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Chapter 13, Problem 35AP

(a) Show that the rate of change of the free-fall acceleration with vertical position near the Earth’s surface is

d g d r = 2 G M E R E 3

This rate of change with position is called a gradient.

(b) Assuming h is small in comparison to the radius of the Earth, show that the difference in free-fall acceleration between two points separated by vertical distance h is

| Δ g | = 2 G M E h R E 3

(c) Evaluate this difference for h = 6.00 m, a typical height for a two-story building.

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Chapter 13 Solutions

Bundle: Physics For Scientists And Engineers With Modern Physics, Loose-leaf Version, 10th + Webassign Printed Access Card For Serway/jewett's Physics For Scientists And Engineers, 10th, Single-term

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