a)
To explain the approach.
a)
Answer to Problem 23E
Probability of independent
Explanation of Solution
Given:
P(Once repair) = 17% = 0.17
P(Twice repair) = 7% = 0.07
P(Thrice or more) = 4% = 0.04
P(No repairs) = 0.72
P(Some repairs) = 0.28
To make the valid approach we need to assume that repairs has to be independent for the two cars.
b)
To explain whether the assumption of independence is reasonable.
b)
Answer to Problem 23E
No.
Explanation of Solution
Given:
P(Once repair) = 17% = 0.17
P(Twice repair) = 7% = 0.07
P(Thrice or more) = 4% = 0.04
P(No repairs) = 0.72
P(Some repairs) = 0.28
To make the valid approach we need to assume that repairs has to be independent for the two cars.This assumption is likely not reasonable if a owner has more than car, then the probability of needing repairs on each of his car will not be independent. Therefore, it is also possible that two cars come in the shop as a consequence of a collision with each other, then the probability of them both needing repairs is also higher.
Chapter 14 Solutions
Stats: Modeling the World Nasta Edition Grades 9-12
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Essentials of Statistics (6th Edition)
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