Chapter 14.8, Problem 7ST2

To determine

To fill the blank.

Answer to Problem 7ST2

The translation of T , $T^{-}\cdot T:P\to \underset{\_}{P}$

Explanation of Solution

Given information: The translation of T , $T^{-}\cdot T:P\to \underset{\_}{}$

The mapping that maps every point to itself is called identity translation, hence the translation of T followed by $T^{-}$ keeps all point fixed.

Therefore,

The translation of T, $T^{-}\cdot T:P\to \underset{\_}{P}$