Organic Chemistry - With Access (Looseleaf) (Custom)
Organic Chemistry - With Access (Looseleaf) (Custom)
4th Edition
ISBN: 9781259726224
Author: SMITH
Publisher: MCG
Question
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Chapter 15, Problem 15.41P
Interpretation Introduction

(a)

Interpretation: The products for radical chlorination and bromination of given compound are to be drawn. The compounds which form single constitutional isomer for both reactions are to be predicted. The true structure of a reactant for both reactions to form a single product is to be identified.

Concept introduction: Chlorination and bromination are radical substitution reaction. In the reaction of chlorination, Cl replaces hydrogen atom and forms alkyl halide in the presence of light. Similarly, in the bromination, an alkyl halide is formed by the replacement of hydrogen atom from highly substituted carbon by Br. Bromination is highly specific reaction than chlorination. Constitutional isomers have same molecular formula but they differ in the connectivity of substituents.

Expert Solution
Check Mark

Answer to Problem 15.41P

The products of radical chlorination and bromination of given compound are,

Organic Chemistry - With Access (Looseleaf) (Custom), Chapter 15, Problem 15.41P , additional homework tip  1

A single constitutional isomer is formed for both reactions.

Explanation of Solution

Alkanes undergo chlorination when they are treated with Cl2 in the presence of light. Chlorination can take place at primary, secondary and tertiary carbon atom. The product formed by the chlorination of given compound is shown in Figure 1.

Organic Chemistry - With Access (Looseleaf) (Custom), Chapter 15, Problem 15.41P , additional homework tip  2

Figure 1

Alkanes undergo bromination through free radical mechanism when they are treated with Br2 in the presence of light. Bromination can take place at primary, secondary and tertiary carbon atom. The product formed by the bromination of given compound is shown in Figure 2.

Organic Chemistry - With Access (Looseleaf) (Custom), Chapter 15, Problem 15.41P , additional homework tip  3

Figure 2

A single constitutional isomer is formed for both reaction because all hydrogen atoms of given compound are present in a same chemical environment. Therefore, to form a single product, the chemical environment of hydrogen atoms should be same.

Conclusion

The products of radical chlorination and bromination of given compound are shown in Figure 1 and Figure 2, respectively. A single constitutional isomer is formed for both reactions.

Interpretation Introduction

(b)

Interpretation: The products for radical chlorination and bromination of given compound are to be drawn. The compounds which form single constitutional isomer for both reactions are to be predicted. The true structure of a reactant for both reactions to form a single product is to be identified.

Concept introduction: Chlorination and bromination are radical substitution reaction. In the reaction of chlorination, Cl replaces hydrogen atom and forms alkyl halide in the presence of light. Similarly, in the bromination, an alkyl halide is formed by the replacement of hydrogen atom from highly substituted carbon by Br. Bromination is highly specific reaction than chlorination. Constitutional isomers have same molecular formula but they differ in the connectivity of substituents.

Expert Solution
Check Mark

Answer to Problem 15.41P

The products of radical chlorination and bromination of given compound are,

Organic Chemistry - With Access (Looseleaf) (Custom), Chapter 15, Problem 15.41P , additional homework tip  4

A single constitutional isomer is not formed for both reactions.

Explanation of Solution

Alkanes undergo chlorination when they are treated with Cl2 in the presence of light. Chlorination can take place at primary, secondary and tertiary carbon atom. The products formed by the chlorination of given compound are shown in Figure 3.

Organic Chemistry - With Access (Looseleaf) (Custom), Chapter 15, Problem 15.41P , additional homework tip  5

Figure 3

Alkanes undergo bromination by free radical mechanism when they are treated with Br2 in the presence of light. Bromination can take place at primary, secondary and tertiary carbon atom. However, the bromination is more selective than chlorination. Hence, tertiary product is more favorable than secondary or primary. The product formed by the bromination of given compound is shown in Figure 4.

Organic Chemistry - With Access (Looseleaf) (Custom), Chapter 15, Problem 15.41P , additional homework tip  6

Figure 4

A single constitutional isomer is formed for bromination reaction but not for chlorination because bromine is more selective than chlorine.

Conclusion

The products of radical chlorination and bromination of given compound are shown in Figure 3 and Figure 4, respectively. A single constitutional isomer is not formed for both reactions.

Interpretation Introduction

(c)

Interpretation: The products for radical chlorination and bromination of given compound are to be drawn. The compounds which form single constitutional isomer for both reactions are to be predicted. The true structure of a reactant for both reactions to form a single product is to be identified.

