ETEXT CAMPBELL BIOLOGY IN FOCUS INSTANT
3rd Edition
ISBN: 9780135964422
Author: Urry
Publisher: PEARSON
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Chapter 13, Problem 6TYU
Summary Introduction
Introduction:
The restriction enzymes cut the sequences of the DNA, which are palindromic repeat sequences. The enzymes cut the DNA, according to the specificity of the sequence.
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The double stranded DNA sequence of a restriction enzyme cut site is typically complementary, antiparallel, and palindromic. Given these criteria, which one of the following single stranded sequences represents a restriction enzyme cut site when made double stranded?
a.
None of these sequences satisfy the given criteria
b.
5' – GTCCTG – 3'
c.
5' – GTCGTC – 3'
d.
5' – GTCGAC – 3'
e.
5' – GGTTCC – 3'
Choose the combination of answers that most accurately completes the statement.Which of the following sequences, when combined with its complement, would be clipped by a restriction endonuclease? a. ATCGATCGTAGCTA c. GAATTC b. AAGCTTCGAA d. ACCATTGGA
If a restriction endonuclease recognizes and cleaves a linear piece of DNA and Circular DNA at 8 distinet places, how many pieces will result?
OA Nine and Eight fragments respectively
B.
Both gerierate nine fragments
C.
Ten and nine fragments respectively
Both generate eight fragments
Chapter 13 Solutions
ETEXT CAMPBELL BIOLOGY IN FOCUS INSTANT
Ch. 13.1 - Given a polynucleotide sequence such as GAATTC,...Ch. 13.1 - Prob. 2CCCh. 13.2 - What role does base pairing play in the...Ch. 13.2 - Make a table listing the functions of seven...Ch. 13.2 - MAKE CONNECTIONS What is the relationship between...Ch. 13.3 - Describe the structure of a nucleosome, the basic...Ch. 13.3 - What two properties, one structural and one...Ch. 13.4 - Prob. 1CCCh. 13.4 - DRAW IT One strand of a DNA molecule has the...Ch. 13.4 - Describe the role of complementary base pairing...
Ch. 13 - In his work with pneumonia-causing bacteria and...Ch. 13 - Prob. 2TYUCh. 13 - In analyzing the number of different bases in a...Ch. 13 - The elongation of the leading strand during DNA...Ch. 13 - Prob. 5TYUCh. 13 - Prob. 6TYUCh. 13 - Prob. 7TYUCh. 13 - Prob. 8TYUCh. 13 - Prob. 9TYUCh. 13 - MAKE CONNECTIONS Although the proteins that cause...Ch. 13 - Prob. 11TYUCh. 13 - FOCUS ON EVOLUTION Some bacteria may be able to...Ch. 13 - FOCUS ON ORGANIZATION The continuity of life is...Ch. 13 - Prob. 14TYU
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- HindIII is a restriction endonuclease that recognizes a palindrome sequence. Predict which one is the HindIII recognition site: a. AAGGTT b. AAGCTT c. AGCCGA d. AGCGCA e. AGCAGCarrow_forwardFeatures of restriction enzymes include the following, except __________ . a. They are produced by both prokaryotes and eukaryotesb. may be type IIc. make single and double stranded breaks in DNAd. operate at a single temperaturee. Are used in nature to destroy bacteriophage DNAarrow_forwardWhich of the following is a sequence most likely to be recognized by restriction enzymes? a. 5' GATTAATC 3' - double-strand form b. 5' ATG 3' - double-strand form c. 5' AUGCGCAU 3' - double-strand form d. NH3-met-trp-val- COOH e. none of the abovearrow_forward
- What is the enzymatic function of restriction enzymes? Group of answer choices a. to cut nucleic acids at specific sites b. to join nucleotides during transcription c. to add new nucleotides to the growing strand of DNA d. to repair breaks in sugar - phosphate backbonesarrow_forwardA new restriction enzyme is discovered. It recognizes a 6 base pair pallindromic sequence. The first three bases of the target sequence are are given below with the cut identified by ^. Answer the following questions: Target sequence: 5' G^TA _ _ _ 3'3' _ _ _ _ _ _ 5' 1) Complete the target sequence with all missing bases. Also include the position of the cut in the lower sequence(^) 2) What kind of clevage does the enzyme use?arrow_forwardWhat is used to cut the DNA in panels 1 and 2? a. Restriction enzymes b. DNA polymerases c. DNA ligases d. RNA polymerases e. Reverse transcriptasearrow_forward
- The other options are: a. RNA cannot be digested by restriction enzymes b. RNA is small enough to be resolved on an agarose gel without the need for restriction digestion. c. RNA is single stranded and DNA is double strandedarrow_forwardSome bacteria, through natural selection, have acquired some extremely potent enzymes that destroy viral DNA, thereby preventing the bacterial cell from becoming infected with the virus. These enzymes are called: Select one: O a. DNA polymerases O b. DNA ligases c. restriction endonucleases O d. restriction ligasesarrow_forwardUse the set of gene sequencing results below to answer the question that follows: A G C T -Wells I 14. Based on the sequencing results above, what is the sequence of nucleotides as they were added by DNA polymerase to the DNA template? a/ATC-GCA-GTA b. TAG-TGC-CAT c. TAC-TGC-GAT GC-GA TAG-CGT-CAT L A EI la la اد ان YIarrow_forward
- If the following is a restriction enzyme: Sma I, A. What is the first letter represent? B. What do the next two letters represent? C. What does the roman numeral represent?arrow_forwardYou isolated a 10,500 base pair plasmid (supercoiled, cccDNA) from E. coli. The plasmid contains one unique recognition site for EcoRI, a restriction enzyme. Restriction enzymes recognize a specific sequence and cut both strands of the DNA at that sequence (Chapter 7). Brief DNase I treatment breaks one (or very few) phosphodiesterbonds in each DNA molecule, leaving the double-stranded DNA with one strand broken but the other strand intact, i.e “nicked.” You briefly incubated the cccDNA at 37°C in four separate reactions containing the components listed below. You ran each reaction sample on an agarose gel and visualized the DNA using ethidium bromide and UV light. The reactions included the appropriate buffer and ATP when required. An agarose gel containing four lanes of possible products is given below. Please refer to Figs. 4-26 and 4-27 in Watson for reference. For each reaction, indicate which lane of the gel contains the products that you would expect to see on your…arrow_forwardIn E.coli, the following enzymes do NOT synthesize the RNA primer for Okazaki fragments? A.DnaA B. DnaC C.DnaG D.None of the abovearrow_forward
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