Physics for Scientists and Engineers with Modern Physics
10th Edition
ISBN: 9781337553292
Author: Raymond A. Serway, John W. Jewett
Publisher: Cengage Learning
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Chapter 13, Problem 20P
To determine
The expression for the work required to move Earth satellite.
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Physics for Scientists and Engineers with Modern Physics
Ch. 13.1 - A planet has two moons of equal mass. Moon 1 is in...Ch. 13.2 - Prob. 13.2QQCh. 13.4 - Prob. 13.3QQCh. 13.6 - Prob. 13.4QQCh. 13 - Prob. 1PCh. 13 - During a solar eclipse, the Moon, the Earth, and...Ch. 13 - Determine the order of magnitude of the...Ch. 13 - Prob. 4PCh. 13 - Review. Miranda, a satellite of Uranus, is shown...Ch. 13 - (a) Compute the vector gravitational field at a...
Ch. 13 - A spacecraft in the shape of a long cylinder has a...Ch. 13 - An artificial satellite circles the Earth in a...Ch. 13 - Prob. 9PCh. 13 - A particle of mass m moves along a straight line...Ch. 13 - Use Keplers third law to determine how many days...Ch. 13 - Prob. 12PCh. 13 - Suppose the Suns gravity were switched off. The...Ch. 13 - (a) Given that the period of the Moons orbit about...Ch. 13 - How much energy is required to move a 1 000-kg...Ch. 13 - An object is released from rest at an altitude h...Ch. 13 - A system consists of three particles, each of mass...Ch. 13 - Prob. 18PCh. 13 - A 500-kg satellite is in a circular orbit at an...Ch. 13 - Prob. 20PCh. 13 - Prob. 21PCh. 13 - Prob. 22PCh. 13 - Ganymede is the largest of Jupiters moons....Ch. 13 - Prob. 24APCh. 13 - Voyager 1 and Voyager 2 surveyed the surface of...Ch. 13 - Prob. 26APCh. 13 - Prob. 27APCh. 13 - Why is the following situation impossible? A...Ch. 13 - Let gM represent the difference in the...Ch. 13 - A sleeping area for a long space voyage consists...Ch. 13 - Prob. 31APCh. 13 - Prob. 32APCh. 13 - Prob. 33APCh. 13 - Two spheres having masses M and 2M and radii R and...Ch. 13 - (a) Show that the rate of change of the free-fall...Ch. 13 - A certain quaternary star system consists of three...Ch. 13 - Studies of the relationship of the Sun to our...Ch. 13 - Review. Two identical hard spheres, each of mass m...Ch. 13 - Prob. 39APCh. 13 - Prob. 40APCh. 13 - Prob. 41APCh. 13 - Prob. 42APCh. 13 - As thermonuclear fusion proceeds in its core, the...Ch. 13 - Two stars of masses M and m, separated by a...Ch. 13 - The Solar and Heliospheric Observatory (SOHO)...
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Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, physics and related others by exploring similar questions and additional content below.Similar questions
- An average-sized asteroid located 5.0107km from Earth with mass 2.01013kg is detected headed directly toward Earth with speed of 2.0km/s . What will its speed be just before it hits our atmosphere? (You may ignore the size of the asteroid.)arrow_forwardShow that the areal velocity for a circular orbit of radius r about a mass M is At=12GMr . Does your expression give the correct value for Earth’s areal vilocity about the Sun?arrow_forwardUsing the technique shown in Satellite Orbits and Energy, show that two masses m1 and m2 in circular orbits about their common center of mass, will have total energy E=K+E=K1+K2Gm1m2r=Gm1m22r . We have shown the kinetic energy of both masses explicitly. (Hint: The masses orbit at radii r1 and r2 , respectively, where r=r1+r2 . Be sure not to confuse the radius needed for centripetal acceleration with that for the gravitational force.)arrow_forward
- Find the escape speed of a projectile from the surface of Jupiter.arrow_forwardFind the speed needed to escape from the solar system starting from the surface of Earth. Assume there are no other bodies involved and do not account for the fact that Earth is moving in its orbit. [Hint: Equation 13.6 does not apply. Use Equation 13.5 and include the potential energy of both Earth and the Sun. Substituting the values for Earth’s mass and radius directly into Equation 13.6, we obtain vesc=2GMR=2(6.67 10 11Nm2/kg2)(5.96 10 24kg)(6.37 106m)=1.12104m/s That is about 11 km/s or 25,000 mph. To escape the Sun, starting from Earth’s orbit, we use R=RES=1.501011m and MSum=1.991030kg . The result is vesc=4.21104m/s or about 42 km/s. We have 12mvesc2GMmR=12m02GMm=0 Solving for the escape velocity,arrow_forwardGiven the perihelion distance, p , and aphelion distance, q , for an elliptical orbit, show that the velocity at perihelion, vp , is given by vp=2GMSun(q+p)qp . (Hint: Use conservation of angular momentum to relate vp and vq , and then substitute into the conservation fo energy equation.)arrow_forward
- Check Your Understanding If we send a probe out of the solar system starting form Earth’s surface, do we only have to escape the Sun?arrow_forwardWhat is the orbital radius of an Earth satellite having a period of 1.00 h? (b) What is unreasonable about this result?arrow_forwardRank the following quantities of energy from largest to the smallest. State if any are equal. (a) the absolute value of the average potential energy of the SunEarth system (b) the average kinetic energy of the Earth in its orbital motion relative to the Sun (c) the absolute value of the total energy of the SunEarth systemarrow_forward
- It was shown that the energy required to lift a satellite into a low Earth orbit (the change in potential energy) is only a small fraction of the kinetic energy needed to keep it in orbit. Is this true for larger orbits? Is there a trend to the ratio of kinetic energy to change in potential energy as the size of the orbit increase?arrow_forwardFind the Hohmann transfer velocities, vEllipseEarth and vEllipseMars ,needed for a trip to Mars. Use Equation 13.7 to find the circular orbital velocities for Earth and Mars. Using Equation 13.4 and the total energy of the ellips (with semi-major asix a), given by E=GmMs2a , find the velocities at Earth (perihelion) and at Mars (aphelion) required to be on the transfer ellipse. The difference, v , at each point is the velocity boost or transfer velocity needed.arrow_forwardTo find the difference in gravitational potential energies, the difference in heights is used. What is used to find the difference in kinetic energies?arrow_forward
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