkyne by the addition of H₂ to one or both of the pi bonds. When an alkyne is treated with two or more equivalents of H₂ and using the Pd catalyst, reduction of both the pi bonds occurs. Thus Palladium metal is too active a catalyst to allow the hydrogenation of an alkyne to stop after one equivalent of H₂. Thus Lindlar catalyst is used to reduce the triple to double bond.

Interpretation Introduction

(c)

Interpretation:

To draw the organic products formed when 4-octyne is treated with given reagent.

Concept introduction:

Reduction of an alkyne by the addition of H₂ to one or both of the pi bonds. When an alkyne is treated with two or more equivalents of H₂ and using the Pd catalyst, reduction of both the pi bonds occurs. Using the Pd catalyst form the cis alkene or alkane product but not the trans alkene. Thus another reagent is used to reduce the triple to double in a trans form.

Interpretation Introduction

(d)

Interpretation:

To draw the organic products formed when 4-octyne is treated with given reagent.

Concept introduction:

Oxidative cleavage of an alkene breaks both the sigma and pi bonds of the double bond to form two carbonyl groups. Depending on the number of R groups bonded to the double bond, oxidative cleavage yields either ketones or aldehydes. But in the alkyne it is different. Alkynes undergoes Oxidative cleavage to form the two acids.

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Answer 2

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Definition Definition Organic compounds that have a carbonyl group, C=O, as their functional group. The carbonyl group in aldehydes is placed at the end of the molecular structure, which means the C=O is attached to one hydrogen atom and an alkyl group or a benzene ring. Just like all the other homologous series in organic chemistry, the naming of aldehydes uses the suffix “-al”. The general molecular formula is C n H 2n O.

Chapter 12, Problem 12.39P

Interpretation Introduction

(a)

Interpretation:

To draw the organic products formed when 4-octyne is treated with given reagent.

Concept introduction:

Reduction of an alkyne by the addition of H₂ to one or both of the pi bonds. When an alkyne is treated with two or more equivalents of H₂ and using the Pd catalyst, reduction of both the pi bonds occurs. Syn addition of H₂ to forms a cis alkene product and then form an alkane. Four new C-H bonds are formed.

Interpretation Introduction

(b)

Interpretation:

To draw the organic products formed when 4-octyne is treated with given reagent.

Concept introduction:

Reduction of an alkyne by the addition of H₂ to one or both of the pi bonds. When an alkyne is treated with two or more equivalents of H₂ and using the Pd catalyst, reduction of both the pi bonds occurs. Thus Palladium metal is too active a catalyst to allow the hydrogenation of an alkyne to stop after one equivalent of H₂. Thus Lindlar catalyst is used to reduce the triple to double bond.

Interpretation Introduction

(c)

Interpretation:

To draw the organic products formed when 4-octyne is treated with given reagent.

Concept introduction:

Reduction of an alkyne by the addition of H₂ to one or both of the pi bonds. When an alkyne is treated with two or more equivalents of H₂ and using the Pd catalyst, reduction of both the pi bonds occurs. Using the Pd catalyst form the cis alkene or alkane product but not the trans alkene. Thus another reagent is used to reduce the triple to double in a trans form.

Interpretation Introduction

(d)

Interpretation:

To draw the organic products formed when 4-octyne is treated with given reagent.

Concept introduction:

Oxidative cleavage of an alkene breaks both the sigma and pi bonds of the double bond to form two carbonyl groups. Depending on the number of R groups bonded to the double bond, oxidative cleavage yields either ketones or aldehydes. But in the alkyne it is different. Alkynes undergoes Oxidative cleavage to form the two acids.

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Answer 3

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Definition Definition Organic compounds that have a carbonyl group, C=O, as their functional group. The carbonyl group in aldehydes is placed at the end of the molecular structure, which means the C=O is attached to one hydrogen atom and an alkyl group or a benzene ring. Just like all the other homologous series in organic chemistry, the naming of aldehydes uses the suffix “-al”. The general molecular formula is C n H 2n O.

Chapter 12, Problem 12.39P

Interpretation Introduction

(a)

Interpretation:

To draw the organic products formed when 4-octyne is treated with given reagent.

Concept introduction:

Reduction of an alkyne by the addition of H₂ to one or both of the pi bonds. When an alkyne is treated with two or more equivalents of H₂ and using the Pd catalyst, reduction of both the pi bonds occurs. Syn addition of H₂ to forms a cis alkene product and then form an alkane. Four new C-H bonds are formed.

Interpretation Introduction

(b)

Interpretation:

To draw the organic products formed when 4-octyne is treated with given reagent.

Concept introduction:

Reduction of an alkyne by the addition of H₂ to one or both of the pi bonds. When an alkyne is treated with two or more equivalents of H₂ and using the Pd catalyst, reduction of both the pi bonds occurs. Thus Palladium metal is too active a catalyst to allow the hydrogenation of an alkyne to stop after one equivalent of H₂. Thus Lindlar catalyst is used to reduce the triple to double bond.

