General Chemistry
General Chemistry
7th Edition
ISBN: 9780073402758
Author: Chang, Raymond/ Goldsby
Publisher: McGraw-Hill College
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Chapter 13, Problem 13.108SP
Interpretation Introduction

Interpretation:

Vapor pressure of pure A and B solutions at 84°C have to be calculated.

Concept introduction:

Raoult’s law states that in an ideal mixture of liquid solution, partial pressure of every component is equal to its mole fraction multiplied into vapour pressure of its pure components.

P= χP°

Where,

P- Partial pressure of each component P°-Partial pressure of its pure components χ- Mole fraction of the components 

Expert Solution & Answer
Check Mark

Answer to Problem 13.108SP

Vapor pressure of pure A solution = 1.9×102mmHg

Vapor pressure of pure B solution = 4.0×102mmHg

Record the given data

Vapor pressure of the solution = 331mmHg

Amount of solution A =1.2 moles

Amount of solution B =2.3 moles

Increased vapor pressure of the solution = 347 mmHg

Explanation of Solution

Given data are recorded as shown.

To calculate mole fraction of total solution

χA=1.2mol1.2mol+2.3mol= 0.3429χB=1- 0.3429 = 0.6571Ptotal= PA+PB= χAPA°+ χBPB°

Substituting in Ptotal and the mole fractions,

331mmHg = 0.3429PA°+0.6571PB°

PA°=331mmHg - 0.6571PB°0.3429 = 965.3mmHg -1.916PB° ......(1)

By plugging in the values of mole fraction of solution A and B, mole fraction of total solution has calculated.

To calculate mole fraction of total solution after additional moles of B

General Chemistry, Chapter 13, Problem 13.108SP  χA=1.2mol1.2mol+3.3mol= 0.2667χB=1- 0.2667 = 0.7333Ptotal= PA+PB= χAPA°+ χBPB°

Substituting in Ptotal and the mole fractions,

347 mmHg = 0.2667(965.3 mmHg-1.916PB°) + 0.7333PB°......(2)

By plugging in the values of mole fraction of solution A and mole fraction of solution after addition of solution B, after additional moles of B has calculated.

To calculate vapor pressure of pure solution of A and B

Substituting equation (1) into (2) we get,

347mmHg = 0.2667(965.3mmHg -1.916PB°) + 0.7333PB°

0.2223PB°= 89.55mmHgPB°= 402.8mmHg = 4.0×102mmHg

Substituting the value of

PA°= 965.3mmHg -1.916(402.8mmHg) =193.5mmHg =1.9×102mmHg

By substituting the equation (1) into equation (2), the vapor pressure of pure solution B has calculated and by subtracting this value into PA°, the vapor pressure of pure solution B has calculated.

Conclusion

Vapor pressure of pure solution A was calculated as 1.9×102mmHg.

Vapor pressure of pure solution B was calculated as 4.0×102mmHg.

