BIOLOGY 12E CONNECT ACCESS CARD
12th Edition
ISBN: 9781264938513
Author: Raven
Publisher: MCG
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Chapter 12, Problem 1S
z1. Create a Punnett square for the following crosses and use this to predict
a. A monohybrid cross between individuals with the genotype Aa and Aa
b. A dihybrid cross between two individuals with the genotype AaBb
c. A dihybrid cross between individuals with the genotype AaBb and aabb
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A. Theoretical: The Punnett square will be used to examine the theoretical outcome of possible monohybrid
crosses.
1. The first cross is between a Homozygous dominant parent (PP), and a Homozygous recessive or just simply
say recessive parent (pp):
a. Fill in the Punnett square. Each box represents a genotype possibility for an offspring.
b. Place the allele donated by each parent in the corresponding box. Now list the possible genotypes and
their corresponding phenotype.
c. If an individual's genotype is heterozygous, the dominant trait will be expressed in the phenotype.
Give the percent possible for the phenotypes.
P
Genotype:
p
Phenotype:
Phenotype % probable:
1| Page
2. Cross between a Homozygous dominant parent (PP) and a Heterozygous parent (Pp). Fill in as in step one.
3. Cross between a Heterozygous parent (Pp), and another Heterozygous parent (Pp). Fill-in as before.
4. Test cross: A test cross is between a recessive parent (pp), and a Heterozygous parent (Pp). Again, fill-in…
a. A variety of fruit bearing plants with the dominant allele A produces cream-coloured fruit while aa plants produce pink or red fruit. Red fruit is produced if allele B is present, and pink fruit is produced when the genotype is bb. What are the expected F2 phenotypes and proportions from intercrossing the F1 offspring of a cross between two plants with the genotype AAbb and aaBB? b. A certain animal can have brown, red, black or gray fur. Assume that fur colour is controlled by a single gene with multiple alleles in a dominance series where black (B1) > brown (B2) > red (B3) > gray (B4). Give the genotypes of two phenotypically different heterozygotes that when crossed produce offspring with the phenotypic ratio of 1 red : 2 black : 1 brown.
1. Genes A and E are independent. Two individuals with the genotypes AaEe x aaEe are
crossed (upper case = dominant, lowercase = recessive).
a. Draw your Punnett square(s) in the space below.
b. On each line, show your calculations and the final answer. ie 1/2 x 1/2 = 1/4
What is the probability of these two individuals having the following:
an offspring with the phenotype aE ?
an offspring that is heterozygous for both traits?
an male offspring with the genotype AaEE ?
Chapter 12 Solutions
BIOLOGY 12E CONNECT ACCESS CARD
Ch. 12.1 - Prob. 1LOCh. 12.1 - Explain the advantages of Mendels experimental...Ch. 12.2 - Evaluate the outcome of a monohybrid cross.Ch. 12.2 - Explain Mendels Principle of Segregation.Ch. 12.2 - Compare the segregation of alleles with the...Ch. 12.3 - Evaluate the outcome of a dihybrid cross.Ch. 12.3 - Explain Mendels Principle of Independent...Ch. 12.3 - Compare the segregation of alleles for different...Ch. 12.4 - Prob. 1LOCh. 12.4 - Prob. 2LO
Ch. 12.5 - Interpret data from testcrosses to infer unknown...Ch. 12.6 - Describe how assumptions in Mendels model result...Ch. 12.6 - Prob. 2LOCh. 12.6 - Explain the genetic basis for observed alterations...Ch. 12 - Inquiry question What confounding problems could...Ch. 12 - Prob. 2IQCh. 12 - Prob. 1DACh. 12 - Prob. 2DACh. 12 - Prob. 3DACh. 12 - What property distinguished Mendels investigation...Ch. 12 - The F1 generation of the monohybrid cross purple...Ch. 12 - The F1 plants from the previous question are...Ch. 12 - In a cross of Aa Bb cc X Aa Bb Cc, what is the...Ch. 12 - An organisms __________ is/are determined by its...Ch. 12 - Phenotypes like height in humans, which show a...Ch. 12 - Japanese four oclocks that are red and tall are...Ch. 12 - If the two genes in the previous question showed...Ch. 12 - What is the probability of obtaining an individual...Ch. 12 - Prob. 4ACh. 12 - Prob. 5ACh. 12 - Mendels model assumes that each trait is...Ch. 12 - z1. Create a Punnett square for the following...Ch. 12 - Explain how the events of meiosis can explain both...Ch. 12 - Prob. 3SCh. 12 - In mammals, a variety of genes affect coat color....
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- Bronze coloured turkey is controlled by a dominant allele, B. Red coloured turkey is homozygous for a recessive allele bb. Dominant gene N produce normal feather and recessive genotype produce ‘hairy’ feather nn. In a cross between homozygous bronzed coloured turkey with ‘hairy’ feather and homozygous red coloured turkey with normal feather. What are the ratios of F2 progeny with Bbnn genotypes? (I want to check if what i'm doing is correct)arrow_forwardPurple flowers are dominant to white flowers. Identify the phenotypefor the following genotype Ff, FF, ff and determine if the genotype is heterozygous or homozygous. * For each row, you should select two columns. Purple flowers White flowers Heterozygous Homozygous Ff FF ff Brown eyes are dominant to blue eyes. Identify the phenotype for the following genotype BB, Bb, bb and determine if the genotype is heterozygous or homozygous. * 口 ロ口arrow_forwarda. 1 dominant allele will contribute 120/10 = 12 cm to the base height of the plant.b. The height of the parent plant 1 Genotype of the parent plant 1 – D1D1D2D2D3D3d4d4d5d5 The height of the parent plant 2 Genotype of the parent plant 2 – d1d1d2d2d3d3D4D4D5D5Contributing alleles – D4D4D5D5. The height of the plant without any contributing alleles would be 80 cm. The plant with genotype d1d1d2d2d3d3D4D4D5D5 has 4 contributing allele each of which contributes 12 cm to the base. Hence, the height of the plant with genotype d1d1d2d2d3d3D4D4D5D5 would be 80 + 12 + 12 + 12 + 12 = 128 cm. c. Parents – D1D1D2D2D3D3d4d4d5d5 × d1d1d2d2d3d3D4D4D5D5 Gametes – D1D2D3d4d5 × d1d2d3D4D5 F1 generation – D1d1D2d2D3d3D4d4D5d5 The height of the plants of F1 generation = 80 + 12 + 12 + 12 + 12 + 12 = 140 cm Hence, Genotype of the F1 = D1d1D2d2D3d3D4d4D5d5 Phenotype of…arrow_forward
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