Interpretation Introduction

(c)

Interpretation:

To draw the organic products formed when 4-octyne is treated with given reagent.

Concept introduction:

Reduction of an alkyne by the addition of H₂ to one or both of the pi bonds. When an alkyne is treated with two or more equivalents of H₂ and using the Pd catalyst, reduction of both the pi bonds occurs. Using the Pd catalyst form the cis alkene or alkane product but not the trans alkene. Thus another reagent is used to reduce the triple to double in a trans form.

Interpretation Introduction

(d)

Interpretation:

To draw the organic products formed when 4-octyne is treated with given reagent.

Concept introduction:

Oxidative cleavage of an alkene breaks both the sigma and pi bonds of the double bond to form two carbonyl groups. Depending on the number of R groups bonded to the double bond, oxidative cleavage yields either ketones or aldehydes. But in the alkyne it is different. Alkynes undergoes Oxidative cleavage to form the two acids.

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Answer 4

Question

Definition Definition Organic compounds that have a carbonyl group, C=O, as their functional group. The carbonyl group in aldehydes is placed at the end of the molecular structure, which means the C=O is attached to one hydrogen atom and an alkyl group or a benzene ring. Just like all the other homologous series in organic chemistry, the naming of aldehydes uses the suffix “-al”. The general molecular formula is C n H 2n O.

Chapter 12, Problem 12.39P

Interpretation Introduction

(a)

Interpretation:

To draw the organic products formed when 4-octyne is treated with given reagent.

Concept introduction:

Reduction of an alkyne by the addition of H₂ to one or both of the pi bonds. When an alkyne is treated with two or more equivalents of H₂ and using the Pd catalyst, reduction of both the pi bonds occurs. Syn addition of H₂ to forms a cis alkene product and then form an alkane. Four new C-H bonds are formed.

Interpretation Introduction

(b)

Interpretation:

To draw the organic products formed when 4-octyne is treated with given reagent.

Concept introduction:

Reduction of an alkyne by the addition of H₂ to one or both of the pi bonds. When an alkyne is treated with two or more equivalents of H₂ and using the Pd catalyst, reduction of both the pi bonds occurs. Thus Palladium metal is too active a catalyst to allow the hydrogenation of an alkyne to stop after one equivalent of H₂. Thus Lindlar catalyst is used to reduce the triple to double bond.

Interpretation Introduction

(c)

Interpretation:

To draw the organic products formed when 4-octyne is treated with given reagent.

Concept introduction:

Reduction of an alkyne by the addition of H₂ to one or both of the pi bonds. When an alkyne is treated with two or more equivalents of H₂ and using the Pd catalyst, reduction of both the pi bonds occurs. Using the Pd catalyst form the cis alkene or alkane product but not the trans alkene. Thus another reagent is used to reduce the triple to double in a trans form.

Interpretation Introduction

(d)

Interpretation:

To draw the organic products formed when 4-octyne is treated with given reagent.

Concept introduction:

Oxidative cleavage of an alkene breaks both the sigma and pi bonds of the double bond to form two carbonyl groups. Depending on the number of R groups bonded to the double bond, oxidative cleavage yields either ketones or aldehydes. But in the alkyne it is different. Alkynes undergoes Oxidative cleavage to form the two acids.

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Answer 5

Chapter 12, Problem 12.39P

Interpretation Introduction

(a)

Interpretation:

To draw the organic products formed when 4-octyne is treated with given reagent.

Concept introduction:

Reduction of an alkyne by the addition of H₂ to one or both of the pi bonds. When an alkyne is treated with two or more equivalents of H₂ and using the Pd catalyst, reduction of both the pi bonds occurs. Syn addition of H₂ to forms a cis alkene product and then form an alkane. Four new C-H bonds are formed.

Interpretation Introduction

(b)

Interpretation:

To draw the organic products formed when 4-octyne is treated with given reagent.

Concept introduction:

Reduction of an alkyne by the addition of H₂ to one or both of the pi bonds. When an alkyne is treated with two or more equivalents of H₂ and using the Pd catalyst, reduction of both the pi bonds occurs. Thus Palladium metal is too active a catalyst to allow the hydrogenation of an alkyne to stop after one equivalent of H₂. Thus Lindlar catalyst is used to reduce the triple to double bond.

Interpretation Introduction

(c)

Interpretation:

To draw the organic products formed when 4-octyne is treated with given reagent.

Concept introduction:

Reduction of an alkyne by the addition of H₂ to one or both of the pi bonds. When an alkyne is treated with two or more equivalents of H₂ and using the Pd catalyst, reduction of both the pi bonds occurs. Using the Pd catalyst form the cis alkene or alkane product but not the trans alkene. Thus another reagent is used to reduce the triple to double in a trans form.

Interpretation Introduction

(d)

Interpretation:

To draw the organic products formed when 4-octyne is treated with given reagent.

