Loose-leaf For Operations Management, 1e
Loose-leaf For Operations Management, 1e
17th Edition
ISBN: 9781259148408
Author: Cachon Associate Professor Dr., Gerard; Terwiesch Associate Professor, CHRISTIAN
Publisher: McGraw-Hill Education
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Textbook Question
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Chapter 13, Problem 1PA

Dan McClure owns a thriving independent bookstore in artsy New Hope, Pennsylvania. He must decide how many copies to order of a new book, Power and Self-Destruction, an exposé on a famous politician’s lurid affairs. Interest in the book will be intense at first and then fizzle quickly as attention turns to other celebrities. The book’s retail price is $20, and the wholesale price is $12. The publisher will buy back the retailer’s leftover copies at a full refund, but McClure Books incurs $4 in shipping and handling costs for each book returned to the publisher. Dan believes his demand forecast can be represented by a normal distribution with a mean of 200 and a standard deviation of 80.

  1. a. Dan will consider this book to be a blockbuster for him if it sells more than 400 units. What is the probability that Power and Self-Destruction will be a blockbuster? [LO13-1]
  2. b. Dan considers a book a “dog” if it sells less than 50 percent of his mean forecast. What is the probability this exposé is a “dog”? [LO13-1]
  3. c. What is the probability that demand for this book will be within 20 percent of the mean forecast? [LO13-1]
  4. d. What order quantity maximizes Dan’s expected profit? [LO13-1]
  5. e. If Dan orders the quantity needed to achieve a 95 percent in-stock probability, what is the probability that some customer won’t be able to purchase a copy of the book? [LO13-2]
  6. f. Suppose Dan orders 300 copies of the book. What is Dan’s expected leftover inventory? [LO13-2]
  7. g. Suppose Dan orders 300 copies of the book. What are Dan’s expected sales? [LO13-2]
  8. h. Suppose Dan orders 300 copies of the book. What is Dan’s expected profit? [LO13-2]
  9. i. How many books should Dan order if he wants to achieve a 95 percent in-stock probability? [LO13-3]

a)

Expert Solution
Check Mark
Summary Introduction

To determine: The probability that the book will be a blockbuster.

Explanation of Solution

Given information:

Retail price (RP)             = $20

Wholesale price (WP)         = $12

Shipping and handling cost (SC)     = $4

Mean (M)                 = 200

Standard deviation (SD)         = 80

Target sales (T)             = 400 units

Calculation of Z – value:

Z=T-MSD=400-20080=20080=2.5

Using the Excel =NORMSDIST (2.5) function, the probability value is 0.99379.

Calculation of probability of being a blockbuster:

Probability=1-F=1-0.99379=0.00621

The probability that the book will be a blockbuster is 0.0062.

b)

Expert Solution
Check Mark
Summary Introduction

To determine: The probability that the book will be a dog.

Explanation of Solution

Given information:

Retail price (RP)             = $20

Wholesale price (WP)         = $12

Shipping and handling cost (SC)     = $4

Mean (M)                 = 200

Standard deviation (SD)         = 80

Target sales (T)             = 50% of mean

  = 100 units

Calculation of Z – value:

Z=T-MSD=100-20080=-10080=-1.25

Using the Excel =NORMSDIST (-1.25) function, the probability value is 0.10565.

The probability that the book will be a dog is 0.1057.

c)

Expert Solution
Check Mark
Summary Introduction

To determine: The probability that the demand of the book will be within 20% of the mean forecast.

Explanation of Solution

Given information:

Retail price (RP)             = $20

Wholesale price (WP)         = $12

Shipping and handling cost (SC)     = $4

Mean (M)                 = 200

Standard deviation (SD)         = 80

Expected demand             = within 20% of the mean forecast

Calculation of probability:

The expected demand value is said to be within 20% of the mean forecast. It means, the demand will be 20 % less or 20% more than the mean.

When sales is 20% less:

Z=(M-(M×20100))-MSD=(200-(200×20100))-20080=160-20080=-0.5

When sales is 20% more:

Z=(M+(M×20100))-MSD=(200+(200×20100))-20080=240-20080=0.5

Using the Excel =NORMSDIST (-0.50) function, the probability value is 0.30854.