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Chapter 13 Solutions

General Chemistry

Ch. 13.6 - Prob. 2PECh. 13.6 - Prob. 2RCCh. 13.6 - Prob. 3PECh. 13.6 - Prob. 4PECh. 13.6 - Prob. 3RCCh. 13.6 - Prob. 5PECh. 13.6 - Prob. 4RCCh. 13 - Prob. 13.1QPCh. 13 - Prob. 13.2QPCh. 13 - Prob. 13.3QPCh. 13 - 13.4 As you know, some solution processes are...Ch. 13 - Prob. 13.5QPCh. 13 - Prob. 13.6QPCh. 13 - Prob. 13.7QPCh. 13 - Prob. 13.8QPCh. 13 - 13.9 Arrange these compounds in order of...Ch. 13 - Prob. 13.10QPCh. 13 - Prob. 13.11QPCh. 13 - Prob. 13.12QPCh. 13 - Prob. 13.13QPCh. 13 - 13.14 Calculate the amount of water (in grams)...Ch. 13 - Prob. 13.15QPCh. 13 - Prob. 13.16QPCh. 13 - Prob. 13.17QPCh. 13 - 12.20 For dilute aqueous solutions in which the...Ch. 13 - Prob. 13.19QPCh. 13 - 13.20 The concentrated sulfuric acid we use in the...Ch. 13 - 13.21 Calculate the molarity and the molality of...Ch. 13 - 13.22 The density of an aqueous solution...Ch. 13 - Prob. 13.23QPCh. 13 - Prob. 13.25QPCh. 13 - 13.26 The solubility of KNO3 is 155 g per 100 g of...Ch. 13 - Prob. 13.27QPCh. 13 - Prob. 13.28QPCh. 13 - Prob. 13.29QPCh. 13 - Prob. 13.30QPCh. 13 - Prob. 13.31QPCh. 13 - 13.32 A man bought a goldfish in a pet shop. Upon...Ch. 13 - Prob. 13.33QPCh. 13 - 13.34 A miner working 260 m below sea level opened...Ch. 13 - Prob. 13.35QPCh. 13 - 13.36 The solubility of N2 in blood at 37°C and at...Ch. 13 - Prob. 13.37QPCh. 13 - Prob. 13.38QPCh. 13 - Prob. 13.39QPCh. 13 - 13.40 How is the lowering in vapor pressure...Ch. 13 - Prob. 13.41QPCh. 13 - Prob. 13.42QPCh. 13 - Prob. 13.43QPCh. 13 - Prob. 13.44QPCh. 13 - Prob. 13.45QPCh. 13 - Prob. 13.46QPCh. 13 - Prob. 13.47QPCh. 13 - 13.48 How many grams of sucrose (C12H22O11) must...Ch. 13 - Prob. 13.49QPCh. 13 - 13.50 The vapor pressures of ethanol (C2H5OH) and...Ch. 13 - Prob. 13.51QPCh. 13 - Prob. 13.52QPCh. 13 - 13.53 What are the boiling point and freezing...Ch. 13 - 13.54 An aqueous solution contains the amino acid...Ch. 13 - 13.55 Pheromones are compounds secreted by the...Ch. 13 - 12.58 The elemental analysis of an organic solid...Ch. 13 - Prob. 13.57QPCh. 13 - 13.58 A solution is prepared by condensing 4.00 L...Ch. 13 - Prob. 13.59QPCh. 13 - 13.60 A solution of 2.50 g of a compound of...Ch. 13 - Prob. 13.61QPCh. 13 - 13.62 A solution containing 0.8330 g of a protein...Ch. 13 - Prob. 13.63QPCh. 13 - 13.64 A solution of 6.85 g of a carbohydrate in...Ch. 13 - 13.65 Define ion pairs. What effect does ion-pair...Ch. 13 - Prob. 13.66QPCh. 13 - Prob. 13.67QPCh. 13 - Prob. 13.68QPCh. 13 - Prob. 13.69QPCh. 13 - Prob. 13.70QPCh. 13 - Prob. 13.71QPCh. 13 - 13.72 At 25°C the vapor pressure of pure water is...Ch. 13 - 13.73 Both NaCl and CaCl2 are used to melt ice on...Ch. 13 - Prob. 13.74QPCh. 13 - Prob. 13.75QPCh. 13 - Prob. 13.76QPCh. 13 - Prob. 13.77QPCh. 13 - Prob. 13.78QPCh. 13 - Prob. 13.79QPCh. 13 - Prob. 13.80QPCh. 13 - Prob. 13.81QPCh. 13 - Prob. 13.82QPCh. 13 - Prob. 13.83QPCh. 13 - Prob. 13.84QPCh. 13 - Prob. 13.85QPCh. 13 - Prob. 13.86QPCh. 13 - Prob. 13.87QPCh. 13 - Prob. 13.88QPCh. 13 - Prob. 13.89QPCh. 13 - Prob. 13.90QPCh. 13 - 13.91 Hydrogen peroxide with a concentration of...Ch. 13 - 13.92 Before a carbonated beverage bottle is...Ch. 13 - Prob. 13.93QPCh. 13 - 13.94 Explain each of these statements: (a) The...Ch. 13 - Prob. 13.95QPCh. 13 - Prob. 13.96QPCh. 13 - Prob. 13.97QPCh. 13 - Prob. 13.98QPCh. 13 - Prob. 13.99QPCh. 13 - Prob. 13.100QPCh. 13 - Prob. 13.101QPCh. 13 - Prob. 13.102QPCh. 13 - Prob. 13.103QPCh. 13 - Prob. 13.104QPCh. 13 - Prob. 13.105SPCh. 13 - Prob. 13.106SPCh. 13 - Prob. 13.107SPCh. 13 - Prob. 13.108SPCh. 13 - Prob. 13.109SPCh. 13 - Prob. 13.110SPCh. 13 - 13.111 A student carried out the following...Ch. 13 - Prob. 13.112SPCh. 13 - Prob. 13.113SPCh. 13 - Prob. 13.114SP
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