Concept introduction:

Oxidative cleavage of an alkene breaks both the sigma and pi bonds of the double bond to form two carbonyl groups. Depending on the number of R groups bonded to the double bond, oxidative cleavage yields either ketones or aldehydes. But in the alkyne it is different. Alkynes undergoes Oxidative cleavage to form the two acids.

Answer 6

Chapter 12, Problem 12.39P

Interpretation Introduction

(a)

Interpretation:

To draw the organic products formed when 4-octyne is treated with given reagent.

Concept introduction:

Reduction of an alkyne by the addition of H₂ to one or both of the pi bonds. When an alkyne is treated with two or more equivalents of H₂ and using the Pd catalyst, reduction of both the pi bonds occurs. Syn addition of H₂ to forms a cis alkene product and then form an alkane. Four new C-H bonds are formed.

Answer 7

Chapter 12, Problem 12.39P

Interpretation Introduction

(a)

Interpretation:

To draw the organic products formed when 4-octyne is treated with given reagent.

Concept introduction:

Reduction of an alkyne by the addition of H₂ to one or both of the pi bonds. When an alkyne is treated with two or more equivalents of H₂ and using the Pd catalyst, reduction of both the pi bonds occurs. Syn addition of H₂ to forms a cis alkene product and then form an alkane. Four new C-H bonds are formed.

Answer 8

Interpretation Introduction

(b)

Interpretation:

To draw the organic products formed when 4-octyne is treated with given reagent.

Concept introduction:

Reduction of an alkyne by the addition of H₂ to one or both of the pi bonds. When an alkyne is treated with two or more equivalents of H₂ and using the Pd catalyst, reduction of both the pi bonds occurs. Thus Palladium metal is too active a catalyst to allow the hydrogenation of an alkyne to stop after one equivalent of H₂. Thus Lindlar catalyst is used to reduce the triple to double bond.

Answer 9

Interpretation Introduction

(b)

Interpretation:

To draw the organic products formed when 4-octyne is treated with given reagent.

Concept introduction:

Reduction of an alkyne by the addition of H₂ to one or both of the pi bonds. When an alkyne is treated with two or more equivalents of H₂ and using the Pd catalyst, reduction of both the pi bonds occurs. Thus Palladium metal is too active a catalyst to allow the hydrogenation of an alkyne to stop after one equivalent of H₂. Thus Lindlar catalyst is used to reduce the triple to double bond.

Answer 10

Interpretation Introduction

(c)

Interpretation:

To draw the organic products formed when 4-octyne is treated with given reagent.

Concept introduction:

Reduction of an alkyne by the addition of H₂ to one or both of the pi bonds. When an alkyne is treated with two or more equivalents of H₂ and using the Pd catalyst, reduction of both the pi bonds occurs. Using the Pd catalyst form the cis alkene or alkane product but not the trans alkene. Thus another reagent is used to reduce the triple to double in a trans form.

Answer 11

Interpretation Introduction

(c)

Interpretation:

To draw the organic products formed when 4-octyne is treated with given reagent.

Concept introduction:

Reduction of an alkyne by the addition of H₂ to one or both of the pi bonds. When an alkyne is treated with two or more equivalents of H₂ and using the Pd catalyst, reduction of both the pi bonds occurs. Using the Pd catalyst form the cis alkene or alkane product but not the trans alkene. Thus another reagent is used to reduce the triple to double in a trans form.

Answer 12

Interpretation Introduction

(d)

Interpretation:

To draw the organic products formed when 4-octyne is treated with given reagent.

Concept introduction:

Oxidative cleavage of an alkene breaks both the sigma and pi bonds of the double bond to form two carbonyl groups. Depending on the number of R groups bonded to the double bond, oxidative cleavage yields either ketones or aldehydes. But in the alkyne it is different. Alkynes undergoes Oxidative cleavage to form the two acids.

Answer 13

Interpretation Introduction

(d)

Interpretation:

To draw the organic products formed when 4-octyne is treated with given reagent.

Concept introduction:

Oxidative cleavage of an alkene breaks both the sigma and pi bonds of the double bond to form two carbonyl groups. Depending on the number of R groups bonded to the double bond, oxidative cleavage yields either ketones or aldehydes. But in the alkyne it is different. Alkynes undergoes Oxidative cleavage to form the two acids.

Answer 14

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Answer 17

Ch. 12 - Prob. 12.1P Ch. 12 - Prob. 12.2P Ch. 12 - Prob. 12.3P Ch. 12 - Prob. 12.4P Ch. 12 - Prob. 12.5P Ch. 12 - Given that syn addition of H2 occurs from both...Ch. 12 - Compound Molecular formula before...Ch. 12 - Draw the products formed when triacylglycerol A is...Ch. 12 - Prob. 12.9P Ch. 12 - Prob. 12.10P

Solution Summary: The author explains how to draw the organic products formed when 4-octyne is treated with given reagent.

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