(a)
Interpretation:
Calculate the value of equilibrium constant for dissolution of AgBr which is a sparingly soluble solute with the help of given
Concept introduction:
Sparingly soluble salts form their respective ions in their solutions. The dissolution process is just opposite to the precipitation reaction. The standard free energy change can be calculated with the help of Gibb’s energy for the reactant and products. The mathematical expression of Gibb’s energy can be written as:
Here:
- R = 8.314 J / mol .K
- T = temperature in Kelvin
(b)
Interpretation:
Calculate the value of equilibrium constant for dissolution of
Concept introduction:
Sparingly soluble salts form their respective ions in their solutions. The dissolution process is just opposite to the precipitation reaction. The standard free energy change can be calculated with the help of Gibb’s energy for the reactant and products. The mathematical expression of Gibb’s energy can be written as:
Here:
- R = 8.314 J / mol .K
- T = temperature in Kelvin
(c)
Interpretation:
Calculate the value of equilibrium constant for dissolution of
Concept introduction:
Sparingly soluble salts form their respective ions in their solutions. The dissolution process is just opposite to the precipitation reaction. The standard free energy change can be calculated with the help of Gibb’s energy for the reactant and products. The mathematical expression of Gibb’s energy can be written as:
Here:
- R = 8.314 J / mol .K
- T = temperature in Kelvin
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EP GENERAL CHEMISTRY-MOD.MASTERINGCHEM.
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