Concept explainers
(a)
The fault in the provided statement.
(a)
Answer to Problem 5E
Solution: The fault in the statement is that the null hypothesis cannot be rejected in a two-way ANOVA when the AB F-statistic is small value.
Explanation of Solution
(b)
The fault in the provided statement.
(b)
Answer to Problem 5E
Solution: The fault in the statement is that the sum of squares is not similar to mean squares divided by the degrees of freedom.
Explanation of Solution
The correct statement is the mean of squares is similar to sum of squares divided by the degrees of freedom. Hence, the hypothesis can be considered as a wrong statement.
(c)
The fault in the provided statement.
(c)
Answer to Problem 5E
Solution: The fault in the statement is that when the null hypothesis is true in a two-way ANOVA, the test statistics for the main effects does not follow chi-square distribution.
Explanation of Solution
(d)
The fault in the provided statement.
(d)
Answer to Problem 5E
Solution: The provided statement is wrong because the sums of squares add up if there is equal number of observations in two-way ANOVA.
Explanation of Solution
If the number of observation are not equal, sum of square may not partitioned as above. Hence, the hypothesis can be considered as a wrong statement.
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Chapter 13 Solutions
Introduction to the Practice of Statistics
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