   Chapter 12.5, Problem 31E ### Mathematical Applications for the ...

11th Edition
Ronald J. Harshbarger + 1 other
ISBN: 9781305108042

#### Solutions

Chapter
Section ### Mathematical Applications for the ...

11th Edition
Ronald J. Harshbarger + 1 other
ISBN: 9781305108042
Textbook Problem

# In Problems 29-36, find the particular solution to each differential equation. 31.   2 y 2   d x = 3 x 2   d y  when  x = 2 ,   y = − 1

To determine

To calculate: The particular solution to the differential equation 2y2dx=3x2dy when x=2,y=1.

Explanation

Given Information:

The provided differential equation is 2y2dx=3x2dy and the values are x=2,y=1.

Formula used:

Solution of the differential equation g(y)dy=f(x)dx is g(y)dy=f(x)dx.

The power of x formula of integration is xndx=xn+1n+1+C, where n1.

Calculation:

Consider the differential equation,

2y2dx=3x2dy

Rearrange the equation as,

2x2dx=3y2dy2x2dx=3y2dy

Integrate both sides to get:

2x2dx=3y2dy2x2

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