Concept introduction: Chlorination and bromination are radical substitution reaction. In the reaction of chlorination, Cl replaces hydrogen atom and forms alkyl halide in the presence of light. Similarly, in the bromination, an alkyl halide is formed by the replacement of hydrogen atom from highly substituted carbon by Br. Bromination is highly specific reaction than chlorination. Constitutional isomers have same molecular formula but they differ in the connectivity of substituents.

Expert Solution
Check Mark

Answer to Problem 15.41P

The products of radical chlorination and bromination of given compound are,

Organic Chemistry - With Access (Looseleaf) (Custom), Chapter 15, Problem 15.41P , additional homework tip  7

A single constitutional isomer is formed for both reactions.

Explanation of Solution

Alkanes undergo chlorination when they are treated with Cl2 in the presence of light. Chlorination can take place at primary, secondary and tertiary carbon atom. The product formed by the chlorination of given compound is shown in Figure 2.

Organic Chemistry - With Access (Looseleaf) (Custom), Chapter 15, Problem 15.41P , additional homework tip  8

Figure 5

Alkanes undergo bromination when they are treated with Br2 in the presence of light. Bromination can take place at primary, secondary and tertiary carbon atom. The product formed by the bromination of given compound is shown in Figure 6.

Organic Chemistry - With Access (Looseleaf) (Custom), Chapter 15, Problem 15.41P , additional homework tip  9

Figure 6

A single constitutional isomer is formed for both reaction because all hydrogen atoms of given compound are present in same chemical environment. Therefore, to form a single product, the chemical environment of hydrogen atoms should be same.

Conclusion

The products of radical chlorination and bromination of given compound are shown in Figure 5 and Figure 6, respectively. A single constitutional isomer is formed for both reactions.

Interpretation Introduction

(d)

Interpretation: The products for radical chlorination and bromination of given compound are to be drawn. The compounds which form single constitutional isomer for both reactions are to be predicted. The true structure of a reactant for both reactions to form a single product is to be identified.

Concept introduction: Chlorination and bromination are radical substitution reaction. In the reaction of chlorination, Cl replaces hydrogen atom and forms alkyl halide in the presence of light. Similarly, in the bromination, an alkyl halide is formed by the replacement of hydrogen atom from highly substituted carbon by Br. Bromination is highly specific reaction than chlorination. Constitutional isomers have same molecular formula but they differ in the connectivity of substituents.

Expert Solution
Check Mark

Answer to Problem 15.41P

The products of radical chlorination and bromination of given compound are,

Organic Chemistry - With Access (Looseleaf) (Custom), Chapter 15, Problem 15.41P , additional homework tip  10

A single constitutional isomer is formed for both reactions.

Explanation of Solution

Alkanes undergo chlorination when they are treated with Cl2 in the presence of light. Chlorination can take place at primary, secondary and tertiary carbon atom. The product formed by the chlorination of given compound is shown in Figure 7.

Organic Chemistry - With Access (Looseleaf) (Custom), Chapter 15, Problem 15.41P , additional homework tip  11

Figure 7

Alkanes undergo bromination when they are treated with Br2 in the presence of light. Bromination can take place at primary, secondary and tertiary carbon atom. The product formed by the bromination of given compound is shown in Figure 8.

Organic Chemistry - With Access (Looseleaf) (Custom), Chapter 15, Problem 15.41P , additional homework tip  12

Figure 8

A single constitutional isomer is formed for both reaction because all hydrogen atoms of given compound are present in same chemical environment. Therefore, to form a single product, the chemical environment of hydrogen atoms should be same.

Conclusion

The products of radical chlorination and bromination of given compound are shown in Figure 7 and Figure 8, respectively. A single constitutional isomer is formed for both reactions.

Interpretation Introduction

(e)

Interpretation: The products for radical chlorination and bromination of given compound are to be drawn. The compounds which form single constitutional isomer for both reactions are to be predicted. The true structure of a reactant for both reactions to form a single product is to be identified.

Concept introduction: Chlorination and bromination are radical substitution reaction. In the reaction of chlorination, Cl replaces hydrogen atom and forms alkyl halide in the presence of light. Similarly, in the bromination, an alkyl halide is formed by the replacement of hydrogen atom from highly substituted carbon by Br. Bromination is highly specific reaction than chlorination. Constitutional isomers have same molecular formula but they differ in the connectivity of substituents.

Expert Solution
Check Mark

Answer to Problem 15.41P

The products of radical chlorination and bromination of given compound are,

Organic Chemistry - With Access (Looseleaf) (Custom), Chapter 15, Problem 15.41P , additional homework tip  13

A single constitutional isomer is not formed for both reactions.

Explanation of Solution

Alkanes undergo chlorination when they are treated with Cl2 in the presence of light. Chlorination can take place at primary, secondary and tertiary carbon atom. The product formed by the chlorination of given compound is shown in Figure 9.

