Traffic and Highway Engineering - With Mindtap
5th Edition
ISBN: 9781305360990
Author: Garber
Publisher: CENGAGE L
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Chapter 15, Problem 15P
To determine
The point of tangent and the deflection angles from PC to full stationsfor lying out of curve in the circular curve connecting two tangents.
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Given a circular curve connecting 2 tangents that intersect at an angle of 48 degrees. The PI is at station (948+67.32) and the design speed of the highway is 60 mi/h. Determine the point of the tangent and the deflection angles from the PC to full stations for laying out the curve.
Given a circular curve connecting 2 tangents that intersect at an angle of 48°. The PI is at station (948+67.32) and the design speed of the highway is 60 mi/h. Determine the point of the tangent and the deflection angles from the PC to full stations for laying out the curve.
an arterial road is to be connected to a frontage road by a reverse curve with parallel tangents. the distance between the centerline of the two roads is 60 ft. if the pc of the curve is located at station (38 25.31) and the deflection angle is 25°, determine the station of pt.
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- The design speed for a two-lane highway (lane width=12 ft.) is 60 mph. The localjurisdiction governs 8% superelevation. The central angel of the curve is 40 degrees. The PI station is at 452+50.What is the curve radius to the travel path (R)? What is the curve radius (R)? What is the curve length (L)? What isthe station of PC? What is the station of PT? What is the SSD? How many feet must be cleared from the lane'sshoulder edge to provide adequate stopping sight distance?arrow_forwardA horizontal curve is designed with a 2000-ft radius. The curve has a tangent length of 400 ft and the PI is at station 103+00. Determine the stationing of the PC, PT, deflection angle (A/2), and chord length for each station between the PC and PT.arrow_forward3.48 A horizontal curve is being designed for a new two-lane highway (12-ft lanes). The PI is at station 250 + 50, the design speed is 65 mi/h, and a maximum superelevation of 0.07 ft/ft is to be used. If the central angle of the curve is 38 degrees, design a curve for the highway by computing the radius and stationing of the PC and PT. 3.49 You are nalarrow_forward
- 6. The intersection angle of a 4.775º curve is 48 degrees. The Point of Curve is at station (943+33.05). Determine the radius and length of the curve, and the deflection angles and the chord lengths from the Point of Curve to full stations for laying out the curve.arrow_forwardA 3.5˚ curve is to be designed on a highway with a design speed of 60 mi/h. Spiral transition curves are to be used. Determine the length of the spiral and the appropriate stations for the T.S., S.C., and S.T. The angle of deflection for the original tangents is 40˚, and the P.I. is at station 15,100+26. The segment consists of two 12-ft lanes.arrow_forward2. A simple curve has a central angle of 36° and a degree of curve of 6°: a. Find the nearest distance from the midpoint of the curve to the point of intersection of the tangents. b. Compute the distance from the midpoint of the curve to the midpoint of the long chord joining the P.C. and P.T. c. If the stationing of P.C. is at 10 + 020, compute the stationing of a point on the curve which intersects with the line making a deflection angle of 10° with the tangent through P.C.arrow_forward
- The intersection angle of a 6.716° curve is 80°41mintes 41.9 seconds and the radius is 260m, and the PC is located at station 4+90. 679 . Determine the length of the curve, the station of the PT, the deflection angles and the chord lengths for setting out the curve at whole stations from the PC.arrow_forwardA horizontal curve is being designed for a new two-lane highway (3.6-m lanes). The PI is at station 7 + 640, the design speed is 105 km/h, and a maximum superelevation of 0.08 m/m is to be used. If the central angle of the curve is 35 degrees, design a curve for the highway by computing the radius and stationing of the PC and PT.arrow_forwardA reverse curve connects two converging tangents intersecting at an angle of 32". The direction of the second tangent is due east. The distance of this intersection from the PI of the second curve is 130 m. The deflection angle of the common tangent from the back tangent is 19° (R). The degree of curve of the second curve is 8° and the stationing of the P.C. is 10+ 128.40 m. Determine the following: *Radius of the first and second curve *Length and bearing of the common tangent *Stationing of the P.R.C. and the P.T. *If a 15-meter width of road right way from the P.C. to the P.T. will be negotiated, compute the considered road areaarrow_forward
- Two horizontal tangents meet at station 132+11.00 with a deflection angle of 55 degrees and 18 minutes. The horizontal curve between the two tangents has a radius of 2000 ft. Sketch the curve and Calculate: A) Degree of Curve B) External Distance C) Middle Ordinate D) Tangent distance E) length of curve F) begin and end stationsarrow_forwardA horizontal curve with spiral curves on either sides is to be designed along a highway. The deflection angle (A) for the road will be 70°, while the spiral length and spiral angle are designed to be 1300 ft and 18°, respectively. (round off the numbers to 2 decimal places) a) Find the radius for the circular curve. b) If the Station for Plc is chosen to be 100+0.00 ft, find the Stations for ST.arrow_forwardIt is required to layout a simple curve by deflection angles. The curve is to connect two tangents with an intersection angle of 32° and a radius of 240 m. Compute the deflection angles to each 20 m full stations on the curve. If the transit is set up at the P.C. which is at station 5+767.2. What is the stationing of the P.T.?arrow_forward
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