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Chemistry: An Atoms-Focused Approach
14th Edition
ISBN: 9780393600681
Author: Gilbert
Publisher: W. W. Norton & Company
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Chapter 13 Solutions
Chemistry: An Atoms-Focused Approach
Ch. 13 - Prob. 13.1VPCh. 13 - Prob. 13.2VPCh. 13 - Prob. 13.3VPCh. 13 - Prob. 13.4VPCh. 13 - Prob. 13.5VPCh. 13 - Prob. 13.6VPCh. 13 - Prob. 13.7VPCh. 13 - Prob. 13.8VPCh. 13 - Prob. 13.9VPCh. 13 - Prob. 13.10VP
Ch. 13 - Prob. 13.11VPCh. 13 - Prob. 13.12VPCh. 13 - Prob. 13.13VPCh. 13 - Prob. 13.14VPCh. 13 - Prob. 13.15VPCh. 13 - Prob. 13.16VPCh. 13 - Prob. 13.17QACh. 13 - Prob. 13.18QACh. 13 - Prob. 13.19QACh. 13 - Prob. 13.20QACh. 13 - Prob. 13.21QACh. 13 - Prob. 13.22QACh. 13 - Prob. 13.23QACh. 13 - Prob. 13.24QACh. 13 - Prob. 13.25QACh. 13 - Prob. 13.26QACh. 13 - Prob. 13.27QACh. 13 - Prob. 13.28QACh. 13 - Prob. 13.29QACh. 13 - Prob. 13.30QACh. 13 - Prob. 13.31QACh. 13 - Prob. 13.32QACh. 13 - Prob. 13.33QACh. 13 - Prob. 13.34QACh. 13 - Prob. 13.35QACh. 13 - Prob. 13.36QACh. 13 - Prob. 13.37QACh. 13 - Prob. 13.38QACh. 13 - Prob. 13.39QACh. 13 - Prob. 13.40QACh. 13 - Prob. 13.41QACh. 13 - Prob. 13.42QACh. 13 - Prob. 13.43QACh. 13 - Prob. 13.44QACh. 13 - Prob. 13.45QACh. 13 - Prob. 13.46QACh. 13 - Prob. 13.47QACh. 13 - Prob. 13.48QACh. 13 - Prob. 13.49QACh. 13 - Prob. 13.50QACh. 13 - Prob. 13.51QACh. 13 - Prob. 13.52QACh. 13 - Prob. 13.54QACh. 13 - Prob. 13.55QACh. 13 - Prob. 13.56QACh. 13 - Prob. 13.57QACh. 13 - Prob. 13.58QACh. 13 - Prob. 13.59QACh. 13 - Prob. 13.60QACh. 13 - Prob. 13.61QACh. 13 - Prob. 13.62QACh. 13 - Prob. 13.63QACh. 13 - Prob. 13.64QACh. 13 - Prob. 13.65QACh. 13 - Prob. 13.66QACh. 13 - Prob. 13.67QACh. 13 - Prob. 13.68QACh. 13 - Prob. 13.69QACh. 13 - Prob. 13.70QACh. 13 - Prob. 13.71QACh. 13 - Prob. 13.72QACh. 13 - Prob. 13.73QACh. 13 - Prob. 13.74QACh. 13 - Prob. 13.75QACh. 13 - Prob. 13.76QACh. 13 - Prob. 13.77QACh. 13 - Prob. 13.78QACh. 13 - Prob. 13.79QACh. 13 - Prob. 13.80QACh. 13 - Prob. 13.81QACh. 13 - Prob. 13.82QACh. 13 - Prob. 13.83QACh. 13 - Prob. 13.84QACh. 13 - Prob. 13.85QACh. 13 - Prob. 13.86QACh. 13 - Prob. 13.87QACh. 13 - Prob. 13.88QACh. 13 - Prob. 13.89QACh. 13 - Prob. 13.90QACh. 13 - Prob. 13.91QACh. 13 - Prob. 13.92QACh. 13 - Prob. 13.93QACh. 13 - Prob. 13.94QACh. 13 - Prob. 13.95QACh. 13 - Prob. 13.96QACh. 13 - Prob. 13.97QACh. 13 - Prob. 13.98QACh. 13 - Prob. 13.99QACh. 13 - Prob. 13.100QACh. 13 - Prob. 13.101QACh. 13 - Prob. 13.102QACh. 13 - Prob. 13.103QACh. 13 - Prob. 13.104QACh. 13 - Prob. 13.105QACh. 13 - Prob. 13.106QACh. 13 - Prob. 13.107QACh. 13 - Prob. 13.108QACh. 13 - Prob. 13.109QACh. 13 - Prob. 13.110QACh. 13 - Prob. 13.111QACh. 13 - Prob. 13.112QACh. 13 - Prob. 13.113QACh. 13 - Prob. 13.114QACh. 13 - Prob. 13.115QACh. 13 - Prob. 13.116QACh. 13 - Prob. 13.117QACh. 13 - Prob. 13.118QACh. 13 - Prob. 13.119QACh. 13 - Prob. 13.120QACh. 13 - Prob. 13.121QACh. 13 - Prob. 13.122QACh. 13 - Prob. 13.123QACh. 13 - Prob. 13.124QACh. 13 - Prob. 13.125QACh. 13 - Prob. 13.126QACh. 13 - Prob. 13.127QACh. 13 - Prob. 13.128QACh. 13 - Prob. 13.129QACh. 13 - Prob. 13.130QACh. 13 - Prob. 13.131QACh. 13 - Prob. 13.132QACh. 13 - Prob. 13.133QACh. 13 - Prob. 13.134QACh. 13 - Prob. 13.135QACh. 13 - Prob. 13.136QACh. 13 - Prob. 13.137QACh. 13 - Prob. 13.138QACh. 13 - Prob. 13.139QACh. 13 - Prob. 13.140QACh. 13 - Prob. 13.141QACh. 13 - Prob. 13.142QACh. 13 - Prob. 13.143QA
