The Practice of Statistics for AP - 4th Edition
The Practice of Statistics for AP - 4th Edition
4th Edition
ISBN: 9781429245593
Author: Starnes, Daren S., Yates, Daniel S., Moore, David S.
Publisher: Macmillan Higher Education
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Chapter 12.2, Problem 37E

(a)

To determine

To make a reasonable accurate scatterplot of the data using the time as the explanatory variable and describe what you see.

(a)

Expert Solution
Check Mark

Explanation of Solution

Now, the scatterplot of the data using the time as the explanatory variable is as follows:

  The Practice of Statistics for AP - 4th Edition, Chapter 12.2, Problem 37E

Thus, by looking at the scatterplot we can see that,

Direction: Negative, because the scatterplot slopes downwards.

Form: Curved, because the points do not lie on a straight line.

Strength: Strong, because all points lie very close together in the same pattern.

We also note an outlier in the upper left corner of the scatterplot.

(b)

To determine

To explain why it would be reasonable to use an exponential model to describe the relationship between the count of bacteria and time.

(b)

Expert Solution
Check Mark

Explanation of Solution

Now, the data of the count of bacteria and the time is given in the question. Thus, we can say that it would be reasonable to use an exponential model to describe the relationship between the count of bacteria and time because the corresponding scatterplot has a roughly linear pattern with no notable strong outliers as we can see in the scatterplot in the part (a).

(c)

To determine

To give the equation of the least squares regression line.

(c)

Expert Solution
Check Mark

Answer to Problem 37E

  lny^=5.973160.218425t .

Explanation of Solution

Now, it is given that t is the time and y is the count of bacteria. Thus the transformation is the natural logarithm of the count as lny .

Thus, as we know that the general equation of the regression line is as follows:

  lny^=a+bt

And the slope and the constant given in the computer output is as:

  a=5.97316b=0.218425

Thus, the regression line is as follows:

  lny^=a+btlny^=5.973160.218425t

(d)

To determine

To use your model to predict the number of surviving bacteria after 17 minutes and explain do you expect this prediction to be too high, too low or about right.

(d)

Expert Solution
Check Mark

Answer to Problem 37E

  y^=9.58247 and it is about right.

Explanation of Solution

Now, the regression line is as follows:

  lny^=a+btlny^=5.973160.218425t

Thus, we will evaluate the equation as:

  lny^=a+btlny^=5.973160.218425tlny^=5.973160.218425(17)lny^=2.259935y^=e2.259935=9.58247

Since the pattern of the residual in the residual plot is centered at zero we expect the predict to be about right.

Chapter 12 Solutions

The Practice of Statistics for AP - 4th Edition

Ch. 12.1 - Prob. 7ECh. 12.1 - Prob. 8ECh. 12.1 - Prob. 9ECh. 12.1 - Prob. 10ECh. 12.1 - Prob. 11ECh. 12.1 - Prob. 12ECh. 12.1 - Prob. 13ECh. 12.1 - Prob. 14ECh. 12.1 - Prob. 15ECh. 12.1 - Prob. 16ECh. 12.1 - Prob. 17ECh. 12.1 - Prob. 18ECh. 12.1 - Prob. 19ECh. 12.1 - Prob. 20ECh. 12.1 - Prob. 21ECh. 12.1 - Prob. 22ECh. 12.1 - Prob. 23ECh. 12.1 - Prob. 24ECh. 12.1 - Prob. 25ECh. 12.1 - Prob. 26ECh. 12.1 - Prob. 27ECh. 12.1 - Prob. 28ECh. 12.1 - Prob. 29ECh. 12.1 - Prob. 30ECh. 12.1 - Prob. 31ECh. 12.1 - Prob. 32ECh. 12.2 - Prob. 1.1CYUCh. 12.2 - Prob. 1.2CYUCh. 12.2 - Prob. 1.3CYUCh. 12.2 - Prob. 1.4CYUCh. 12.2 - Prob. 33ECh. 12.2 - Prob. 34ECh. 12.2 - Prob. 35ECh. 12.2 - Prob. 36ECh. 12.2 - Prob. 37ECh. 12.2 - Prob. 38ECh. 12.2 - Prob. 39ECh. 12.2 - Prob. 40ECh. 12.2 - Prob. 41ECh. 12.2 - Prob. 42ECh. 12.2 - Prob. 43ECh. 12.2 - Prob. 44ECh. 12.2 - Prob. 45ECh. 12.2 - Prob. 46ECh. 12.2 - Prob. 47ECh. 12.2 - Prob. 48ECh. 12.2 - Prob. 49ECh. 12.2 - Prob. 50ECh. 12.2 - Prob. 51ECh. 12.2 - Prob. 52ECh. 12 - Prob. 1CRECh. 12 - Prob. 2CRECh. 12 - Prob. 3CRECh. 12 - Prob. 4CRECh. 12 - Prob. 5CRECh. 12 - Prob. 6CRECh. 12 - Prob. 1PTCh. 12 - Prob. 2PTCh. 12 - Prob. 3PTCh. 12 - Prob. 4PTCh. 12 - Prob. 5PTCh. 12 - Prob. 6PTCh. 12 - Prob. 7PTCh. 12 - Prob. 8PTCh. 12 - Prob. 9PTCh. 12 - Prob. 10PTCh. 12 - Prob. 11PTCh. 12 - Prob. 12PTCh. 12 - Prob. 1PT4Ch. 12 - Prob. 2PT4Ch. 12 - Prob. 3PT4Ch. 12 - Prob. 4PT4Ch. 12 - Prob. 5PT4Ch. 12 - Prob. 6PT4Ch. 12 - Prob. 7PT4Ch. 12 - Prob. 8PT4Ch. 12 - Prob. 9PT4Ch. 12 - Prob. 10PT4Ch. 12 - Prob. 11PT4Ch. 12 - Prob. 12PT4Ch. 12 - Prob. 13PT4Ch. 12 - Prob. 14PT4Ch. 12 - Prob. 15PT4Ch. 12 - Prob. 16PT4Ch. 12 - Prob. 17PT4Ch. 12 - Prob. 18PT4Ch. 12 - Prob. 19PT4Ch. 12 - Prob. 20PT4Ch. 12 - Prob. 21PT4Ch. 12 - Prob. 22PT4Ch. 12 - Prob. 23PT4Ch. 12 - Prob. 24PT4Ch. 12 - Prob. 25PT4Ch. 12 - Prob. 26PT4Ch. 12 - Prob. 27PT4Ch. 12 - Prob. 28PT4Ch. 12 - Prob. 29PT4Ch. 12 - Prob. 30PT4Ch. 12 - Prob. 31PT4Ch. 12 - Prob. 32PT4Ch. 12 - Prob. 33PT4Ch. 12 - Prob. 34PT4Ch. 12 - Prob. 35PT4Ch. 12 - Prob. 36PT4Ch. 12 - Prob. 37PT4Ch. 12 - Prob. 38PT4Ch. 12 - Prob. 39PT4Ch. 12 - Prob. 40PT4Ch. 12 - Prob. 41PT4Ch. 12 - Prob. 42PT4Ch. 12 - Prob. 43PT4Ch. 12 - Prob. 44PT4Ch. 12 - Prob. 45PT4Ch. 12 - Prob. 46PT4
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