Campbell Biology & Modified Mastering Biology /eText ValuePack Access Card Package
1st Edition
ISBN: 9780133857108
Author: Jane B. Reece, Martha R. Taylor, Eric J. Simon, Jean L. Dickey, Kelly A. Hogan
Publisher: PEARSON
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Textbook Question
Chapter 13, Problem 12TYK
Sickle-cell disease is caused by a recessive allele. Roughly one out of every 400 African Americans (0.25%) is afflicted with sickle-cell disease. Use the Hardy-Weinberg equation to calculate the percentage of African Americans who are carriers of the sickle-cell allele. (Hint: q2 = 0.0025 .)
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While studying the frequency of sickle-cell disease ("sickle cell anemia") in a population living in sub-Saharan Africa, you obtain the following data from a sample of n= 100 people (note that I chose a simpler system for identifying the alleles rather than using "Hb S" for sickle cell allele), which is the actual name and what you used in lab). What is the frequency of the sickle cell allele (b) in the sample below from a human population?
Sample Data
BB-60 individuals (No sickle cell disease)
Bb-30 individuals (No sickle cell disease)
bb-10 individuals (Sickle cell disease)
1. 0.25
2. 0.10
3. 0.35
4. 0.60
5. 0.20
Cystic fibrosis is an autosomal recessive disorder that affects 1 in 3 000 newborns with Caucasian background. It causes thick mucus build up in various organs and can cause damages and problems in respiratory and digestive systems.
a) What is the frequency of the cystic fibrosis allele in the Caucasian population? Show all your work and express your answer as a value between 0 and 1 rounded to two decimal places.
b) What percentage of the Caucasian population would be carriers for cystic fibrosis? Show all your work and express your answer rounded to two decimal places.
c)If two individuals are carriers of the cystic fibrosis allele, what is the probability that they would have a girl without cystic fibrosis? Show all your work (including the Punnett square) and express your answer as a value between 0 and 1 rounded to two decimal places.
Using the two equations, p + q = 1 and p2 + 2pq + q2 = 1, answer the following questions.
Maple Syrup Urine Disease (MSUD) is an autosomal recessive condition that causes intellectual and physical disabilities, difficulty feeding, and a sweet maple syrup odor to the urine. In Costa Rica, the incidence of MSUD is calculated as approximately 1 in 8,000 newborns. Calculate the allele frequencies for the normal and disease alleles.
Chapter 13 Solutions
Campbell Biology & Modified Mastering Biology /eText ValuePack Access Card Package
Ch. 13 - Summarize the key points of Darwins theory of...Ch. 13 - Complete this concept map describing potential...Ch. 13 - Which of the following did not influence Darwin as...Ch. 13 - Natural selection is sometimes described as...Ch. 13 - In an area of erratic rainfall, a biologist found...Ch. 13 - If an allele is recessive and lethal in...Ch. 13 - In a population with two alleles, B and b, the...Ch. 13 - Within a few weeks of treatment with the drug 3TC,...Ch. 13 - Prob. 9TYKCh. 13 - Write a paragraph briefly describing the kinds of...
Ch. 13 - In the early 1800s, French naturalist Jean...Ch. 13 - Sickle-cell disease is caused by a recessive...Ch. 13 - It seems logical that natural selection would work...Ch. 13 - SCIENTIFIC THINKING Cetaceans are fully aquatic...Ch. 13 - A population of snails is preyed on by birds that...Ch. 13 - Advocates of scientific creationism and...