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- The hydrolysis of the sugar sucrose to the sugars glucose and fructose, C12H22O11+H2OC6H12O6+C6H12O6 follows a first-order rate equation for the disappearance of sucrose: Rate =k[C12H22O11] (The products of the reaction, glucose and fructose, have the same molecular formulas but differ in the arrangement of the atoms in their molecules.) (a) In neutral solution, k=2.11011s1 at 27 C and 8.51011s1 at 37 C. Determine the activation energy, the frequency factor, and the rate constant for this equation at 47 C (assuming the kinetics remain consistent with the Arrhenius equation at this temperature). (b) When a solution of sucrose with an initial concentration of 0.150 M reaches equilibrium, the concentration of sucrose is 1.65107M . How long will it take the solution to reach equilibrium at 27 C in the absence of a catalyst? Because the concentration of sucrose at equilibrium is so low, assume that the reaction is irreversible. (c) Why does assuming that the reaction is irreversible simplify the calculation in pan (b)?arrow_forwardDerive an expression for the half-life of a a third order reaction;b a reaction whose order is =1; c a reaction whose order is 12. In these last two cases, examples are rare but known.arrow_forwardAs with any drug, aspirin (acetylsalicylic acid) must remain in the bloodstream long enough to be effective. Assume that the removal of aspirin from the bloodstream into the urine is a lirst-order reaction, with a half-life of about 3 hours. The instructions on an aspirin bottle say to take 1 or 2 tablets every 4 hours. If a person takes 2 aspirin tablets, how much aspirin remains in the bloodstream when it is time for the second dose? (A standard tablet contains 325 mg of aspirin.)arrow_forward
- Many biochemical reactions are catalyzed by acids. A typical mechanism consistent with the experimental results (in which HA is the acid and X is the reactant) is Step 1: Step 2: Step 3: Derive the rate law from this mechanism. Determine the order of reaction with respect to HA. Determine how doubling the concentration of HA would affect the rate of the reaction.arrow_forwardIf a reaction has the same rate constant, what time does it take for a reactant to decrease by 5 that is, still near the beginning of the reaction process if the kinetics are zeroth-order, first-order, and second-order with respect to that reactant?arrow_forwardWhen enzymes are present at very low concentration, their effect on reaction rate can be described by first-order kinetics. Calculate by what factor the rate of an enzyme-catalyzed reaction changes when the enzyme concentration is changed from 1.5 107 M to 4.5 106 M.arrow_forward
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