Explanation The five-number summary of a set of observations consists of the smallest observation, the first quartile ( Q 1 ) , the median, the third quartile ( Q 3 ) , and the largest observation, which are calculated as shown below: Arrange the data in order from smallest to largest as shown below: 55 , 73 , 75 , 80 , 81 , 85 , 90 , 93 , 93 , 98 The count of observations n = 10 is even. From the data, it is clear that the smallest observation is 55. The first quartile ( Q 1 ) is considered to be the median of the lower half of the data set. The second quartile ( Q 2 ) is considered to be the median of the entire data set. The third quartile ( Q 3 ) is considered to be the median of the upper half of the data set. The first quartile ( Q 1 ) is the median of first five observations, which is calculated as shown below: Consider the left half of the data set: 55 , 73 , 75 , 80 , 81 The first quartile is calculated as shown below: First quartile ( Q 1 ) = ( 5 + 1 2 ) th observation = ( 6 2 ) th observation = 3 rd observation The 3 rd observation in the first five observations of the data set is 75 . Thus, the first quartile is 75 . The second quartile ( Q 2 ) is the median of the entire data set

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Chapter 1.3, Problem 54UYK

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To find: The five-number summary ofthe first-exam scores of 10 students.

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Chapter 1.3, Problem 53UYK

Chapter 1.3, Problem 55UYK

Chapter 1 Solutions

Introduction to the Practice of Statistics: w/CrunchIt/EESEE Access Card

Ch. 1.1 - Prob. 1UYK Ch. 1.1 - Prob. 2UYK Ch. 1.1 - Prob. 3UYK Ch. 1.1 - Prob. 5UYK Ch. 1.1 - Prob. 4UYK Ch. 1.1 - Prob. 6UYK Ch. 1.1 - Prob. 7UYK Ch. 1.1 - Prob. 8E Ch. 1.1 - Prob. 9E Ch. 1.1 - Prob. 10E

