Concept explainers
a)
To find probability that car neither will need repair.
a)
Answer to Problem 21E
The probability that car neither will need repair is 0.5184
Explanation of Solution
Given:
P(Once repair) = 17% = 0.17
P(Twice repair) = 7% = 0.07
P(Thrice or more) = 4% = 0.04
P(No repairs) = 0.72
P(Some repairs) = 0.28
Formula:
Multiplication rule:
Hence, probability that car neither will need repair is 51.84%
b)
To find probability that both will need repair.
b)
Answer to Problem 21E
The probability that both will need repair is 0.0784
Explanation of Solution
Given:
P(Once repair) = 17% = 0.17
P(Twice repair) = 7% = 0.07
P(Thrice or more) = 4% = 0.04
P(No repairs) = 0.72
P(Some repairs) = 0.28
Formula:
Multiplication rule:
Hence, probability that both will need repair is 7.84%
c)
To find probability that at least one repair.
c)
Answer to Problem 21E
The probability that at least one repair is 0.4816
Explanation of Solution
Given:
P(Once repair) = 17% = 0.17
P(Twice repair) = 7% = 0.07
P(Thrice or more) = 4% = 0.04
P(No repairs) = 0.72
P(Some repairs) = 0.28
P(Neither need repairs) = 0.5184
Formula:
Complement rule:
Hence, probability that at least one repair is 48.16%
Chapter 14 Solutions
Stats: Modeling the World Nasta Edition Grades 9-12
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