Chapter 14, Problem 14.4P

(a)

Interpretation Introduction

Interpretation:

Oxidizing and reducing agent and balanced half-reaction for below reaction have to be determined.

  ${\text{2S}}_2{\text{O}}_4^{2-}\left(s\right)+{\text{TeO}}_3^{2-}+2{\text{OH}}^{-}\rightleftharpoons {\text{4SO}}_3^{2-}+\text{Te}\left(s\right)+{\text{H}}_2\text{O}$

Concept Introduction:

Oxidation refers to phenomenon of loss of electrons, loss of electropositive $\text{H}$ and gain of electronegative $\text{O}$. Substance that gets oxidized is termed as reducing agent.

Reduction is process that involves gain of electrons, gain of $\text{H}$ or loss of electronegative $\text{O}$ atom. Substance that gets reduced is termed as oxidizing agent.

Interpretation Introduction

Interpretation:

Coulomb of charge that passes from reductant to oxidant has to be determined.

  ${\text{2S}}_2{\text{O}}_4^{2-}\left(s\right)+{\text{TeO}}_3^{2-}+2{\text{OH}}^{-}\rightleftharpoons {\text{4SO}}_3^{2-}+\text{Te}\left(s\right)+{\text{H}}_2\text{O}$

Concept Introduction:

Electric charge is defined as physical property of matter due to that it experiences a force when placed in electric field and it is denoted by $q$. On other hand, electric current is defined as flow of electric charge. Electric charge is carried by ions and electrolytes. It is denoted by $I$.

Interpretation Introduction

Interpretation:

Amount of current that flows has to be determined.

Concept Introduction:

Refer to part (b).