Chapter 14, Problem 16PT

To determine

To calculate: The simplified form of the polynomial $-8y^3\left(2y-6\right)$ .

Answer to Problem 16PT

The simplified form of the polynomial $-8y^3\left(2y-6\right)$ is $-16y^4+48y^3$ .

Explanation of Solution

Given Information:

The polynomialexpression is $-8y^3\left(2y-6\right)$ .

Calculation:

The given polynomial is $-8y^3\left(2y-6\right)$ .

Now, find the simplified form of the polynomial $-8y^3\left(2y-6\right)$ .

  $\begin{array}{c}-8y^3\left(2y-6\right)=-8y^3\times 2y+8y^3\times 6\\ =-16y^4+48y^3\end{array}$

Hence, the simplified form of the polynomial $-8y^3\left(2y-6\right)$ is $-16y^4+48y^3$ .