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- In a hypothetical population, 16% have sickle-cell anemia. The population is in Hardy-Weinberg equilibrium. ( sickle-cell anemia is recessive) What is the frequency of the allele for sickle-cell anemia? What is the frequency of the allele for normal hemoglobin?arrow_forwardCystic fibrosis in humans is caused by a recessive allele. A man is known to be a carrier of the cystic fibrosis allele. He marries a phenotypically normal woman. In the general population, the incidence of cystic fibrosis at birth is approximately 1 in 1,700. Assume Hardy-Weinberg proportions. What is the probability that the wife is also a carrier? Answer in decimal number only (three decimal places; example: 0.123). What is the probability that their first child will be affected? Answer in decimal number only (three decimal places; example: 0.123).arrow_forwardThe allele for sickle anemia is found at higher frequencies in central Africa than in other parts of the world. What are the advantage and disadvantages?arrow_forward
- A given autosomal locus has three possible alleles (A1, A2, and A3). Assuming that the numbers of individuals with the six possible genotypes are as follows, what would be the frequency of the A1 allele in the population? A1A1 = 30 A1A2 = 27 A2A2 = 12 A1A3 = 17 A2A3 = 10 A3A3 = 4 What would be the frequency of the A3A3 genotype? Assume the population is under Hardy-Weinberg equilibrium. A. 0.182 B. 0.27 C. 0.03 D. 0.317 E. 0.107 F. 0.09arrow_forwardPhenylketonuria (PKU) is an inherited disease caused by a recessive allele. Individuals with PKU have two recessive alleles and have very low levels of an enzyme that is needed to properly break down proteins. If a woman and her husband are both carriers and have three children, what is the probability of each of the following? Show your math. (Hint: You can represent your probabilities as fractions or decimals, but probabilities are always between 0 and 1) a. All three children are of normal phenotype. b. One or more of the three children have the disease. c.All three children have the disease.arrow_forwardCystic fibrosis is an autosomal recessive disease characterized by two copies of a mutated CFTR gene. If one in 100 (hypothetical scenario, not reality) people in the United States have cystic fibrosis, calculate the p and q frequency for the normal allele (p) and the mutated allele (q). Based on those calculations, what percentage of individuals would be expected to be homozygous dominant?arrow_forward
- Tay–Sachs disease is an autosomal recessive disorder. Among Ashkenazi Jews, the frequency of Tay–Sachs disease is 1 in 3600. Assuming the Ashkenazi population is in Hardy-Weinberg equilibrium, what proportion of the population is expected to be carriers (e.g. heterozygous) for the Tay–Sachs allele?arrow_forward8% of XY individuals are color blind in a population. Assume Hardy-Weinberg conditions. Submit your answer as it is. a) What is the percentage of color-blind XX individuals? b) What is the percentage of XX individuals who are carriers? c) If this population has 1000 individuals with 50% of male and 50% of female, how many carriers are present in this population? Submit your answer as it is. Do not round up.arrow_forwardSickle cell anemia is a genetically inherited autosomal recessive trait in which results in a condition that there are not enough healthy red blood cells to carry oxygen throughout the body due to the production of red blood cells that are sickle shaped. The frequency of the sickle cell condition is as high as 10% in Central Africa compared to 0.5% in the United States. Calculate the frequency of the normal and carries of the sickle cell condition.arrow_forward
- Tay-Sachs disease in humans is caused by a recessive allele. The disease is characterized by mental deficiency and blindness, with death occurring by 4 years of age. Among Ashkenazi Jews of central European ancestry, about 1 in 3600 children is born with the disease. Assume Hardy-Weinberg equilibrium and calculate the frequency of the Tay- Sachs allele in this population. Round your answer to the nearest 0.001. Type your answer...arrow_forwardIdentify each of the following as an example of allele, genotype, and/or phenotype frequency: A. Approximately 1 in 2500 people of Northern European descent is born with cystic fibrosis. B. The percentage of carriers of the sickle cell allele in West Africa is approximately 13%. C. The number of new mutations for achondroplasia, a genetic disorder, is approximately 5 × 10–5.arrow_forwardBecause there are three alleles, there are six possible genotypes of blood groups, both the IA and IB alleles are dominant to the i allele. Thus, people with the heterozygous genotype of type AB blood express both alleles codominantly. Select one: True Falsearrow_forward
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