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Concept explainers
To analyze:
Referring to the locations of domains in the glucocorticoidreceptor relative to the amino- and carboxyl-terminal ends of the protein, make a drawing illustrating the binding of aglucocorticoid receptor dimer to the DNA. Label the amino and carboxyl ends, the hormone-binding domains, theDNA-binding domains, the dimerization domains, and the transactivationdomains.
Introduction:
In the function of glucocorticoid receptor, smaller domains like transactivation domain, DNA binding domain, and hormone binding domain play specific functional roles. For example, the carboxy terminal portion contains a domain that functions as a glucocorticoid binding site. The locations of domains in the glucocorticoid receptor relative to the amino and carboxyl terminal ends of the protein can be used to draw a hypothetical diagram of a glucocorticoid receptor dimer bound to the DNA.
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Chapter 15 Solutions
Genetics: Analysis and Principles
- [ Choose ] [Choose ) in vitro mutagenesis CRISPR-Cas9 system SNP (single nucleotide polymorphism) RNA interference (RNAI) >arrow_forwardQuestion: A decapeptide composed of ser, ala, IIe. his, trp, phe was treated with 1-flouro- 2,4-dinitrobenzene. It gave a DNP-his on the N terminal and free trp when treated with carboxypeptidase. Upon partial hydrolysis of the peptide, the following fragments were obtained. a. his-lle-phe-ala c. his-ala-phe e. ser-lle-his b. ala-phe-trp d. phe-ala-ser Give the amino acid sequence of the above decapeptide.arrow_forwardQuestion 2 Match the term and its description. Each term can only be used once. a series of nonoverlapping, three-nucleotide words [Choose J This DNA strand provides a template for ordering the sequence of complementary nucleotides in an RNA transcript | Choose ) the MRNA base triplets [ Choose J Codons must be read in the correct groupings in order for the specified polypeptide to be produced. These correct groupings are [ Choose J called > > > >arrow_forward
- Question 4: Explain how a deletion mutation leading to a modification of the 3' untranslated region (UTR) on the CACNA1S mRNA could lead to hypokalemic periodic paralysis without changing the structure of the polypeptide formed? (Note this is not the known cause of hypoKPP, but it makes a good question)arrow_forwardQuestion 7 Review translation. Match the term and its description. Each term can only be used once. transfer amino acids to the growing polypeptide in a ribosome |Choose | these base-pairs of a ERNA with a complementary codon on MRNA [ Choose J The two ribosomal subunits (large and small) are made of proteins | Choose | and this RNA called >arrow_forwardQuestion Choose forward and reverse primers to amplify gene X 5'ATTAGTCATGCCAACTTGCACTGATATGA...geneX...CCAGGCGCTAACCTAGATCGCTAGTATCG3' Forward primer: A. 5'-AGTCACGTTCAACCGTACTG-3' B. 5'-GTCATGCCAACTTGCACTGA-3' C. 5'-TCAGTGCAAGTTGGCATGAC-3' D. 5'-CAGTACGGTTGAACGTGACT-3' E. other? Reverse primer: A. 5'-TGATCGCTAGATCCAATCGC-3' B. 5'-CGCTAACCTAGATCGCTAGT-3' C. 5'-ACTAGCGATCTAGGTTAGCG-3' D. 5'-GCGATTGGATCTAGCGATCA-3' E. other? * Sequences above are 20mers with 50%GC.arrow_forward
- QUESTION 8 Consider the pathway for the synthesis of the amino acid arginine in Neurospora: ARG-E → citrulline ARG-F ARG-H ornithine argininosuccinate arginine Mutant strains of Neurospora may carry one or more mutations. Neurospora mutant strain b is grown on minimal media plus supplements as shown. Growth is shown by (+) and no growth is shown by (o). Supplements ornithine mutant nothing citrulline arginino- succinate arginine strain What can you conclude from these data? O Strain a has only one mutation and it is in ARG-E. O Strain b has only one mutation and it is in ARG-H. O Strain a has a mutation in ARG-F and strain b has a mutation in ARG-E. O Strain b has mutations in ARG-E, ARG-F, and ARG-H. + +arrow_forwardQuestion 4: Imagine that you isolated X-receptor proteins from mutant cells with the nonsense mutation in exon 3. You also isolate X-receptor proteins from wild-type (normal) cells. If you ran these protein molecules on a gel which are your predicted results? A В C Ladder Wild-type Mutant Ladder Wild-type Mutant Ladder Wild-type Mutantarrow_forwardQuestion 1. Suppose that the diagram below represents the genomic organization of an enzyme involved in eye pigment production in mice. Within the gene are four exons. Biochemical analysis has revealed that the active site of the enzyme is located in the C terminus of the protein. The nucleotide length of each exon and intron is shown. The dinucleotide sequence GT represents the 5’ splice site and the dinucleotide sequence AG represents the 3’ splice site. Both the 5’ and the 3’ splice sites must be present for splicing to occur. Assume that the first and second stop codons are located immediately after the first and second 5’ splice sites, respectively; the third and fourth stop codons are located near the 3’ end of exons 3 and 4, respectively; all these stop codons are in the correct reading frame. E) Suppose you isolate a mutant mouse that has white eyes. When you examine the size of the eye pigment enzyme produced by this mouse, you see that it is 400 amino acids long. Sequence…arrow_forward
- Question 8. How is the green fluorescent protein (GFP) attached to the protein for which it serves as a label allowing that protein's dynamic activities to be tracked? A. The GFP itself is attached directly to the coding region of the gene of the protein being studied. B. A recombinant RNA is produced by attaching the GFP mRNA to the mRNA of the desired protein. C. GFP adheres specifically to the desired protein via weak interactions. D. The coding region of the GFP gene is joined to the coding region of the gene that encodes the protein being studied.arrow_forwardQuestion 2. From mouse nerve cells you isolate the mouse Tau-gene-containing DNA fragment and hybridize it to the mRNA encoding Tau from the cytoplasm of the same cells. Describe what you see when you look at the molecules under the electron microscope. A. A double-stranded DNA-RNA hybrid with complete overlap of all the sequences. B. A partially double stranded DNA-RNA hybrid molecule containing regions of DNA-RNA overlap representing the mRNA exons, loops where there are introns and tails at the 5' and 3' ends. C. A partially double-stranded molecule containing regions of DNA-RNA overlap representing the mRNA introns, loops where there are introns and tails at the 5' and 3' ends. D. Regions of DNA-RNA overlap representing the mRNA exons and loops where there are introns with no tails at the 5' or 3' ends. E. Two distinct molecules with no overlapping regions. Multiple Choicearrow_forwardQuestion 5A You are doing a genetic engineering experiment. You use restrictions enzymes to cut the regulatory sequences from the lac operon and replace them with the regulatory sequences of the trp operon. Specifically, you will eliminate everything upstream of the beginning of lacZ and replace them with the trp sequences upstream of the beginning of trpE, including trpR. Now, describe the regulation of your ñew constructed gene. What will you do to get expression of the three lac genes? The lac Operon and its Control Elements lacl CAP PO lacz lacY lacA genes 5 binding site 3 DNA AUG AUG AUG messenger RNA RNA polymerase blocked from transcribing trp operon Regulatory gene trp operon DNA PR trpR Ptrp trpE trpD trpC trpB trpA Repressor bound to operator Promoter 5' 3' trpR-MRNA (a) Tryptophan present, repressor bound to operator, operon ropressed. When complexed with tryptophan, the repressor protein produced by the trpR gene binds tightly to the trp operator, thereby preventing RNA…arrow_forward
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