Shigley's Mechanical Engineering Design (McGraw-Hill Series in Mechanical Engineering)
10th Edition
ISBN: 9780077591670
Author: BUDYNAS
Publisher: MCG
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Chapter 13, Problem 28P
To determine
The speed of the arm.
The direction of rotation of the arm.
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Two mating involute spur gears of 20 pressure angle have a gear ratio of 2. The number of teeth on the pinion is 20 and its speed is 250 r.p.m. The module pitch of teeth is 10 mm. If the addendum on each wheel is such that the path of approach and the path of recess on each side are half the maximum possible length cach, find: i) the addendum for pinion and gear wheel, i) the length of arc of contact, iiithe maximum velocity of sliding during approach and recess. Assume pinion to be driver.
Two mating involute spur gear of 20° pressure angle have a gear ratio of 2. The number of teeth on the pinion is 20 and its speed is 250 r.p.m. The module pitch of the teeth is 12 mm. If the addendum on each wheel is such that the path of approach and the path of recess on each side are half the maximum possible length, find : a. The addendum for pinion and gear wheel; b. The length of the arc of contact; c. The maximum velocity of sliding during approach and recess. Assume pinion to be the driver.
A commercial quadrotor drone for the photography industry uses a propellersystem that uses gears. The 20-tooth spur pinion with a diametrical pitch of8 rotates 2000 rpm and drives a spur gear that rotates the blades. Determinethe theoretical centre distance, the number of teeth on the gear and circularpitch.
Chapter 13 Solutions
Shigley's Mechanical Engineering Design (McGraw-Hill Series in Mechanical Engineering)
Ch. 13 - A 17-tooth spur pinion has a diametral pitch of 8...Ch. 13 - A 15-tooth spur pinion has a module of 3 mm and...Ch. 13 - A spur gearset has a module of 6 mm and a velocity...Ch. 13 - A 21-tooth spur pinion mates with a 28-tooth gear....Ch. 13 - A 20 straight-tooth bevel pinion having 14 teeth...Ch. 13 - A parallel helical gearset uses a 20-tooth pinion...Ch. 13 - A parallel helical gearset consists of a 19-tooth...Ch. 13 - To avoid the problem of interference in a pair of...Ch. 13 - Prob. 9PCh. 13 - Prob. 10P
Ch. 13 - Prob. 11PCh. 13 - Prob. 12PCh. 13 - Prob. 13PCh. 13 - Prob. 14PCh. 13 - A parallel-shaft gearset consists of an 18-tooth...Ch. 13 - The double-reduction helical gearset shown in the...Ch. 13 - Shaft a in the figure rotates at 600 rev/min in...Ch. 13 - The mechanism train shown consists of an...Ch. 13 - The figure shows a gear train consisting of a pair...Ch. 13 - A compound reverted gear trains are to be designed...Ch. 13 - Prob. 21PCh. 13 - Prob. 22PCh. 13 - Prob. 23PCh. 13 - A gearbox is to be designed with a compound...Ch. 13 - The tooth numbers for the automotive differential...Ch. 13 - Prob. 26PCh. 13 - In the reverted planetary train illustrated, find...Ch. 13 - Prob. 28PCh. 13 - Tooth numbers for the gear train shown in the...Ch. 13 - The tooth numbers for the gear train illustrated...Ch. 13 - Shaft a in the figure has a power input of 75 kW...Ch. 13 - The 24T 6-pitch 20 pinion 2 shown in the figure...Ch. 13 - The gears shown in the figure have a module of 12...Ch. 13 - The figure shows a pair of shaft-mounted spur...Ch. 13 - Prob. 35PCh. 13 - Prob. 36PCh. 13 - A speed-reducer gearbox containing a compound...Ch. 13 - For the countershaft in Prob. 3-72, p. 152, assume...Ch. 13 - Prob. 39PCh. 13 - Prob. 40PCh. 13 - Prob. 41PCh. 13 - Prob. 42PCh. 13 - The figure shows a 16T 20 straight bevel pinion...Ch. 13 - The figure shows a 10 diametral pitch 18-tooth 20...Ch. 13 - Prob. 45PCh. 13 - The gears shown in the figure have a normal...Ch. 13 - Prob. 47PCh. 13 - Prob. 48PCh. 13 - Prob. 49PCh. 13 - The figure shows a double-reduction helical...Ch. 13 - A right-hand single-tooth hardened-steel (hardness...Ch. 13 - The hub diameter and projection for the gear of...Ch. 13 - A 2-tooth left-hand worm transmits 34 hp at 600...
