Principles of Geotechnical Engineering (MindTap Course List)
9th Edition
ISBN: 9781305970939
Author: Braja M. Das, Khaled Sobhan
Publisher: Cengage Learning
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Chapter 12, Problem 12.3P
To determine
Find the shear force required to cause failure.
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1 .For a direct shear test on a dry sand, the following are given:• Specimen size: 75 mm 75 mm 30 mm (height)• Normal stress: 200 kN/m2• Shear stress at failure: 175 kN/m2a. Determine the angle of friction, f b. For a normal stress of 150 kN/m2, what shear force is required to cause failure?in the specime
The following data are given for a direct shear test conducted on dry sand:- Specimen dimensions: 75 mm X 75 mm X 30 mm (height)- Normal stress: 200 kN/m2- Shear stress at failure: 175 kN/m2a) Determine the angle of friction,b) For a normal stress of 150 kN/m2, what shear force is required to cause failure?
A direct shear test, when conducted on a remolded sample of sand, gave the following observations at the time of failure: Normal load = 288 N; shear load = 173 N. The cross-sectional area of the sample = 36 cm2. Determine the minor principal stress in kPa. Show diagram
Chapter 12 Solutions
Principles of Geotechnical Engineering (MindTap Course List)
Ch. 12 - Prob. 12.1PCh. 12 - Prob. 12.2PCh. 12 - Prob. 12.3PCh. 12 - Prob. 12.4PCh. 12 - Prob. 12.5PCh. 12 - Prob. 12.6PCh. 12 - Prob. 12.7PCh. 12 - Prob. 12.8PCh. 12 - Prob. 12.9PCh. 12 - Prob. 12.10P
Ch. 12 - Prob. 12.11PCh. 12 - Prob. 12.12PCh. 12 - Prob. 12.13PCh. 12 - Following are the results of...Ch. 12 - Prob. 12.15PCh. 12 - Prob. 12.16PCh. 12 - Prob. 12.17PCh. 12 - Prob. 12.18PCh. 12 - Prob. 12.19PCh. 12 - Prob. 12.20PCh. 12 - Prob. 12.21PCh. 12 - Prob. 12.22PCh. 12 - Prob. 12.23PCh. 12 - Prob. 12.24PCh. 12 - Prob. 12.1CTP
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- A direct shear test, when conducted on a remolded sample of sand, gave the following observations at the time of failure: Normal load = 288 N; shear load = 173 N. The cross-sectional area of the sample = 36 cm2. Determine the minor principal stress in kPa.arrow_forwardFollowing data are given for a direct shear test conducted on dry sand: Cylindrical specimen dimensions: diameter = 50 mm and height = 25 mm Normal stress: 0.15 N/mm2 Shear force at failure: 276 N Determine the angle of friction of this soil. Normal Stress = 0.15 N/mm2 Shear Force = 276 N Shear Force = 276 Narrow_forwardFollowing data are given for a direct shear test conducted on dry silty sand:Specimen dimensions: diameter = 71 mm; height = 25 mmNormal stress: 150 kN/m2Shear force at failure: 276 Narrow_forward
- After conducting a tri-axial test on a sand sample, the normal and shearing stress on the failure plane at failure was found to be 475kPa and 350kPa, respectively. Which of the following most nearly gives the plunger stress?arrow_forwardA direct shear test was conducted on a specimen of dry sand with a normal stress of 200 kN/m2. Failure occurred at a shear stress of 175 kN/m2. The size of the specimen testedwas 75 mm × 75 mm × 30 mm (height). Determine the angle of friction, . For a normal stress of 150 kN/m2, what shear force would be required to cause failure of the specimen?arrow_forwardA direct shear test, when conducted on a remolded sample of sand, gave the following observations at the time of failure: Normal load = 288 N; shear load = 173 N. The cross-sectional area of the sample = 36 cm2. Determine the major principal stress in kPa. a.174.6 b.246.5 c.163.5 d.146.9arrow_forward
- Can TRIAXIAL TESTS be performed on sand samples? Briefly explain. The results of an undrained triaxial test on a clay soil sample are given in table below Cell Pressure (kN/m2) 200 400 600 Additional Axial Load at Failure (N) 342 388 465 Each sample, originally 76mm long and 38mm in diameter, experienced a vertical deformation of 5.1mm. Evaluate the stress at failure for each cell pressure given in table above. Draw Mohr Circles and determine the shear strength parameters of the soil.arrow_forwardThe size of a sand specimen in a direct shear test was 50 mm x 50 mm x 30 mm (height). It is known that, for the sand, tan phi prime = 0.65/e (where e = void ratio) and the specific gravity of soil solids Gs = 2.65. During the test, a normal stress of 140 kN/m^2 was applied. Failure occured at a shear stress of 105 kN/m^2. What was the mass of the sand specimen?arrow_forwardA direct shear test, when conducted on a remolded sample of sand, gave the following observations at the time of failure: Normal load = 288 N; shear load = 173 N. The cross-sectional area of the sample = 36 cm2. Determine the minor principal stress in kPa. Pls include fbd.arrow_forward
- he following results were obtained from a direct shear test conducted on pure sand: Sample height and diameter = 30 mm and 75 mm respectively. Normal stress = 100 kN/m2 Shear force at failure = 185 N a) Determine the angle of friction for the soil. Round off to one decimal i.e. 99.5! b) What would be the shear force (in N) at failure if the normal stress is 175 kN/m2? Round off to the nearest figure i.e. 300.55 to 301! c) What would be the principal stress at failure? Consider a and barrow_forward: In a tri-axial test of a silty soil, the sample failed at normal stress of 475 kPa and a shear stress of 350 kPa. Which of the following gives the angle of internal friction? Compute the angle that the failure plane makes with the x-axis. Compute the maximum failure stress.arrow_forwardIn a tri-axial test of normally consolidated clay, the sample subjected to chamber confining pressure of 250 kPa and failed when deviator stress is 350 kPa. Which of the following gives the angle of internal friction? Which of the following gives the shear stress at failure? Which of the following gives the effective normal stress at maximum shear?arrow_forward
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