General, Organic, & Biological Chemistry
General, Organic, & Biological Chemistry
3rd Edition
ISBN: 9780073511245
Author: Janice Gorzynski Smith Dr.
Publisher: McGraw-Hill Education
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Chapter 14, Problem 14.29P
Interpretation Introduction

(a)

Interpretation:

The following alcohol should be classified as primary, secondary and tertiary alcohol:

  General, Organic, & Biological Chemistry, Chapter 14, Problem 14.29P , additional homework tip  1

Concept Introduction:

Organic compounds are the compounds that are mainly composed of C and H atoms. The branch of chemistry that deals with the preparation, reactions, and properties of organic compounds are said to be organic chemistry. The molecular formula of the organic compound represents the number of bonded atoms with their atomic symbols. The structural formula represents all the bonded atoms with chemical bonds and the arrangement of atoms in the molecule.

Expert Solution
Check Mark

Answer to Problem 14.29P

Propanol is a primary alcohol.

Explanation of Solution

Alcohols are the organic compounds with the general formula R-OH. Here, the −OH group (hydroxyl group) is directly bonded to the carbon atom of the parent chain. On the basis of the carbon atom to which the −OH group is bonded, alcohols can be classified as primary, secondary and tertiary alcohols.

  • Primary alcohol = The −OH group must be bonded to the primary carbon atom (bonded with one other C atom).
  • Secondary alcohol = The −OH group must be bonded to the secondary carbon atom (bonded with two other C atoms).
  • Tertiary alcohol = The −OH group must be bonded to a tertiary carbon atom (bonded with three other C atoms).

In the given alcohol, the −OH group is bonded to a primary C atom which is bonded with one other C atom hence, it should be primary alcohol.

  General, Organic, & Biological Chemistry, Chapter 14, Problem 14.29P , additional homework tip  2

Interpretation Introduction

(b)

Interpretation:

The following alcohol should be classified as primary, secondary and tertiary alcohol:

  General, Organic, & Biological Chemistry, Chapter 14, Problem 14.29P , additional homework tip  3

Concept Introduction:

Organic compounds are the compounds that are mainly composed of C and H atoms. The branch of chemistry that deals with the preparation, reactions, and properties of organic compounds are said to be organic chemistry. The molecular formula of the organic compound represents the number of bonded atoms with their atomic symbols. The structural formula represents all the bonded atoms with chemical bonds and the arrangement of atoms in the molecule.

Expert Solution
Check Mark

Answer to Problem 14.29P

3-ethyl-3-pentanol is a tertiary alcohol.

Explanation of Solution

Alcohols are the organic compounds with the general formula R-OH. Here the −OH group (hydroxyl group) is directly bonded to the carbon atom of the parent chain. On the basis of the carbon atom to which the −OH group is bonded, alcohols can be classified as primary, secondary and tertiary alcohols.

  • Primary alcohol = The −OH group must be bonded to the primary carbon atom (bonded with one other C atom).
  • Secondary alcohol = The −OH group must be bonded to the secondary carbon atom (bonded with two other C atoms).
  • Tertiary alcohol = The −OH group must be bonded to a tertiary carbon atom (bonded with three other C atoms).

In the given alcohol, the −OH group is bonded to a tertiary C atom which is bonded with 3 other C atoms hence, it should be tertiary alcohol.

  General, Organic, & Biological Chemistry, Chapter 14, Problem 14.29P , additional homework tip  4

Interpretation Introduction

(c)

Interpretation:

The following alcohol should be classified as primary, secondary and tertiary alcohol:

  General, Organic, & Biological Chemistry, Chapter 14, Problem 14.29P , additional homework tip  5

Concept Introduction:

Organic compounds are the compounds that are mainly composed of C and H atoms. The branch of chemistry that deals with the preparation, reactions, and properties of organic compounds are said to be organic chemistry. The molecular formula of the organic compound represents the number of bonded atoms with their atomic symbols. The structural formula represents all the bonded atoms with chemical bonds and the arrangement of atoms in the molecule.

Expert Solution
Check Mark

Answer to Problem 14.29P

2,2-dimethylcyclohexanol is a secondary alcohol.

Explanation of Solution

Alcohols are the organic compounds with the general formula R-OH. Here the −OH group (hydroxyl group) is directly bonded to the carbon atom of the parent chain. On the basis of the carbon atom to which the −OH group is bonded, alcohols can be classified as primary, secondary and tertiary alcohols.

  • Primary alcohol = The −OH group must be bonded to the primary carbon atom (bonded with one other C atom).
  • Secondary alcohol = The −OH group must be bonded to the secondary carbon atom (bonded with two other C atoms).
  • Tertiary alcohol = The −OH group must be bonded to a tertiary carbon atom (bonded with three other C atoms).

In the given alcohol, the −OH group is bonded to a secondary C atom which is bonded with two other C atoms hence, it should be secondary alcohol.

  General, Organic, & Biological Chemistry, Chapter 14, Problem 14.29P , additional homework tip  6

Interpretation Introduction

(d)

Interpretation:

The following alcohol should be classified as primary, secondary and tertiary alcohol:

  General, Organic, & Biological Chemistry, Chapter 14, Problem 14.29P , additional homework tip  7

Concept Introduction:

Organic compounds are the compounds that are mainly composed of C and H atoms. The branch of chemistry that deals with the preparation, reactions, and properties of organic compounds are said to be organic chemistry. The molecular formula of the organic compound represents the number of bonded atoms with their atomic symbols. The structural formula represents all the bonded atoms with chemical bonds and the arrangement of atoms in the molecule.