Organic Chemistry - With Access (Looseleaf) (Custom), Chapter 15, Problem 15.41P , additional homework tip  14

Figure 9

Alkanes undergo bromination by free radical mechanism when they are treated with Br2 in the presence of light. Bromination can take place at primary, secondary and tertiary carbon atom. However, the bromination is more selective than chlorination. Hence, tertiary product is more favorable than secondary or primary. The product formed by the bromination of given compound is shown in Figure 10.

Organic Chemistry - With Access (Looseleaf) (Custom), Chapter 15, Problem 15.41P , additional homework tip  15

Figure 10

A single constitutional isomer is formed for bromination reaction but not for chlorination because bromine is more selective than chlorine.

Conclusion

The products of radical chlorination and bromination of given compound are shown in Figure 9 and Figure 10, respectively. A single constitutional isomer is not formed for both reactions.

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Chapter 15 Solutions

Organic Chemistry - With Access (Looseleaf) (Custom)

Ch. 15 - Prob. 15.11PCh. 15 - Synthesize each compound from (CH3)3CH. a....Ch. 15 - Prob. 15.13PCh. 15 - Prob. 15.14PCh. 15 - Prob. 15.15PCh. 15 - Prob. 15.16PCh. 15 - Prob. 15.17PCh. 15 - Prob. 15.18PCh. 15 - Draw all constitutional isomers formed when each...Ch. 15 - Draw the structure of the four allylic halides...Ch. 15 - Which compounds can be prepared in good yield by...Ch. 15 - Which CH bond is most readily cleaved in linolenic...Ch. 15 - Prob. 15.23PCh. 15 - Draw the products formed when each alkene is...Ch. 15 - Problem 15.24 When adds to under radical...Ch. 15 - Prob. 15.26PCh. 15 - Draw an energy diagram for the two propagation...Ch. 15 - Prob. 15.28PCh. 15 - Problem 15.27 Draw the steps of the mechanism that...Ch. 15 - Prob. 15.30PCh. 15 - Prob. 15.31PCh. 15 - Prob. 15.32PCh. 15 - Prob. 15.33PCh. 15 - Why is a benzylic CH bond labeled in red unusually...Ch. 15 - Prob. 15.35PCh. 15 - Prob. 15.36PCh. 15 - Prob. 15.37PCh. 15 - Prob. 15.38PCh. 15 - What alkane is needed to make each alkyl halide by...Ch. 15 - Which alkyl halides can be prepared in good yield...Ch. 15 - Prob. 15.41PCh. 15 - 15.40 Explain why radical bromination of p-xylene...Ch. 15 - a. What product(s) (excluding stereoisomers) are...Ch. 15 - Prob. 15.44PCh. 15 - Prob. 15.45PCh. 15 - Prob. 15.46PCh. 15 - 15.44 Draw all constitutional isomers formed when...Ch. 15 - Draw the organic products formed in each reaction....Ch. 15 - Prob. 15.49PCh. 15 - 15.47 Treatment of a hydrocarbon A (molecular...Ch. 15 - Prob. 15.51PCh. 15 - Prob. 15.52PCh. 15 - Prob. 15.53PCh. 15 - Prob. 15.54PCh. 15 - 15.53 Consider the following bromination: . a....Ch. 15 - 15.54 Draw a stepwise mechanism for the following...Ch. 15 - Prob. 15.57PCh. 15 - An alternative mechanism for the propagation steps...Ch. 15 - Prob. 15.59PCh. 15 - Prob. 15.60PCh. 15 - Devise a synthesis of each compound from...Ch. 15 - Devise a synthesis of each target compound from...Ch. 15 - Devisea synthesis of each target compound from the...Ch. 15 - Devise a synthesis of each compound using CH3CH3...Ch. 15 - Prob. 15.65PCh. 15 - 15.63 As described in Section 9.16, the...Ch. 15 - 15.64 Ethers are oxidized with to form...Ch. 15 - Prob. 15.68PCh. 15 - Prob. 15.69PCh. 15 - 15.67 In cells, vitamin C exists largely as its...Ch. 15 - What monomer is needed to form each...Ch. 15 - Prob. 15.72PCh. 15 - Prob. 15.73PCh. 15 - 15.71 Draw a stepwise mechanism for the following...Ch. 15 - 15.72 As we will learn in Chapter 30, styrene...Ch. 15 - Prob. 15.76PCh. 15 - 15.74 A and B, isomers of molecular formula , are...Ch. 15 - Prob. 15.78PCh. 15 - Radical chlorination of CH3CH3 forms two minor...Ch. 15 - 15.76 Draw a stepwise mechanism for the...Ch. 15 - Prob. 15.81PCh. 15 - Prob. 15.82PCh. 15 - Prob. 15.83P
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