Using the Excel =NORMSDIST (0.50) function, the probability value is 0.69146.

The two probabilities are subtracted to identify the demand probability as shown below:

Probability=0.69146-0.30854=0.38292

The probability that the demand of the book will be within 20% of the mean forecast is 0.3830.

d)

Expert Solution
Check Mark
Summary Introduction

To determine: The order quantity that maximizes the profit.

Explanation of Solution

Given information:

Retail price (RP)             = $20

Wholesale price (WP)         = $12

Shipping and handling cost (SC)     = $4

Mean (M)                 = 200

Standard deviation (SD)         = 80

Calculation of critical ratio:

Critical ratio=RP-WP(RP-WP)+SC=20-12(20-12)+SC=88+4=812=0.6667

Using the Excel =NORMSINV (0.6667) function, the value of Z using the round up rule is 0.5.

Calculation of order quantity that maximizes the expected profit:

Order quantity=M+(Z×SD)=200+(0.5×80)=200+40=240 units

The order quantity that maximizes the profit is 240 units.

e)

Expert Solution
Check Mark
Summary Introduction

To determine: The probability that some customers won’t be able to purchase a copy of the book.

Explanation of Solution

Given information:

In-stock probability = 95%

Calculation of probability of some customers not able to purchase the book:

The in-stock probability is 95% which means 95% percent of customers are able to purchase the book. Therefore, the probability that the customers will not be able to purchase the book will be:

Probability=100-In-stock probability=100-95%=5%

The probability that some customers won’t be able to purchase a copy of the book is 5%.

f)

Expert Solution
Check Mark
Summary Introduction

To determine: The expected leftover inventory.

Explanation of Solution

Given information:

Retail price (RP)             = $20

Wholesale price (WP)         = $12

Shipping and handling cost (SC)     = $4

Mean (M)                 = 200

Standard deviation (SD)         = 80

Target sales (T)             = 300 units

Calculation of Z – value:

Z=T-MSD=300-20080=10080=1.25

From the standard normal distribution table, using the roundup rule, the value of expected inventory distribution (I) for a Z-value of 1.3 is 1.3455.

Calculation of expected leftover inventory:

Expected leftover inventory=SD×I=80×1.3455=107.64

The expected leftover inventory is 107.64 units.

g)

Expert Solution
Check Mark
Summary Introduction

To determine: The expected sales.

Explanation of Solution

Given information:

Retail price (RP)             = $20

Wholesale price (WP)         = $12

Shipping and handling cost (SC)     = $4

Mean (M)                 = 200

Standard deviation (SD)         = 80

Target sales (T)             = 300 units

Calculation of expected sales:

Expected sales=Target sales-Expected leftover inventory=300-107.64=192.36

The expected sales is 192.36 units.

h)

Expert Solution
Check Mark
Summary Introduction

To determine: The expected profit.

Explanation of Solution

Given information:

Retail price (RP)             = $20

Wholesale price (WP)         = $12

Shipping and handling cost (SC)     = $4

Mean (M)                 = 200

Standard deviation (SD)         = 80

Target sales (T)             = 300 units

Calculation of expected profit:

Expected profit=(RP×Expected sales)+[(RP-WP)×Leftover inventory]-(WP×T)=(20×192.36)+[(20-12)×107.64]-(12×300)=3,847.2+861.12-3,600=$1,108.32

The expected profit is $108.32.

i)

Expert Solution
Check Mark
Summary Introduction

To determine: The number of books that must be ordered to achieve an in-stock probability of 95%.

Explanation of Solution

Given information:

Retail price (RP)             = $20

Wholesale price (WP)         = $12

Shipping and handling cost (SC)     = $4

Mean (M)                 = 200

Standard deviation (SD)         = 80

Target sales (T)             = 300 units

Calculation of order quantity:

The in-stock probability of 95% and the roundup rule corresponds to z- value of 1.70 from the standard distribution table.

Order quantity=M+(Z×SD)=200+(1.7×80)=200+136=336 units

The number of books that must be ordered to achieve an in-stock probability of 95% is $336 books.

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