Expert Solution
Check Mark

Answer to Problem 14.29P

3-methyl-2-pentanol is a secondary alcohol.

Explanation of Solution

Alcohols are the organic compounds with the general formula R-OH. Here the −OH group (hydroxyl group) is directly bonded to the carbon atom of the parent chain. On the basis of the carbon atom to which the −OH group is bonded, alcohols can be classified as primary, secondary and tertiary alcohols.

  • Primary alcohol = The −OH group must be bonded to the primary carbon atom (bonded with one other C atom).
  • Secondary alcohol = The −OH group must be bonded to the secondary carbon atom (bonded with two other C atoms).
  • Tertiary alcohol = The −OH group must be bonded to a tertiary carbon atom (bonded with three other C atoms).

In the given alcohol, the −OH group bonds to a secondary C atom which is bonded with two other C atoms hence it should be secondary alcohol.

  General, Organic, & Biological Chemistry, Chapter 14, Problem 14.29P , additional homework tip  8

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Chapter 14 Solutions

General, Organic, & Biological Chemistry

Ch. 14.5 - Prob. 14.11PCh. 14.6 - Prob. 14.12PCh. 14.6 - Prob. 14.13PCh. 14.7 - Prob. 14.14PCh. 14.7 - Prob. 14.15PCh. 14.7 - Prob. 14.16PCh. 14.7 - Prob. 14.17PCh. 14.8 - (a) Translate the hall and stick model of...Ch. 14.8 - Prob. 14.19PCh. 14.9 - Prob. 14.20PCh. 14.9 - Prob. 14.21PCh. 14.9 - Prob. 14.22PCh. 14.9 - Prob. 14.23PCh. 14.9 - Prob. 14.24PCh. 14.9 - Prob. 14.25PCh. 14.10 - Prob. 14.26PCh. 14.10 - Prob. 14.27PCh. 14.10 - Prob. 14.28PCh. 14 - Prob. 14.29PCh. 14 - Prob. 14.30PCh. 14 - Prob. 14.31PCh. 14 - Classify each halide hi A as 1°, 2°, or 3°. A is a...Ch. 14 - Prob. 14.33PCh. 14 - Draw the structure of a molecule that fits each...Ch. 14 - Draw the structure of the six constitutional...Ch. 14 - Draw the structure of the four constitutional...Ch. 14 - Prob. 14.37PCh. 14 - Prob. 14.38PCh. 14 - Prob. 14.39PCh. 14 - Answer each question about alcohol B. Draw a...Ch. 14 - Prob. 14.41PCh. 14 - Give the IUAPC name for each alcohol.Ch. 14 - Prob. 14.43PCh. 14 - Prob. 14.44PCh. 14 - Prob. 14.45PCh. 14 - Prob. 14.46PCh. 14 - Draw the structures and give the IUPAC names for...Ch. 14 - Prob. 14.48PCh. 14 - Prob. 14.49PCh. 14 - Prob. 14.50PCh. 14 - Give the structure corresponding to each IUPAC...Ch. 14 - Give the structure corresponding to each IUPAC...Ch. 14 - Which compound in each pair has the higher boiling...Ch. 14 - Rank the compounds in order of increasing melting...Ch. 14 - Rank the following compounds in order of...Ch. 14 - Rank the following compounds in order of...Ch. 14 - Prob. 14.57PCh. 14 - Prob. 14.58PCh. 14 - Prob. 14.59PCh. 14 - Prob. 14.60PCh. 14 - Prob. 14.61PCh. 14 - Prob. 14.62PCh. 14 - Prob. 14.63PCh. 14 - Prob. 14.64PCh. 14 - Prob. 14.65PCh. 14 - Prob. 14.66PCh. 14 - Prob. 14.67PCh. 14 - Prob. 14.68PCh. 14 - Prob. 14.69PCh. 14 - Prob. 14.70PCh. 14 - Prob. 14.71PCh. 14 - Prob. 14.72PCh. 14 - Prob. 14.73PCh. 14 - Prob. 14.74PCh. 14 - Prob. 14.75PCh. 14 - Prob. 14.76PCh. 14 - Prob. 14.77PCh. 14 - Prob. 14.78PCh. 14 - Prob. 14.79PCh. 14 - Prob. 14.80PCh. 14 - Prob. 14.81PCh. 14 - Prob. 14.82PCh. 14 - Prob. 14.83PCh. 14 - Prob. 14.84PCh. 14 - Prob. 14.85PCh. 14 - Prob. 14.86PCh. 14 - With reference to the halogenated organic...Ch. 14 - Prob. 14.88PCh. 14 - Prob. 14.89PCh. 14 - Prob. 14.90PCh. 14 - Write out the chemical reaction that occurs when a...Ch. 14 - Prob. 14.92PCh. 14 - Prob. 14.93PCh. 14 - Lactic acid [CH3CH(OH)CO2H] gives sour milk its...Ch. 14 - Prob. 14.95PCh. 14 - Prob. 14.96PCh. 14 - Prob. 14.97PCh. 14 - Prob. 14.98PCh. 14 - Prob. 14.99PCh. 14 - Answer the following questions about alcohol B....Ch. 14 - Prob. 14.101CPCh. 14 - Dehydration of alcohol C forms two products of...
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