Ch. 1.1 - Prob. 11E Ch. 1.1 - Prob. 12E Ch. 1.1 - Prob. 13E Ch. 1.1 - Prob. 14E Ch. 1.1 - Prob. 15E Ch. 1.2 - Prob. 16UYK Ch. 1.2 - Prob. 17UYK Ch. 1.2 - Prob. 18UYK Ch. 1.2 - Prob. 19UYK Ch. 1.2 - Prob. 20UYK Ch. 1.2 - Prob. 21UYK Ch. 1.2 - Prob. 22UYK Ch. 1.2 - Prob. 23UYK Ch. 1.2 - Prob. 24UYK Ch. 1.2 - Prob. 25E Ch. 1.2 - Prob. 26E Ch. 1.2 - Prob. 27E Ch. 1.2 - Prob. 28E Ch. 1.2 - Prob. 29E Ch. 1.2 - Prob. 30E Ch. 1.2 - Prob. 31E Ch. 1.2 - Prob. 32E Ch. 1.2 - Prob. 33E Ch. 1.2 - Prob. 34E Ch. 1.2 - Prob. 35E Ch. 1.2 - Prob. 42E Ch. 1.2 - Prob. 36E Ch. 1.2 - Prob. 43E Ch. 1.2 - Prob. 37E Ch. 1.2 - Prob. 44E Ch. 1.2 - Prob. 38E Ch. 1.2 - Prob. 45E Ch. 1.2 - Prob. 46E Ch. 1.2 - Prob. 39E Ch. 1.2 - Prob. 40E Ch. 1.2 - Prob. 41E Ch. 1.3 - Prob. 47UYK Ch. 1.3 - Prob. 48UYK Ch. 1.3 - Prob. 49UYK Ch. 1.3 - Prob. 50UYK Ch. 1.3 - Prob. 51UYK Ch. 1.3 - Prob. 52UYK Ch. 1.3 - Prob. 53UYK Ch. 1.3 - Prob. 54UYK Ch. 1.3 - Prob. 55UYK Ch. 1.3 - Prob. 56UYK Ch. 1.3 - Prob. 57UYK Ch. 1.3 - Prob. 58UYK Ch. 1.3 - Prob. 59UYK Ch. 1.3 - Prob. 60UYK Ch. 1.3 - Prob. 67E Ch. 1.3 - Prob. 69E Ch. 1.3 - Prob. 61E Ch. 1.3 - Prob. 62E Ch. 1.3 - Prob. 63E Ch. 1.3 - Prob. 64E Ch. 1.3 - Prob. 65E Ch. 1.3 - Prob. 66E Ch. 1.3 - Prob. 74E Ch. 1.3 - Prob. 75E Ch. 1.3 - Prob. 76E Ch. 1.3 - Prob. 71E Ch. 1.3 - Prob. 68E Ch. 1.3 - Prob. 70E Ch. 1.3 - Prob. 77E Ch. 1.3 - Prob. 78E Ch. 1.3 - Prob. 79E Ch. 1.3 - Prob. 80E Ch. 1.3 - Prob. 81E Ch. 1.3 - Prob. 82E Ch. 1.3 - Prob. 83E Ch. 1.3 - Prob. 84E Ch. 1.3 - Prob. 85E Ch. 1.3 - Prob. 86E Ch. 1.3 - Prob. 87E Ch. 1.3 - Prob. 88E Ch. 1.3 - Prob. 89E Ch. 1.3 - Prob. 90E Ch. 1.3 - Prob. 91E Ch. 1.3 - Prob. 92E Ch. 1.3 - Prob. 93E Ch. 1.3 - Prob. 94E Ch. 1.3 - Prob. 95E Ch. 1.3 - Prob. 96E Ch. 1.3 - Prob. 72E Ch. 1.3 - Prob. 97E Ch. 1.3 - Prob. 98E Ch. 1.3 - Prob. 99E Ch. 1.3 - Prob. 100E Ch. 1.3 - Prob. 73E Ch. 1.4 - Prob. 101UYK Ch. 1.4 - Prob. 102UYK Ch. 1.4 - Prob. 103UYK Ch. 1.4 - Prob. 104UYK Ch. 1.4 - Prob. 105UYK Ch. 1.4 - Prob. 106UYK Ch. 1.4 - Prob. 107UYK Ch. 1.4 - Prob. 108UYK Ch. 1.4 - Prob. 109E Ch. 1.4 - Prob. 110E Ch. 1.4 - Prob. 111E Ch. 1.4 - Prob. 112E Ch. 1.4 - Prob. 113E Ch. 1.4 - Prob. 114E Ch. 1.4 - Prob. 115E Ch. 1.4 - Prob. 116E Ch. 1.4 - Prob. 117E Ch. 1.4 - Prob. 118E Ch. 1.4 - Prob. 119E Ch. 1.4 - Prob. 120E Ch. 1.4 - Prob. 121E Ch. 1.4 - Prob. 122E Ch. 1.4 - Prob. 123E Ch. 1.4 - Prob. 124E Ch. 1.4 - Prob. 125E Ch. 1.4 - Prob. 126E Ch. 1.4 - Prob. 127E Ch. 1.4 - Prob. 128E Ch. 1.4 - Prob. 129E Ch. 1.4 - Prob. 130E Ch. 1.4 - Prob. 131E Ch. 1.4 - Prob. 132E Ch. 1.4 - Prob. 133E Ch. 1.4 - Prob. 134E Ch. 1.4 - Prob. 135E Ch. 1.4 - Prob. 136E Ch. 1.4 - Prob. 137E Ch. 1.4 - Prob. 138E Ch. 1.4 - Prob. 139E Ch. 1.4 - Prob. 140E Ch. 1.4 - Prob. 141E Ch. 1.4 - Prob. 142E Ch. 1.4 - Prob. 143E Ch. 1.4 - Prob. 144E Ch. 1.4 - Prob. 145E Ch. 1.4 - Prob. 146E Ch. 1.4 - Prob. 147E Ch. 1.4 - Prob. 148E Ch. 1.4 - Prob. 149E Ch. 1.4 - Prob. 150E Ch. 1.4 - Prob. 151E Ch. 1.4 - Prob. 152E Ch. 1.4 - Prob. 153E Ch. 1.4 - Prob. 154E Ch. 1.4 - Prob. 155E Ch. 1 - Prob. 156E Ch. 1 - Prob. 157E Ch. 1 - Prob. 158E Ch. 1 - Prob. 159E Ch. 1 - Prob. 160E Ch. 1 - Prob. 161E Ch. 1 - Prob. 162E Ch. 1 - Prob. 163E Ch. 1 - Prob. 164E Ch. 1 - Prob. 165E Ch. 1 - Prob. 166E Ch. 1 - Prob. 167E Ch. 1 - Prob. 168E Ch. 1 - Prob. 169E Ch. 1 - Prob. 170E Ch. 1 - Prob. 171E Ch. 1 - Prob. 172E Ch. 1 - Prob. 173E Ch. 1 - Prob. 174E Ch. 1 - Prob. 175E Ch. 1 - Prob. 176E Ch. 1 - Prob. 177E

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The five-number summary ofthe first-exam scores of 10 students.

Solution Summary: The author explains that the five-number summary of first-exam scores of 10 students is as follows: the smallest observation is 55, the first quartile (Q_1)

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To find: The five-number summary ofthe first-exam scores of 10 students.

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Chapter 1 Solutions