Interpretation:
The solubility of argon at pressure 15 atm have to be calculated.
Concept introduction:
Solubility: Solubility can be expressed as maximum amount of solute that can dissolve in a known amount of solvent at a given temperature and pressure.
Henry’s Law: The solubility of a gas in liquid varies proportional to the pressure of the gas which is above the liquid at a given temperature.
Answer to Problem 114A
The solubility of argon at pressure 15 atmis 82.5 mg/100 gm water.
Explanation of Solution
The expression of Henry’s Law is
The solubility of argon is S1 at P1 pressure and S2 at pressure P2.
From the graph we got, S1 = 55 mg/100 gm water, P1=10 atmand P2 = 15 atm
So, the solubility of argon at pressure 15 atm is 82.5 mg/100 gm water.
Chapter 14 Solutions
Glencoe Chemistry: Matter and Change, Student Edition
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