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- The figure shows a double-reduction helical gearset. Pinion 2 is the driver, and it receives a torque of 1200 Ibf • in from its shaft in the direction shown. Pinion 2 has a normal diametral pitch of 8 teeth/in, 14 teeth, and a normal pressure angle of 20° and is cut right-handed with a helix angle of 30°. The mating gear 3 on shaft b has 36 teeth. Gear 4, which is the driver for the second pair of gears in the train, has a normal diametral pitch of 3 teeth/in, 15 teeth, and a normal pressure angle of 20° and is cut left-handed with a helix angle of 15°. Mating gear S has 45 teeth. Find the magnitude and direction of the force exerted by the bearings C and D on shaft b if bearing C can take only a radial load while bearing D is mounted to take both radial and thrust loads.arrow_forwardQ5 Determine the output rotational speed, ω2 for the gear train shown in Figure Q5 if ω1 = 200 rpm CW. N1 = 20; N3 = 25, N4 = 70, N5 = 15, N6 = 15, N7 = 35, N8 = 80.arrow_forward8.7 A pair of involute gears with 16° pressure angle and 6 mm module is in mesh. The number of teeth on pinion is 16 and its rotational speed is 240 r.p.m. When the gear ratio is just 1.75, find, in order that the interference is just avoided, (a) the addenda on pinion and gear wheel (b) the length of path of contact, and (d) the maximum velocity of sliding of teeth on either side of the pitch point. (DAV Indore, 1989) (Ans. a, 9.6 mm; a 4.2 mm; 35.41 mm; V = 95.58 cm/s) %3Darrow_forward
- A compound epicyclic gear is shown in Fig. for Q.2. C and D form acompound wheel which rotates freely on shaft G. The planet wheels B andE rotate on pins fixed in arms attached to shaft G. C and F have internalteeth: the others have external teeth with the following numbers: A, 40;B, 30; D, 50; E, 20. If A rotates at 500 rev/min and wheel F is fixed,find the speed of shaft G.arrow_forwardA synchronous belt drive system is used as a speed reducer. The input shaft rotates at 1000 rpm and has a 36-tooth sprocket with a pitch diameter of 3.609 in. The output shaft has a 72-tooth sprocket with a pitch diameter of 7.218 in. the center distance between the two shafts is 15.01 in. Determine the following for the belt drive: a. The velocity ratiob. The angular velocity of the output shaftc. The linear belt speedd. The belt wrap on the input and output sprocketse. The belt perimeter lengthf. Draw the schematic of the belt drive systemarrow_forwardA pair of gears having 40 and 20 teeth respectively are rotating in mesh, the speed of the smaller being 2000 rpm. Determine the velocity of sliding between the gear teeth faces at the point of engagement, at the pitch point and at the point of disengagement if the smaller gear is the driver. Assume that the gear teeth are 20° involute form, addendum length is 5mm and the module is 5mm.Also find the angle through which the pinion turns while any pairs of teeth are in contact.arrow_forward
- A pickup truck is driving at a speed of 100 km/h on a leveled road. This truck has4 wheels of the same diameter of 400 mm and drives at a gear ratio of 5 to 1 ifits gearbox 5th gear is selected. The gear’s teeth are of involute form with amodule of 8 mm, an addendum is double the module, and the pressure angle isequal to 20° .1.1. If the driving shaft of the front wheels of the truck is connected to the output shaftof the gearbox, determine the number of teeth on the pinion to avoid interferenceand the corresponding number of teeth on the gear wheel.arrow_forwardA simple gear train of 30 and 50 teeth for pinion and gear wheel respectively,is used to drive an electric wheelchair at a velocity that is double the maximum velocity of slip. The pinion has an equal addendum as the gear wheel, a module of 3 mm, and a pressure angle of 14.5o. The wheelchair has a maximum velocity of 5 m/s when its pinion rotates at 800 r.p.m. Calculate: 1.1. The magnitude of the velocity of slip of gears in mesh. (2)1.2. The angular speed of the gear wheel in rad/s. (4)1.3. The maximum length of a path of the approach in mm. (2)1.4. The length of a path of a recess in mm. (7)1.5. The addendum of the gears in mm. (7)1.6. The contact ratio.arrow_forwardHello good Afternoon Sir, Permission, i have a question in my homework. The following bellow is question. Please advice. Thank you Regards,Irfan In planning the combined gears of the Ferguson planetary paradox as shown in the figure below.Sun gear hand input with angular speed (w2) = 0 rpm and hand input with angular speed (w.arm) = 400 rpm counterclockwise (ccw)Where is the number of teeth:Sun gear N2 = 100 (external gear)Sun gear N3 = 99 (external gear)Sun gear N4 = 101 (external gear)Planet gear N5 = 20 (external gear)Calculate the angular velocity, for each gear using the tabulation method. The data is in the image belowarrow_forward
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